{"id":88923,"date":"2025-06-01T07:24:54","date_gmt":"2025-06-01T07:24:54","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=88923"},"modified":"2025-06-01T07:24:54","modified_gmt":"2025-06-01T07:24:54","slug":"the-potential-difference-between-the-two-end-terminals-of-an-electric","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/the-potential-difference-between-the-two-end-terminals-of-an-electric\/","title":{"rendered":"The potential difference between the two end terminals of an electric"},"content":{"rendered":"

The potential difference between the two end terminals of an electric heater is 220 V and the current through it is 0\u00b75 A. What would be the current through the heater if the potential difference across the terminals of the heater is reduced to 120 V ?<\/p>\n

[amp_mcq option1=”1\u00b70 A” option2=”0\u00b75 A” option3=”0\u00b727 A” option4=”0\u00b77 A” correct=”option3″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC NDA-2 – 2023<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nAssuming the resistance of the electric heater remains constant, the current through it would be approximately 0.27 A when the potential difference is reduced to 120 V.
\n<\/section>\n
\n– We can use Ohm’s Law, which states that the voltage (V) across a resistor is directly proportional to the current (I) flowing through it, provided the temperature and other physical conditions remain unchanged (V = I * R).
\n– First, calculate the resistance (R) of the heater using the initial conditions: V1 = 220 V, I1 = 0.5 A.
\n– R = V1 \/ I1 = 220 V \/ 0.5 A = 440 ohms.
\n– Now, use this resistance to find the new current (I2) when the potential difference (V2) is 120 V.
\n– V2 = I2 * R
\n– 120 V = I2 * 440 ohms
\n– I2 = 120 V \/ 440 ohms = 12 \/ 44 A = 3 \/ 11 A.
\n– Calculating the decimal value: 3 \/ 11 \u2248 0.2727 A.
\n<\/section>\n
\nIn reality, the resistance of a heater element made of materials like nichrome increases with temperature. However, standard Ohm’s Law problems involving fixed resistors or devices like heaters typically assume constant resistance unless otherwise specified. The calculated current represents the value based on this common assumption.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

The potential difference between the two end terminals of an electric heater is 220 V and the current through it is 0\u00b75 A. What would be the current through the heater if the potential difference across the terminals of the heater is reduced to 120 V ? [amp_mcq option1=”1\u00b70 A” option2=”0\u00b75 A” option3=”0\u00b727 A” option4=”0\u00b77 … <\/p>\n

Detailed SolutionThe potential difference between the two end terminals of an electric<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1094],"tags":[1105,1201,1128],"class_list":["post-88923","post","type-post","status-publish","format-standard","hentry","category-upsc-nda-2","tag-1105","tag-electric-current","tag-physics","no-featured-image-padding"],"yoast_head":"\nThe potential difference between the two end terminals of an electric<\/title>\n<meta name=\"description\" content=\"Assuming the resistance of the electric heater remains constant, the current through it would be approximately 0.27 A when the potential difference is reduced to 120 V. - We can use Ohm's Law, which states that the voltage (V) across a resistor is directly proportional to the current (I) flowing through it, provided the temperature and other physical conditions remain unchanged (V = I * R). - First, calculate the resistance (R) of the heater using the initial conditions: V1 = 220 V, I1 = 0.5 A. - R = V1 \/ I1 = 220 V \/ 0.5 A = 440 ohms. - Now, use this resistance to find the new current (I2) when the potential difference (V2) is 120 V. - V2 = I2 * R - 120 V = I2 * 440 ohms - I2 = 120 V \/ 440 ohms = 12 \/ 44 A = 3 \/ 11 A. - Calculating the decimal value: 3 \/ 11 \u2248 0.2727 A.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/the-potential-difference-between-the-two-end-terminals-of-an-electric\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"The potential difference between the two end terminals of an electric\" \/>\n<meta property=\"og:description\" content=\"Assuming the resistance of the electric heater remains constant, the current through it would be approximately 0.27 A when the potential difference is reduced to 120 V. - We can use Ohm's Law, which states that the voltage (V) across a resistor is directly proportional to the current (I) flowing through it, provided the temperature and other physical conditions remain unchanged (V = I * R). - First, calculate the resistance (R) of the heater using the initial conditions: V1 = 220 V, I1 = 0.5 A. - R = V1 \/ I1 = 220 V \/ 0.5 A = 440 ohms. - Now, use this resistance to find the new current (I2) when the potential difference (V2) is 120 V. - V2 = I2 * R - 120 V = I2 * 440 ohms - I2 = 120 V \/ 440 ohms = 12 \/ 44 A = 3 \/ 11 A. - Calculating the decimal value: 3 \/ 11 \u2248 0.2727 A.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/the-potential-difference-between-the-two-end-terminals-of-an-electric\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T07:24:54+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"The potential difference between the two end terminals of an electric","description":"Assuming the resistance of the electric heater remains constant, the current through it would be approximately 0.27 A when the potential difference is reduced to 120 V. - We can use Ohm's Law, which states that the voltage (V) across a resistor is directly proportional to the current (I) flowing through it, provided the temperature and other physical conditions remain unchanged (V = I * R). - First, calculate the resistance (R) of the heater using the initial conditions: V1 = 220 V, I1 = 0.5 A. - R = V1 \/ I1 = 220 V \/ 0.5 A = 440 ohms. - Now, use this resistance to find the new current (I2) when the potential difference (V2) is 120 V. - V2 = I2 * R - 120 V = I2 * 440 ohms - I2 = 120 V \/ 440 ohms = 12 \/ 44 A = 3 \/ 11 A. - Calculating the decimal value: 3 \/ 11 \u2248 0.2727 A.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/the-potential-difference-between-the-two-end-terminals-of-an-electric\/","og_locale":"en_US","og_type":"article","og_title":"The potential difference between the two end terminals of an electric","og_description":"Assuming the resistance of the electric heater remains constant, the current through it would be approximately 0.27 A when the potential difference is reduced to 120 V. - We can use Ohm's Law, which states that the voltage (V) across a resistor is directly proportional to the current (I) flowing through it, provided the temperature and other physical conditions remain unchanged (V = I * R). - First, calculate the resistance (R) of the heater using the initial conditions: V1 = 220 V, I1 = 0.5 A. - R = V1 \/ I1 = 220 V \/ 0.5 A = 440 ohms. - Now, use this resistance to find the new current (I2) when the potential difference (V2) is 120 V. - V2 = I2 * R - 120 V = I2 * 440 ohms - I2 = 120 V \/ 440 ohms = 12 \/ 44 A = 3 \/ 11 A. - Calculating the decimal value: 3 \/ 11 \u2248 0.2727 A.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/the-potential-difference-between-the-two-end-terminals-of-an-electric\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T07:24:54+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/the-potential-difference-between-the-two-end-terminals-of-an-electric\/","url":"https:\/\/exam.pscnotes.com\/mcq\/the-potential-difference-between-the-two-end-terminals-of-an-electric\/","name":"The potential difference between the two end terminals of an electric","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T07:24:54+00:00","dateModified":"2025-06-01T07:24:54+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"Assuming the resistance of the electric heater remains constant, the current through it would be approximately 0.27 A when the potential difference is reduced to 120 V. - We can use Ohm's Law, which states that the voltage (V) across a resistor is directly proportional to the current (I) flowing through it, provided the temperature and other physical conditions remain unchanged (V = I * R). - First, calculate the resistance (R) of the heater using the initial conditions: V1 = 220 V, I1 = 0.5 A. - R = V1 \/ I1 = 220 V \/ 0.5 A = 440 ohms. - Now, use this resistance to find the new current (I2) when the potential difference (V2) is 120 V. - V2 = I2 * R - 120 V = I2 * 440 ohms - I2 = 120 V \/ 440 ohms = 12 \/ 44 A = 3 \/ 11 A. - Calculating the decimal value: 3 \/ 11 \u2248 0.2727 A.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/the-potential-difference-between-the-two-end-terminals-of-an-electric\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/the-potential-difference-between-the-two-end-terminals-of-an-electric\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/the-potential-difference-between-the-two-end-terminals-of-an-electric\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC NDA-2","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-nda-2\/"},{"@type":"ListItem","position":3,"name":"The potential difference between the two end terminals of an electric"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/88923","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=88923"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/88923\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=88923"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=88923"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=88923"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}