{"id":88843,"date":"2025-06-01T07:23:19","date_gmt":"2025-06-01T07:23:19","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=88843"},"modified":"2025-06-01T07:23:19","modified_gmt":"2025-06-01T07:23:19","slug":"an-electric-bulb-is-connected-to-220-v-generator-the-current-drawn-is","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/an-electric-bulb-is-connected-to-220-v-generator-the-current-drawn-is\/","title":{"rendered":"An electric bulb is connected to 220 V generator. The current drawn is"},"content":{"rendered":"

An electric bulb is connected to 220 V generator. The current drawn is 600 mA. What is the power of the bulb?<\/p>\n

[amp_mcq option1=”132 W” option2=”13.2 W” option3=”1320 W” option4=”13200 W” correct=”option1″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC NDA-2 – 2022<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe power (P) of an electrical device connected to a circuit is given by the formula:
\nP = V \u00d7 I
\nWhere V is the voltage across the device and I is the current flowing through it.
\nGiven:
\nVoltage (V) = 220 V
\nCurrent (I) = 600 mA
\nFirst, convert the current from milliamperes (mA) to amperes (A):
\n1 A = 1000 mA
\nSo, 600 mA = 600 \/ 1000 A = 0.6 A.
\nNow, calculate the power:
\nP = 220 V \u00d7 0.6 A
\nP = 220 \u00d7 (6\/10) W
\nP = 22 \u00d7 6 W
\nP = 132 W.
\n<\/section>\n
\nPower is calculated as the product of voltage and current (P=VI). Ensure units are in Volts and Amperes to get Power in Watts.
\n<\/section>\n
\nThis calculation is a fundamental application of Ohm’s law and the power formula in basic electricity. The resistance of the bulb could also be calculated using Ohm’s law (V=IR), but it is not needed to find the power. The power rating (in Watts) indicates the rate at which the bulb consumes electrical energy.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

An electric bulb is connected to 220 V generator. The current drawn is 600 mA. What is the power of the bulb? [amp_mcq option1=”132 W” option2=”13.2 W” option3=”1320 W” option4=”13200 W” correct=”option1″] This question was previously asked in UPSC NDA-2 – 2022 Download PDFAttempt Online The power (P) of an electrical device connected to a … <\/p>\n

Detailed SolutionAn electric bulb is connected to 220 V generator. The current drawn is<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1094],"tags":[1108,1201,1128],"class_list":["post-88843","post","type-post","status-publish","format-standard","hentry","category-upsc-nda-2","tag-1108","tag-electric-current","tag-physics","no-featured-image-padding"],"yoast_head":"\nAn electric bulb is connected to 220 V generator. The current drawn is<\/title>\n<meta name=\"description\" content=\"The power (P) of an electrical device connected to a circuit is given by the formula: P = V \u00d7 I Where V is the voltage across the device and I is the current flowing through it. Given: Voltage (V) = 220 V Current (I) = 600 mA First, convert the current from milliamperes (mA) to amperes (A): 1 A = 1000 mA So, 600 mA = 600 \/ 1000 A = 0.6 A. Now, calculate the power: P = 220 V \u00d7 0.6 A P = 220 \u00d7 (6\/10) W P = 22 \u00d7 6 W P = 132 W. Power is calculated as the product of voltage and current (P=VI). Ensure units are in Volts and Amperes to get Power in Watts.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/an-electric-bulb-is-connected-to-220-v-generator-the-current-drawn-is\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"An electric bulb is connected to 220 V generator. The current drawn is\" \/>\n<meta property=\"og:description\" content=\"The power (P) of an electrical device connected to a circuit is given by the formula: P = V \u00d7 I Where V is the voltage across the device and I is the current flowing through it. Given: Voltage (V) = 220 V Current (I) = 600 mA First, convert the current from milliamperes (mA) to amperes (A): 1 A = 1000 mA So, 600 mA = 600 \/ 1000 A = 0.6 A. Now, calculate the power: P = 220 V \u00d7 0.6 A P = 220 \u00d7 (6\/10) W P = 22 \u00d7 6 W P = 132 W. Power is calculated as the product of voltage and current (P=VI). Ensure units are in Volts and Amperes to get Power in Watts.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/an-electric-bulb-is-connected-to-220-v-generator-the-current-drawn-is\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T07:23:19+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"An electric bulb is connected to 220 V generator. The current drawn is","description":"The power (P) of an electrical device connected to a circuit is given by the formula: P = V \u00d7 I Where V is the voltage across the device and I is the current flowing through it. Given: Voltage (V) = 220 V Current (I) = 600 mA First, convert the current from milliamperes (mA) to amperes (A): 1 A = 1000 mA So, 600 mA = 600 \/ 1000 A = 0.6 A. Now, calculate the power: P = 220 V \u00d7 0.6 A P = 220 \u00d7 (6\/10) W P = 22 \u00d7 6 W P = 132 W. Power is calculated as the product of voltage and current (P=VI). Ensure units are in Volts and Amperes to get Power in Watts.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/an-electric-bulb-is-connected-to-220-v-generator-the-current-drawn-is\/","og_locale":"en_US","og_type":"article","og_title":"An electric bulb is connected to 220 V generator. The current drawn is","og_description":"The power (P) of an electrical device connected to a circuit is given by the formula: P = V \u00d7 I Where V is the voltage across the device and I is the current flowing through it. Given: Voltage (V) = 220 V Current (I) = 600 mA First, convert the current from milliamperes (mA) to amperes (A): 1 A = 1000 mA So, 600 mA = 600 \/ 1000 A = 0.6 A. Now, calculate the power: P = 220 V \u00d7 0.6 A P = 220 \u00d7 (6\/10) W P = 22 \u00d7 6 W P = 132 W. Power is calculated as the product of voltage and current (P=VI). Ensure units are in Volts and Amperes to get Power in Watts.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/an-electric-bulb-is-connected-to-220-v-generator-the-current-drawn-is\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T07:23:19+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/an-electric-bulb-is-connected-to-220-v-generator-the-current-drawn-is\/","url":"https:\/\/exam.pscnotes.com\/mcq\/an-electric-bulb-is-connected-to-220-v-generator-the-current-drawn-is\/","name":"An electric bulb is connected to 220 V generator. The current drawn is","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T07:23:19+00:00","dateModified":"2025-06-01T07:23:19+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The power (P) of an electrical device connected to a circuit is given by the formula: P = V \u00d7 I Where V is the voltage across the device and I is the current flowing through it. Given: Voltage (V) = 220 V Current (I) = 600 mA First, convert the current from milliamperes (mA) to amperes (A): 1 A = 1000 mA So, 600 mA = 600 \/ 1000 A = 0.6 A. Now, calculate the power: P = 220 V \u00d7 0.6 A P = 220 \u00d7 (6\/10) W P = 22 \u00d7 6 W P = 132 W. Power is calculated as the product of voltage and current (P=VI). Ensure units are in Volts and Amperes to get Power in Watts.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/an-electric-bulb-is-connected-to-220-v-generator-the-current-drawn-is\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/an-electric-bulb-is-connected-to-220-v-generator-the-current-drawn-is\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/an-electric-bulb-is-connected-to-220-v-generator-the-current-drawn-is\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC NDA-2","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-nda-2\/"},{"@type":"ListItem","position":3,"name":"An electric bulb is connected to 220 V generator. The current drawn is"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/88843","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=88843"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/88843\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=88843"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=88843"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=88843"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}