{"id":88547,"date":"2025-06-01T07:14:25","date_gmt":"2025-06-01T07:14:25","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=88547"},"modified":"2025-06-01T07:14:25","modified_gmt":"2025-06-01T07:14:25","slug":"if-the-work-done-on-the-system-or-by-the-system-is-zero-which-one-of","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/if-the-work-done-on-the-system-or-by-the-system-is-zero-which-one-of\/","title":{"rendered":"If the work done on the system or by the system is zero, which one of"},"content":{"rendered":"

If the work done on the system or by the system is zero, which one of the following statements for a gas kept at a certain temperature is correct ?<\/p>\n

[amp_mcq option1=”Change in internal energy of the system is equal to flow of heat in or out of the system.” option2=”Change in internal energy of the system is less than heat transferred.” option3=”Change in internal energy of the system is more than the heat flow.” option4=”Cannot be determined.” correct=”option1″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC NDA-2 – 2019<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe first law of thermodynamics states that the change in internal energy of a system ($\\Delta U$) is equal to the heat added to the system ($Q$) minus the work done by the system ($W$). This can be written as $\\Delta U = Q – W$. The question states that the work done on the system or by the system is zero, meaning $W = 0$. Substituting this into the first law equation gives $\\Delta U = Q – 0$, which simplifies to $\\Delta U = Q$. Therefore, the change in internal energy of the system is equal to the flow of heat in or out of the system.
\n<\/section>\n
\n– First Law of Thermodynamics: $\\Delta U = Q – W$.
\n– Work done is zero ($W=0$).
\n– The change in internal energy is directly equal to the heat transfer when no work is done.
\n<\/section>\n
\nThis condition ($W=0$) occurs in processes where the volume of the system does not change (isochoric process) or when the system is rigid. Heat flowing into the system increases its internal energy ($Q > 0, \\Delta U > 0$), and heat flowing out decreases its internal energy ($Q < 0, \\Delta U < 0$).\n<\/section>\n","protected":false},"excerpt":{"rendered":"

If the work done on the system or by the system is zero, which one of the following statements for a gas kept at a certain temperature is correct ? [amp_mcq option1=”Change in internal energy of the system is equal to flow of heat in or out of the system.” option2=”Change in internal energy of … <\/p>\n

Detailed SolutionIf the work done on the system or by the system is zero, which one of<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1094],"tags":[1119,1130,1128],"class_list":["post-88547","post","type-post","status-publish","format-standard","hentry","category-upsc-nda-2","tag-1119","tag-heat-and-thermodynamics","tag-physics","no-featured-image-padding"],"yoast_head":"\nIf the work done on the system or by the system is zero, which one of<\/title>\n<meta name=\"description\" content=\"The first law of thermodynamics states that the change in internal energy of a system ($Delta U$) is equal to the heat added to the system ($Q$) minus the work done by the system ($W$). This can be written as $Delta U = Q - W$. The question states that the work done on the system or by the system is zero, meaning $W = 0$. Substituting this into the first law equation gives $Delta U = Q - 0$, which simplifies to $Delta U = Q$. Therefore, the change in internal energy of the system is equal to the flow of heat in or out of the system. - First Law of Thermodynamics: $Delta U = Q - W$. - Work done is zero ($W=0$). - The change in internal energy is directly equal to the heat transfer when no work is done.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/if-the-work-done-on-the-system-or-by-the-system-is-zero-which-one-of\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"If the work done on the system or by the system is zero, which one of\" \/>\n<meta property=\"og:description\" content=\"The first law of thermodynamics states that the change in internal energy of a system ($Delta U$) is equal to the heat added to the system ($Q$) minus the work done by the system ($W$). This can be written as $Delta U = Q - W$. The question states that the work done on the system or by the system is zero, meaning $W = 0$. Substituting this into the first law equation gives $Delta U = Q - 0$, which simplifies to $Delta U = Q$. Therefore, the change in internal energy of the system is equal to the flow of heat in or out of the system. - First Law of Thermodynamics: $Delta U = Q - W$. - Work done is zero ($W=0$). - The change in internal energy is directly equal to the heat transfer when no work is done.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/if-the-work-done-on-the-system-or-by-the-system-is-zero-which-one-of\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T07:14:25+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"If the work done on the system or by the system is zero, which one of","description":"The first law of thermodynamics states that the change in internal energy of a system ($Delta U$) is equal to the heat added to the system ($Q$) minus the work done by the system ($W$). This can be written as $Delta U = Q - W$. The question states that the work done on the system or by the system is zero, meaning $W = 0$. Substituting this into the first law equation gives $Delta U = Q - 0$, which simplifies to $Delta U = Q$. Therefore, the change in internal energy of the system is equal to the flow of heat in or out of the system. - First Law of Thermodynamics: $Delta U = Q - W$. - Work done is zero ($W=0$). - The change in internal energy is directly equal to the heat transfer when no work is done.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/if-the-work-done-on-the-system-or-by-the-system-is-zero-which-one-of\/","og_locale":"en_US","og_type":"article","og_title":"If the work done on the system or by the system is zero, which one of","og_description":"The first law of thermodynamics states that the change in internal energy of a system ($Delta U$) is equal to the heat added to the system ($Q$) minus the work done by the system ($W$). This can be written as $Delta U = Q - W$. The question states that the work done on the system or by the system is zero, meaning $W = 0$. Substituting this into the first law equation gives $Delta U = Q - 0$, which simplifies to $Delta U = Q$. Therefore, the change in internal energy of the system is equal to the flow of heat in or out of the system. - First Law of Thermodynamics: $Delta U = Q - W$. - Work done is zero ($W=0$). - The change in internal energy is directly equal to the heat transfer when no work is done.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/if-the-work-done-on-the-system-or-by-the-system-is-zero-which-one-of\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T07:14:25+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/if-the-work-done-on-the-system-or-by-the-system-is-zero-which-one-of\/","url":"https:\/\/exam.pscnotes.com\/mcq\/if-the-work-done-on-the-system-or-by-the-system-is-zero-which-one-of\/","name":"If the work done on the system or by the system is zero, which one of","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T07:14:25+00:00","dateModified":"2025-06-01T07:14:25+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The first law of thermodynamics states that the change in internal energy of a system ($\\Delta U$) is equal to the heat added to the system ($Q$) minus the work done by the system ($W$). This can be written as $\\Delta U = Q - W$. The question states that the work done on the system or by the system is zero, meaning $W = 0$. Substituting this into the first law equation gives $\\Delta U = Q - 0$, which simplifies to $\\Delta U = Q$. Therefore, the change in internal energy of the system is equal to the flow of heat in or out of the system. - First Law of Thermodynamics: $\\Delta U = Q - W$. - Work done is zero ($W=0$). - The change in internal energy is directly equal to the heat transfer when no work is done.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/if-the-work-done-on-the-system-or-by-the-system-is-zero-which-one-of\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/if-the-work-done-on-the-system-or-by-the-system-is-zero-which-one-of\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/if-the-work-done-on-the-system-or-by-the-system-is-zero-which-one-of\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC NDA-2","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-nda-2\/"},{"@type":"ListItem","position":3,"name":"If the work done on the system or by the system is zero, which one of"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/88547","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=88547"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/88547\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=88547"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=88547"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=88547"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}