{"id":88935,"date":"2025-06-01T07:25:08","date_gmt":"2025-06-01T07:25:08","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=88935"},"modified":"2025-06-01T07:25:08","modified_gmt":"2025-06-01T07:25:08","slug":"consider-the-following-reaction-2hgo-%e2%8e%af%e2%8e%af%e2%86%92-2hg-o%e2%82%82the-respective-sta","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-reaction-2hgo-%e2%8e%af%e2%8e%af%e2%86%92-2hg-o%e2%82%82the-respective-sta\/","title":{"rendered":"Consider the following reaction :\n2HgO \u23af\u23af\u2192 2Hg + O\u2082\nThe respective sta"},"content":{"rendered":"<p>Consider the following reaction :<br \/>\n2HgO \u23af\u23af\u2192 2Hg + O\u2082<br \/>\nThe respective state of HgO, Hg and O\u2082 in the above reaction is<\/p>\n<p>[amp_mcq option1=&#8221;Liquid, solid, gas&#8221; option2=&#8221;Solid, solid, gas&#8221; option3=&#8221;Liquid, solid, liquid&#8221; option4=&#8221;Solid, liquid, gas&#8221; correct=&#8221;option4&#8243;]<\/p>\n<div class=\"psc-box-pyq-exam-year-detail\">\n<div class=\"pyq-exam\">\n<div class=\"psc-heading\">This question was previously asked in<\/div>\n<div class=\"psc-title line-ellipsis\">UPSC NDA-2 &#8211; 2023<\/div>\n<\/div>\n<div class=\"pyq-exam-psc-buttons\"><a href=\"\/pyq\/pyq-upsc-nda-2-2023.pdf\" target=\"_blank\" class=\"psc-pdf-button\" rel=\"noopener\">Download PDF<\/a><a href=\"\/pyq-upsc-nda-2-2023\" target=\"_blank\" class=\"psc-attempt-button\" rel=\"noopener\">Attempt Online<\/a><\/div>\n<\/div>\n<section id=\"pyq-correct-answer\">Mercuric oxide (HgO) is a solid compound at room temperature. Mercury (Hg) is the only metal that exists as a liquid at room temperature. Oxygen (O\u2082) is a gas at room temperature. Therefore, the respective states of HgO, Hg, and O\u2082 are solid, liquid, and gas.<\/section>\n<section id=\"pyq-key-points\">The physical states of substances at standard temperature and pressure (or implied conditions) are important in chemical reactions. Mercury is unique among metals in being liquid at room temperature.<\/section>\n<section id=\"pyq-additional-information\">This reaction represents the thermal decomposition of mercuric oxide. Heating HgO breaks it down into its constituent elements, mercury and oxygen. The states indicated correspond to the stable forms of these substances under normal conditions after the reaction.<\/section>\n","protected":false},"excerpt":{"rendered":"<p>Consider the following reaction : 2HgO \u23af\u23af\u2192 2Hg + O\u2082 The respective state of HgO, Hg and O\u2082 in the above reaction is [amp_mcq option1=&#8221;Liquid, solid, gas&#8221; option2=&#8221;Solid, solid, gas&#8221; option3=&#8221;Liquid, solid, liquid&#8221; option4=&#8221;Solid, liquid, gas&#8221; correct=&#8221;option4&#8243;] This question was previously asked in UPSC NDA-2 &#8211; 2023 Download PDFAttempt Online Mercuric oxide (HgO) is a &#8230; <\/p>\n<p class=\"read-more-container\"><a title=\"Consider the following reaction :\n2HgO \u23af\u23af\u2192 2Hg + O\u2082\nThe respective sta\" class=\"read-more button\" href=\"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-reaction-2hgo-%e2%8e%af%e2%8e%af%e2%86%92-2hg-o%e2%82%82the-respective-sta\/#more-88935\">Detailed Solution<span class=\"screen-reader-text\">Consider the following reaction :<br \/>\n2HgO \u23af\u23af\u2192 2Hg + O\u2082<br \/>\nThe respective sta<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1094],"tags":[1105,1096,1155],"class_list":["post-88935","post","type-post","status-publish","format-standard","hentry","category-upsc-nda-2","tag-1105","tag-chemistry","tag-physical-and-chemical-changes-solution","no-featured-image-padding"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Consider the following reaction : 2HgO \u23af\u23af\u2192 2Hg + O\u2082 The respective sta<\/title>\n<meta name=\"description\" content=\"Mercuric oxide (HgO) is a solid compound at room temperature. Mercury (Hg) is the only metal that exists as a liquid at room temperature. Oxygen (O\u2082) is a gas at room temperature. Therefore, the respective states of HgO, Hg, and O\u2082 are solid, liquid, and gas. The physical states of substances at standard temperature and pressure (or implied conditions) are important in chemical reactions. Mercury is unique among metals in being liquid at room temperature.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-reaction-2hgo-\u23af\u23af\u2192-2hg-o\u2082the-respective-sta\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Consider the following reaction : 2HgO \u23af\u23af\u2192 2Hg + O\u2082 The respective sta\" \/>\n<meta property=\"og:description\" content=\"Mercuric oxide (HgO) is a solid compound at room temperature. Mercury (Hg) is the only metal that exists as a liquid at room temperature. Oxygen (O\u2082) is a gas at room temperature. Therefore, the respective states of HgO, Hg, and O\u2082 are solid, liquid, and gas. The physical states of substances at standard temperature and pressure (or implied conditions) are important in chemical reactions. Mercury is unique among metals in being liquid at room temperature.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-reaction-2hgo-\u23af\u23af\u2192-2hg-o\u2082the-respective-sta\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T07:25:08+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"Consider the following reaction : 2HgO \u23af\u23af\u2192 2Hg + O\u2082 The respective sta","description":"Mercuric oxide (HgO) is a solid compound at room temperature. Mercury (Hg) is the only metal that exists as a liquid at room temperature. Oxygen (O\u2082) is a gas at room temperature. Therefore, the respective states of HgO, Hg, and O\u2082 are solid, liquid, and gas. The physical states of substances at standard temperature and pressure (or implied conditions) are important in chemical reactions. Mercury is unique among metals in being liquid at room temperature.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-reaction-2hgo-\u23af\u23af\u2192-2hg-o\u2082the-respective-sta\/","og_locale":"en_US","og_type":"article","og_title":"Consider the following reaction : 2HgO \u23af\u23af\u2192 2Hg + O\u2082 The respective sta","og_description":"Mercuric oxide (HgO) is a solid compound at room temperature. Mercury (Hg) is the only metal that exists as a liquid at room temperature. Oxygen (O\u2082) is a gas at room temperature. Therefore, the respective states of HgO, Hg, and O\u2082 are solid, liquid, and gas. The physical states of substances at standard temperature and pressure (or implied conditions) are important in chemical reactions. Mercury is unique among metals in being liquid at room temperature.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-reaction-2hgo-\u23af\u23af\u2192-2hg-o\u2082the-respective-sta\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T07:25:08+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-reaction-2hgo-%e2%8e%af%e2%8e%af%e2%86%92-2hg-o%e2%82%82the-respective-sta\/","url":"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-reaction-2hgo-%e2%8e%af%e2%8e%af%e2%86%92-2hg-o%e2%82%82the-respective-sta\/","name":"Consider the following reaction : 2HgO \u23af\u23af\u2192 2Hg + O\u2082 The respective sta","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T07:25:08+00:00","dateModified":"2025-06-01T07:25:08+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"Mercuric oxide (HgO) is a solid compound at room temperature. Mercury (Hg) is the only metal that exists as a liquid at room temperature. Oxygen (O\u2082) is a gas at room temperature. Therefore, the respective states of HgO, Hg, and O\u2082 are solid, liquid, and gas. The physical states of substances at standard temperature and pressure (or implied conditions) are important in chemical reactions. Mercury is unique among metals in being liquid at room temperature.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-reaction-2hgo-%e2%8e%af%e2%8e%af%e2%86%92-2hg-o%e2%82%82the-respective-sta\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-reaction-2hgo-%e2%8e%af%e2%8e%af%e2%86%92-2hg-o%e2%82%82the-respective-sta\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-reaction-2hgo-%e2%8e%af%e2%8e%af%e2%86%92-2hg-o%e2%82%82the-respective-sta\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC NDA-2","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-nda-2\/"},{"@type":"ListItem","position":3,"name":"Consider the following reaction : 2HgO \u23af\u23af\u2192 2Hg + O\u2082 The respective sta"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/88935","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=88935"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/88935\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=88935"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=88935"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=88935"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}