{"id":88827,"date":"2025-06-01T07:21:59","date_gmt":"2025-06-01T07:21:59","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=88827"},"modified":"2025-06-01T07:21:59","modified_gmt":"2025-06-01T07:21:59","slug":"a-negative-work-is-done-when-an-applied-force-f-and-the-corresponding","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/a-negative-work-is-done-when-an-applied-force-f-and-the-corresponding\/","title":{"rendered":"A negative work is done when an applied force F and the corresponding"},"content":{"rendered":"

A negative work is done when an applied force F and the corresponding displacement S are<\/p>\n

[amp_mcq option1=”perpendicular to each other.” option2=”parallel to each other.” option3=”anti-parallel to each other.” option4=”equal in magnitude.” correct=”option3″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC NDA-2 – 2021<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
A negative work is done when an applied force F and the corresponding displacement S are anti-parallel to each other.<\/section>\n
The work done (W) by a constant force (F) when an object undergoes a displacement (S) is given by the dot product of the force and displacement vectors: $W = \\vec{F} \\cdot \\vec{S} = |\\vec{F}| |\\vec{S}| \\cos\\theta$, where $\\theta$ is the angle between the force and displacement vectors. Work done is positive when the force and displacement are in the same general direction ($0^\\circ \\le \\theta < 90^\\circ$), zero when they are perpendicular ($\\theta = 90^\\circ$), and negative when they are in opposite directions ($90^\\circ < \\theta \\le 180^\\circ$). When the force and displacement are anti-parallel ($\\theta = 180^\\circ$), $\\cos\\theta = -1$, and the work done is maximum negative: $W = -FS$.<\/section>\n
Examples of negative work include the work done by friction when an object moves (friction acts opposite to motion), or the work done by gravity when an object is lifted upwards (gravity acts downwards while displacement is upwards).<\/section>\n","protected":false},"excerpt":{"rendered":"

A negative work is done when an applied force F and the corresponding displacement S are [amp_mcq option1=”perpendicular to each other.” option2=”parallel to each other.” option3=”anti-parallel to each other.” option4=”equal in magnitude.” correct=”option3″] This question was previously asked in UPSC NDA-2 – 2021 Download PDFAttempt Online A negative work is done when an applied force … <\/p>\n

Detailed SolutionA negative work is done when an applied force F and the corresponding<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1094],"tags":[1110,1129,1128],"class_list":["post-88827","post","type-post","status-publish","format-standard","hentry","category-upsc-nda-2","tag-1110","tag-mechanics","tag-physics","no-featured-image-padding"],"yoast_head":"\nA negative work is done when an applied force F and the corresponding<\/title>\n<meta name=\"description\" content=\"A negative work is done when an applied force F and the corresponding displacement S are anti-parallel to each other. The work done (W) by a constant force (F) when an object undergoes a displacement (S) is given by the dot product of the force and displacement vectors: $W = vec{F} cdot vec{S} = |vec{F}| |vec{S}| costheta$, where $theta$ is the angle between the force and displacement vectors. Work done is positive when the force and displacement are in the same general direction ($0^circ le theta < 90^circ$), zero when they are perpendicular ($theta = 90^circ$), and negative when they are in opposite directions ($90^circ < theta le 180^circ$). When the force and displacement are anti-parallel ($theta = 180^circ$), $costheta = -1$, and the work done is maximum negative: $W = -FS$.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/a-negative-work-is-done-when-an-applied-force-f-and-the-corresponding\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"A negative work is done when an applied force F and the corresponding\" \/>\n<meta property=\"og:description\" content=\"A negative work is done when an applied force F and the corresponding displacement S are anti-parallel to each other. The work done (W) by a constant force (F) when an object undergoes a displacement (S) is given by the dot product of the force and displacement vectors: $W = vec{F} cdot vec{S} = |vec{F}| |vec{S}| costheta$, where $theta$ is the angle between the force and displacement vectors. Work done is positive when the force and displacement are in the same general direction ($0^circ le theta < 90^circ$), zero when they are perpendicular ($theta = 90^circ$), and negative when they are in opposite directions ($90^circ < theta le 180^circ$). When the force and displacement are anti-parallel ($theta = 180^circ$), $costheta = -1$, and the work done is maximum negative: $W = -FS$.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/a-negative-work-is-done-when-an-applied-force-f-and-the-corresponding\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T07:21:59+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"A negative work is done when an applied force F and the corresponding","description":"A negative work is done when an applied force F and the corresponding displacement S are anti-parallel to each other. The work done (W) by a constant force (F) when an object undergoes a displacement (S) is given by the dot product of the force and displacement vectors: $W = vec{F} cdot vec{S} = |vec{F}| |vec{S}| costheta$, where $theta$ is the angle between the force and displacement vectors. Work done is positive when the force and displacement are in the same general direction ($0^circ le theta < 90^circ$), zero when they are perpendicular ($theta = 90^circ$), and negative when they are in opposite directions ($90^circ < theta le 180^circ$). When the force and displacement are anti-parallel ($theta = 180^circ$), $costheta = -1$, and the work done is maximum negative: $W = -FS$.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/a-negative-work-is-done-when-an-applied-force-f-and-the-corresponding\/","og_locale":"en_US","og_type":"article","og_title":"A negative work is done when an applied force F and the corresponding","og_description":"A negative work is done when an applied force F and the corresponding displacement S are anti-parallel to each other. The work done (W) by a constant force (F) when an object undergoes a displacement (S) is given by the dot product of the force and displacement vectors: $W = vec{F} cdot vec{S} = |vec{F}| |vec{S}| costheta$, where $theta$ is the angle between the force and displacement vectors. Work done is positive when the force and displacement are in the same general direction ($0^circ le theta < 90^circ$), zero when they are perpendicular ($theta = 90^circ$), and negative when they are in opposite directions ($90^circ < theta le 180^circ$). When the force and displacement are anti-parallel ($theta = 180^circ$), $costheta = -1$, and the work done is maximum negative: $W = -FS$.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/a-negative-work-is-done-when-an-applied-force-f-and-the-corresponding\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T07:21:59+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/a-negative-work-is-done-when-an-applied-force-f-and-the-corresponding\/","url":"https:\/\/exam.pscnotes.com\/mcq\/a-negative-work-is-done-when-an-applied-force-f-and-the-corresponding\/","name":"A negative work is done when an applied force F and the corresponding","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T07:21:59+00:00","dateModified":"2025-06-01T07:21:59+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"A negative work is done when an applied force F and the corresponding displacement S are anti-parallel to each other. The work done (W) by a constant force (F) when an object undergoes a displacement (S) is given by the dot product of the force and displacement vectors: $W = \\vec{F} \\cdot \\vec{S} = |\\vec{F}| |\\vec{S}| \\cos\\theta$, where $\\theta$ is the angle between the force and displacement vectors. Work done is positive when the force and displacement are in the same general direction ($0^\\circ \\le \\theta < 90^\\circ$), zero when they are perpendicular ($\\theta = 90^\\circ$), and negative when they are in opposite directions ($90^\\circ < \\theta \\le 180^\\circ$). When the force and displacement are anti-parallel ($\\theta = 180^\\circ$), $\\cos\\theta = -1$, and the work done is maximum negative: $W = -FS$.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/a-negative-work-is-done-when-an-applied-force-f-and-the-corresponding\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/a-negative-work-is-done-when-an-applied-force-f-and-the-corresponding\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/a-negative-work-is-done-when-an-applied-force-f-and-the-corresponding\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC NDA-2","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-nda-2\/"},{"@type":"ListItem","position":3,"name":"A negative work is done when an applied force F and the corresponding"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/88827","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=88827"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/88827\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=88827"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=88827"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=88827"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}