{"id":88544,"date":"2025-06-01T07:14:19","date_gmt":"2025-06-01T07:14:19","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=88544"},"modified":"2025-06-01T07:14:19","modified_gmt":"2025-06-01T07:14:19","slug":"a-car-starts-from-bengaluru-goes-50-km-in-a-straight-line-towards-sou","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/a-car-starts-from-bengaluru-goes-50-km-in-a-straight-line-towards-sou\/","title":{"rendered":"A car starts from Bengaluru, goes 50 km in a straight line towards sou"},"content":{"rendered":"<p>A car starts from Bengaluru, goes 50 km in a straight line towards south, immediately turns around and returns to Bengaluru. The time taken for this round trip is 2 hours. The magnitude of the average velocity of the car for this round trip<\/p>\n<p>[amp_mcq option1=&#8221;is 0.&#8221; option2=&#8221;is 50 km\/hr.&#8221; option3=&#8221;is 25 km\/hr.&#8221; option4=&#8221;cannot be calculated without knowing acceleration.&#8221; correct=&#8221;option1&#8243;]<\/p>\n<div class=\"psc-box-pyq-exam-year-detail\">\n<div class=\"pyq-exam\">\n<div class=\"psc-heading\">This question was previously asked in<\/div>\n<div class=\"psc-title line-ellipsis\">UPSC NDA-2 &#8211; 2019<\/div>\n<\/div>\n<div class=\"pyq-exam-psc-buttons\"><a href=\"\/pyq\/pyq-upsc-nda-2-2019.pdf\" target=\"_blank\" class=\"psc-pdf-button\" rel=\"noopener\">Download PDF<\/a><a href=\"\/pyq-upsc-nda-2-2019\" target=\"_blank\" class=\"psc-attempt-button\" rel=\"noopener\">Attempt Online<\/a><\/div>\n<\/div>\n<section id=\"pyq-correct-answer\">\nAverage velocity is defined as the total displacement divided by the total time taken. Displacement is the change in position from the starting point to the ending point. The car starts from Bengaluru and returns to Bengaluru. Therefore, the initial position and the final position are the same. This means the total displacement is zero.<br \/>\nTotal displacement = Final position &#8211; Initial position = Bengaluru &#8211; Bengaluru = 0 km.<br \/>\nTotal time taken = 2 hours.<br \/>\nAverage velocity = Total displacement \/ Total time = 0 km \/ 2 hours = 0 km\/hr.<br \/>\nThe magnitude of the average velocity is the absolute value of the average velocity, which is $|0| = 0$.<br \/>\n<\/section>\n<section id=\"pyq-key-points\">\n&#8211; Average velocity is a vector quantity and depends on displacement, not total distance traveled.<br \/>\n&#8211; Displacement is the shortest straight-line distance from the starting point to the ending point, along with direction. If the start and end points are the same, displacement is zero.<br \/>\n&#8211; Average speed is a scalar quantity and depends on the total distance traveled divided by the total time. In this case, the average speed is 100 km \/ 2 hr = 50 km\/hr.<br \/>\n<\/section>\n<section id=\"pyq-additional-information\">\n&#8211; The path taken (straight line towards south and back) is relevant for calculating distance but not displacement when the trip is a round trip back to the origin.<br \/>\n&#8211; The acceleration is not constant during the trip (it changes direction when turning around), but this information is not needed to calculate average velocity, which only depends on total displacement and total time.<br \/>\n<\/section>\n","protected":false},"excerpt":{"rendered":"<p>A car starts from Bengaluru, goes 50 km in a straight line towards south, immediately turns around and returns to Bengaluru. The time taken for this round trip is 2 hours. The magnitude of the average velocity of the car for this round trip [amp_mcq option1=&#8221;is 0.&#8221; option2=&#8221;is 50 km\/hr.&#8221; option3=&#8221;is 25 km\/hr.&#8221; option4=&#8221;cannot be &#8230; <\/p>\n<p class=\"read-more-container\"><a title=\"A car starts from Bengaluru, goes 50 km in a straight line towards sou\" class=\"read-more button\" href=\"https:\/\/exam.pscnotes.com\/mcq\/a-car-starts-from-bengaluru-goes-50-km-in-a-straight-line-towards-sou\/#more-88544\">Detailed Solution<span class=\"screen-reader-text\">A car starts from Bengaluru, goes 50 km in a straight line towards sou<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1094],"tags":[1119,1129,1128],"class_list":["post-88544","post","type-post","status-publish","format-standard","hentry","category-upsc-nda-2","tag-1119","tag-mechanics","tag-physics","no-featured-image-padding"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>A car starts from Bengaluru, goes 50 km in a straight line towards sou<\/title>\n<meta name=\"description\" content=\"Average velocity is defined as the total displacement divided by the total time taken. Displacement is the change in position from the starting point to the ending point. The car starts from Bengaluru and returns to Bengaluru. Therefore, the initial position and the final position are the same. This means the total displacement is zero. Total displacement = Final position - Initial position = Bengaluru - Bengaluru = 0 km. Total time taken = 2 hours. Average velocity = Total displacement \/ Total time = 0 km \/ 2 hours = 0 km\/hr. The magnitude of the average velocity is the absolute value of the average velocity, which is $|0| = 0$. - Average velocity is a vector quantity and depends on displacement, not total distance traveled. - Displacement is the shortest straight-line distance from the starting point to the ending point, along with direction. If the start and end points are the same, displacement is zero. - Average speed is a scalar quantity and depends on the total distance traveled divided by the total time. In this case, the average speed is 100 km \/ 2 hr = 50 km\/hr.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/a-car-starts-from-bengaluru-goes-50-km-in-a-straight-line-towards-sou\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"A car starts from Bengaluru, goes 50 km in a straight line towards sou\" \/>\n<meta property=\"og:description\" content=\"Average velocity is defined as the total displacement divided by the total time taken. Displacement is the change in position from the starting point to the ending point. The car starts from Bengaluru and returns to Bengaluru. Therefore, the initial position and the final position are the same. This means the total displacement is zero. Total displacement = Final position - Initial position = Bengaluru - Bengaluru = 0 km. Total time taken = 2 hours. Average velocity = Total displacement \/ Total time = 0 km \/ 2 hours = 0 km\/hr. The magnitude of the average velocity is the absolute value of the average velocity, which is $|0| = 0$. - Average velocity is a vector quantity and depends on displacement, not total distance traveled. - Displacement is the shortest straight-line distance from the starting point to the ending point, along with direction. If the start and end points are the same, displacement is zero. - Average speed is a scalar quantity and depends on the total distance traveled divided by the total time. In this case, the average speed is 100 km \/ 2 hr = 50 km\/hr.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/a-car-starts-from-bengaluru-goes-50-km-in-a-straight-line-towards-sou\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T07:14:19+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"2 minutes\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"A car starts from Bengaluru, goes 50 km in a straight line towards sou","description":"Average velocity is defined as the total displacement divided by the total time taken. Displacement is the change in position from the starting point to the ending point. The car starts from Bengaluru and returns to Bengaluru. Therefore, the initial position and the final position are the same. This means the total displacement is zero. Total displacement = Final position - Initial position = Bengaluru - Bengaluru = 0 km. Total time taken = 2 hours. Average velocity = Total displacement \/ Total time = 0 km \/ 2 hours = 0 km\/hr. The magnitude of the average velocity is the absolute value of the average velocity, which is $|0| = 0$. - Average velocity is a vector quantity and depends on displacement, not total distance traveled. - Displacement is the shortest straight-line distance from the starting point to the ending point, along with direction. If the start and end points are the same, displacement is zero. - Average speed is a scalar quantity and depends on the total distance traveled divided by the total time. In this case, the average speed is 100 km \/ 2 hr = 50 km\/hr.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/a-car-starts-from-bengaluru-goes-50-km-in-a-straight-line-towards-sou\/","og_locale":"en_US","og_type":"article","og_title":"A car starts from Bengaluru, goes 50 km in a straight line towards sou","og_description":"Average velocity is defined as the total displacement divided by the total time taken. Displacement is the change in position from the starting point to the ending point. The car starts from Bengaluru and returns to Bengaluru. Therefore, the initial position and the final position are the same. This means the total displacement is zero. Total displacement = Final position - Initial position = Bengaluru - Bengaluru = 0 km. Total time taken = 2 hours. Average velocity = Total displacement \/ Total time = 0 km \/ 2 hours = 0 km\/hr. The magnitude of the average velocity is the absolute value of the average velocity, which is $|0| = 0$. - Average velocity is a vector quantity and depends on displacement, not total distance traveled. - Displacement is the shortest straight-line distance from the starting point to the ending point, along with direction. If the start and end points are the same, displacement is zero. - Average speed is a scalar quantity and depends on the total distance traveled divided by the total time. In this case, the average speed is 100 km \/ 2 hr = 50 km\/hr.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/a-car-starts-from-bengaluru-goes-50-km-in-a-straight-line-towards-sou\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T07:14:19+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"2 minutes"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/a-car-starts-from-bengaluru-goes-50-km-in-a-straight-line-towards-sou\/","url":"https:\/\/exam.pscnotes.com\/mcq\/a-car-starts-from-bengaluru-goes-50-km-in-a-straight-line-towards-sou\/","name":"A car starts from Bengaluru, goes 50 km in a straight line towards sou","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T07:14:19+00:00","dateModified":"2025-06-01T07:14:19+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"Average velocity is defined as the total displacement divided by the total time taken. Displacement is the change in position from the starting point to the ending point. The car starts from Bengaluru and returns to Bengaluru. Therefore, the initial position and the final position are the same. This means the total displacement is zero. Total displacement = Final position - Initial position = Bengaluru - Bengaluru = 0 km. Total time taken = 2 hours. Average velocity = Total displacement \/ Total time = 0 km \/ 2 hours = 0 km\/hr. The magnitude of the average velocity is the absolute value of the average velocity, which is $|0| = 0$. - Average velocity is a vector quantity and depends on displacement, not total distance traveled. - Displacement is the shortest straight-line distance from the starting point to the ending point, along with direction. If the start and end points are the same, displacement is zero. - Average speed is a scalar quantity and depends on the total distance traveled divided by the total time. In this case, the average speed is 100 km \/ 2 hr = 50 km\/hr.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/a-car-starts-from-bengaluru-goes-50-km-in-a-straight-line-towards-sou\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/a-car-starts-from-bengaluru-goes-50-km-in-a-straight-line-towards-sou\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/a-car-starts-from-bengaluru-goes-50-km-in-a-straight-line-towards-sou\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC NDA-2","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-nda-2\/"},{"@type":"ListItem","position":3,"name":"A car starts from Bengaluru, goes 50 km in a straight line towards sou"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/88544","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=88544"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/88544\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=88544"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=88544"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=88544"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}