{"id":88819,"date":"2025-06-01T07:21:50","date_gmt":"2025-06-01T07:21:50","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=88819"},"modified":"2025-06-01T07:21:50","modified_gmt":"2025-06-01T07:21:50","slug":"which-one-of-the-following-ions-is-not-iso-electronic-with-f%e2%81%bb","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-ions-is-not-iso-electronic-with-f%e2%81%bb\/","title":{"rendered":"Which one of the following ions is not iso-electronic with F\u207b ?"},"content":{"rendered":"

Which one of the following ions is not<\/b> iso-electronic with F\u207b ?<\/p>\n

[amp_mcq option1=”O\u00b2\u207b” option2=”Na\u207a” option3=”Ne” option4=”N\u207b” correct=”option4″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC NDA-2 – 2021<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe correct option is D. Iso-electronic species are atoms or ions that have the same number of electrons. We need to find which species among the options does not have the same number of electrons as F\u207b.
\n<\/section>\n
\nA neutral Fluorine atom (F) has 9 electrons (atomic number = 9). The F\u207b ion has gained one electron, so it has $9 + 1 = 10$ electrons.
\nLet’s find the number of electrons for each option:
\nA) O\u00b2\u207b: Neutral Oxygen (O) has 8 electrons (atomic number = 8). O\u00b2\u207b has gained two electrons, so $8 + 2 = 10$ electrons.
\nB) Na\u207a: Neutral Sodium (Na) has 11 electrons (atomic number = 11). Na\u207a has lost one electron, so $11 – 1 = 10$ electrons.
\nC) Ne: Neutral Neon (Ne) has 10 electrons (atomic number = 10).
\nD) N\u207b: Neutral Nitrogen (N) has 7 electrons (atomic number = 7). N\u207b has gained one electron, so $7 + 1 = 8$ electrons.
\nThus, N\u207b has 8 electrons, while F\u207b has 10 electrons. N\u207b is not isoelectronic with F\u207b.
\n<\/section>\n
\nIsoelectronic species often have similar chemical and physical properties due to having the same electron configuration. The species O\u00b2\u207b, F\u207b, Ne, Na\u207a, Mg\u00b2\u207a, Al\u00b3\u207a are all isoelectronic with 10 electrons, having the electron configuration of Neon.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

Which one of the following ions is not iso-electronic with F\u207b ? [amp_mcq option1=”O\u00b2\u207b” option2=”Na\u207a” option3=”Ne” option4=”N\u207b” correct=”option4″] This question was previously asked in UPSC NDA-2 – 2021 Download PDFAttempt Online The correct option is D. Iso-electronic species are atoms or ions that have the same number of electrons. We need to find which species … <\/p>\n

Detailed SolutionWhich one of the following ions is not iso-electronic with F\u207b ?<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1094],"tags":[1110,1162,1096],"class_list":["post-88819","post","type-post","status-publish","format-standard","hentry","category-upsc-nda-2","tag-1110","tag-atomic-structure","tag-chemistry","no-featured-image-padding"],"yoast_head":"\nWhich one of the following ions is not iso-electronic with F\u207b ?<\/title>\n<meta name=\"description\" content=\"The correct option is D. Iso-electronic species are atoms or ions that have the same number of electrons. We need to find which species among the options does not have the same number of electrons as F\u207b. A neutral Fluorine atom (F) has 9 electrons (atomic number = 9). The F\u207b ion has gained one electron, so it has $9 + 1 = 10$ electrons. Let's find the number of electrons for each option: A) O\u00b2\u207b: Neutral Oxygen (O) has 8 electrons (atomic number = 8). O\u00b2\u207b has gained two electrons, so $8 + 2 = 10$ electrons. B) Na\u207a: Neutral Sodium (Na) has 11 electrons (atomic number = 11). Na\u207a has lost one electron, so $11 - 1 = 10$ electrons. C) Ne: Neutral Neon (Ne) has 10 electrons (atomic number = 10). D) N\u207b: Neutral Nitrogen (N) has 7 electrons (atomic number = 7). N\u207b has gained one electron, so $7 + 1 = 8$ electrons. Thus, N\u207b has 8 electrons, while F\u207b has 10 electrons. N\u207b is not isoelectronic with F\u207b.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-ions-is-not-iso-electronic-with-f\u207b\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Which one of the following ions is not iso-electronic with F\u207b ?\" \/>\n<meta property=\"og:description\" content=\"The correct option is D. Iso-electronic species are atoms or ions that have the same number of electrons. We need to find which species among the options does not have the same number of electrons as F\u207b. A neutral Fluorine atom (F) has 9 electrons (atomic number = 9). The F\u207b ion has gained one electron, so it has $9 + 1 = 10$ electrons. Let's find the number of electrons for each option: A) O\u00b2\u207b: Neutral Oxygen (O) has 8 electrons (atomic number = 8). O\u00b2\u207b has gained two electrons, so $8 + 2 = 10$ electrons. B) Na\u207a: Neutral Sodium (Na) has 11 electrons (atomic number = 11). Na\u207a has lost one electron, so $11 - 1 = 10$ electrons. C) Ne: Neutral Neon (Ne) has 10 electrons (atomic number = 10). D) N\u207b: Neutral Nitrogen (N) has 7 electrons (atomic number = 7). N\u207b has gained one electron, so $7 + 1 = 8$ electrons. Thus, N\u207b has 8 electrons, while F\u207b has 10 electrons. N\u207b is not isoelectronic with F\u207b.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-ions-is-not-iso-electronic-with-f\u207b\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T07:21:50+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"Which one of the following ions is not iso-electronic with F\u207b ?","description":"The correct option is D. Iso-electronic species are atoms or ions that have the same number of electrons. We need to find which species among the options does not have the same number of electrons as F\u207b. A neutral Fluorine atom (F) has 9 electrons (atomic number = 9). The F\u207b ion has gained one electron, so it has $9 + 1 = 10$ electrons. Let's find the number of electrons for each option: A) O\u00b2\u207b: Neutral Oxygen (O) has 8 electrons (atomic number = 8). O\u00b2\u207b has gained two electrons, so $8 + 2 = 10$ electrons. B) Na\u207a: Neutral Sodium (Na) has 11 electrons (atomic number = 11). Na\u207a has lost one electron, so $11 - 1 = 10$ electrons. C) Ne: Neutral Neon (Ne) has 10 electrons (atomic number = 10). D) N\u207b: Neutral Nitrogen (N) has 7 electrons (atomic number = 7). N\u207b has gained one electron, so $7 + 1 = 8$ electrons. Thus, N\u207b has 8 electrons, while F\u207b has 10 electrons. N\u207b is not isoelectronic with F\u207b.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-ions-is-not-iso-electronic-with-f\u207b\/","og_locale":"en_US","og_type":"article","og_title":"Which one of the following ions is not iso-electronic with F\u207b ?","og_description":"The correct option is D. Iso-electronic species are atoms or ions that have the same number of electrons. We need to find which species among the options does not have the same number of electrons as F\u207b. A neutral Fluorine atom (F) has 9 electrons (atomic number = 9). The F\u207b ion has gained one electron, so it has $9 + 1 = 10$ electrons. Let's find the number of electrons for each option: A) O\u00b2\u207b: Neutral Oxygen (O) has 8 electrons (atomic number = 8). O\u00b2\u207b has gained two electrons, so $8 + 2 = 10$ electrons. B) Na\u207a: Neutral Sodium (Na) has 11 electrons (atomic number = 11). Na\u207a has lost one electron, so $11 - 1 = 10$ electrons. C) Ne: Neutral Neon (Ne) has 10 electrons (atomic number = 10). D) N\u207b: Neutral Nitrogen (N) has 7 electrons (atomic number = 7). N\u207b has gained one electron, so $7 + 1 = 8$ electrons. Thus, N\u207b has 8 electrons, while F\u207b has 10 electrons. N\u207b is not isoelectronic with F\u207b.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-ions-is-not-iso-electronic-with-f\u207b\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T07:21:50+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-ions-is-not-iso-electronic-with-f%e2%81%bb\/","url":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-ions-is-not-iso-electronic-with-f%e2%81%bb\/","name":"Which one of the following ions is not iso-electronic with F\u207b ?","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T07:21:50+00:00","dateModified":"2025-06-01T07:21:50+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The correct option is D. Iso-electronic species are atoms or ions that have the same number of electrons. We need to find which species among the options does not have the same number of electrons as F\u207b. A neutral Fluorine atom (F) has 9 electrons (atomic number = 9). The F\u207b ion has gained one electron, so it has $9 + 1 = 10$ electrons. Let's find the number of electrons for each option: A) O\u00b2\u207b: Neutral Oxygen (O) has 8 electrons (atomic number = 8). O\u00b2\u207b has gained two electrons, so $8 + 2 = 10$ electrons. B) Na\u207a: Neutral Sodium (Na) has 11 electrons (atomic number = 11). Na\u207a has lost one electron, so $11 - 1 = 10$ electrons. C) Ne: Neutral Neon (Ne) has 10 electrons (atomic number = 10). D) N\u207b: Neutral Nitrogen (N) has 7 electrons (atomic number = 7). N\u207b has gained one electron, so $7 + 1 = 8$ electrons. Thus, N\u207b has 8 electrons, while F\u207b has 10 electrons. N\u207b is not isoelectronic with F\u207b.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-ions-is-not-iso-electronic-with-f%e2%81%bb\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-ions-is-not-iso-electronic-with-f%e2%81%bb\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-ions-is-not-iso-electronic-with-f%e2%81%bb\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC NDA-2","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-nda-2\/"},{"@type":"ListItem","position":3,"name":"Which one of the following ions is not iso-electronic with F\u207b ?"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/88819","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=88819"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/88819\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=88819"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=88819"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=88819"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}