{"id":88418,"date":"2025-06-01T07:10:01","date_gmt":"2025-06-01T07:10:01","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=88418"},"modified":"2025-06-01T07:10:01","modified_gmt":"2025-06-01T07:10:01","slug":"consider-the-following-reaction-ch%e2%82%84-2o%e2%82%82-%e2%86%92-co%e2%82%82-2h%e2%82%82owhich-of-the-f","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-reaction-ch%e2%82%84-2o%e2%82%82-%e2%86%92-co%e2%82%82-2h%e2%82%82owhich-of-the-f\/","title":{"rendered":"Consider the following reaction: CH\u2084 + 2O\u2082 \u2192 CO\u2082 + 2H\u2082O\nWhich of the f"},"content":{"rendered":"<p>Consider the following reaction: CH\u2084 + 2O\u2082 \u2192 CO\u2082 + 2H\u2082O<br \/>\nWhich of the following about the reaction given above is\/are correct ?<\/p>\n<ul>\n<li>1. Carbon is oxidized.<\/li>\n<li>2. Hydrogen is oxidized.<\/li>\n<li>3. Hydrogen is reduced.<\/li>\n<li>4. Carbon is reduced.<\/li>\n<\/ul>\n<p>Select the correct answer using the code given below :<\/p>\n<p>[amp_mcq option1=&#8221;1 only&#8221; option2=&#8221;1 and 2 only&#8221; option3=&#8221;2 and 3 only&#8221; option4=&#8221;2 and 4 only&#8221; correct=&#8221;option1&#8243;]<\/p>\n<div class=\"psc-box-pyq-exam-year-detail\">\n<div class=\"pyq-exam\">\n<div class=\"psc-heading\">This question was previously asked in<\/div>\n<div class=\"psc-title line-ellipsis\">UPSC NDA-2 &#8211; 2017<\/div>\n<\/div>\n<div class=\"pyq-exam-psc-buttons\"><a href=\"\/pyq\/pyq-upsc-nda-2-2017.pdf\" target=\"_blank\" class=\"psc-pdf-button\" rel=\"noopener\">Download PDF<\/a><a href=\"\/pyq-upsc-nda-2-2017\" target=\"_blank\" class=\"psc-attempt-button\" rel=\"noopener\">Attempt Online<\/a><\/div>\n<\/div>\n<section id=\"pyq-correct-answer\">\nStatement 1 is correct: Carbon is oxidized. Statements 2, 3, and 4 are incorrect.<br \/>\n<\/section>\n<section id=\"pyq-key-points\">\nOxidation is the process where an atom or molecule loses electrons or increases its oxidation state. Reduction is the process where an atom or molecule gains electrons or decreases its oxidation state. In the given reaction (combustion of methane), let&#8217;s look at the oxidation states:<br \/>\n&#8211; In CH\u2084: Hydrogen is +1, so Carbon is -4 (since CH\u2084 is neutral).<br \/>\n&#8211; In O\u2082: Oxygen is 0 (elemental form).<br \/>\n&#8211; In CO\u2082: Oxygen is -2, so Carbon is +4 (since CO\u2082 is neutral).<br \/>\n&#8211; In H\u2082O: Hydrogen is +1, so Oxygen is -2 (since H\u2082O is neutral).<br \/>\nCarbon&#8217;s oxidation state changes from -4 to +4 (increase), so Carbon is oxidized.<br \/>\nHydrogen&#8217;s oxidation state remains +1 (no change), so Hydrogen is neither oxidized nor reduced.<br \/>\nOxygen&#8217;s oxidation state changes from 0 to -2 (decrease), so Oxygen is reduced.<br \/>\n<\/section>\n<section id=\"pyq-additional-information\">\nThis reaction is a classic example of a redox (reduction-oxidation) reaction. Methane (CH\u2084) acts as the reducing agent (gets oxidized), and Oxygen (O\u2082) acts as the oxidizing agent (gets reduced). Combustion reactions are typically redox reactions where a fuel is oxidized rapidly, usually releasing heat and light.<br \/>\n<\/section>\n","protected":false},"excerpt":{"rendered":"<p>Consider the following reaction: CH\u2084 + 2O\u2082 \u2192 CO\u2082 + 2H\u2082O Which of the following about the reaction given above is\/are correct ? 1. Carbon is oxidized. 2. Hydrogen is oxidized. 3. Hydrogen is reduced. 4. Carbon is reduced. Select the correct answer using the code given below : [amp_mcq option1=&#8221;1 only&#8221; option2=&#8221;1 and 2 &#8230; <\/p>\n<p class=\"read-more-container\"><a title=\"Consider the following reaction: CH\u2084 + 2O\u2082 \u2192 CO\u2082 + 2H\u2082O\nWhich of the f\" class=\"read-more button\" href=\"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-reaction-ch%e2%82%84-2o%e2%82%82-%e2%86%92-co%e2%82%82-2h%e2%82%82owhich-of-the-f\/#more-88418\">Detailed Solution<span class=\"screen-reader-text\">Consider the following reaction: CH\u2084 + 2O\u2082 \u2192 CO\u2082 + 2H\u2082O<br \/>\nWhich of the f<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1094],"tags":[1101,1096,1155],"class_list":["post-88418","post","type-post","status-publish","format-standard","hentry","category-upsc-nda-2","tag-1101","tag-chemistry","tag-physical-and-chemical-changes-solution","no-featured-image-padding"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Consider the following reaction: CH\u2084 + 2O\u2082 \u2192 CO\u2082 + 2H\u2082O Which of the f<\/title>\n<meta name=\"description\" content=\"Statement 1 is correct: Carbon is oxidized. Statements 2, 3, and 4 are incorrect. Oxidation is the process where an atom or molecule loses electrons or increases its oxidation state. Reduction is the process where an atom or molecule gains electrons or decreases its oxidation state. In the given reaction (combustion of methane), let&#039;s look at the oxidation states: - In CH\u2084: Hydrogen is +1, so Carbon is -4 (since CH\u2084 is neutral). - In O\u2082: Oxygen is 0 (elemental form). - In CO\u2082: Oxygen is -2, so Carbon is +4 (since CO\u2082 is neutral). - In H\u2082O: Hydrogen is +1, so Oxygen is -2 (since H\u2082O is neutral). Carbon&#039;s oxidation state changes from -4 to +4 (increase), so Carbon is oxidized. Hydrogen&#039;s oxidation state remains +1 (no change), so Hydrogen is neither oxidized nor reduced. Oxygen&#039;s oxidation state changes from 0 to -2 (decrease), so Oxygen is reduced.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-reaction-ch\u2084-2o\u2082-\u2192-co\u2082-2h\u2082owhich-of-the-f\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Consider the following reaction: CH\u2084 + 2O\u2082 \u2192 CO\u2082 + 2H\u2082O Which of the f\" \/>\n<meta property=\"og:description\" content=\"Statement 1 is correct: Carbon is oxidized. Statements 2, 3, and 4 are incorrect. Oxidation is the process where an atom or molecule loses electrons or increases its oxidation state. Reduction is the process where an atom or molecule gains electrons or decreases its oxidation state. In the given reaction (combustion of methane), let&#039;s look at the oxidation states: - In CH\u2084: Hydrogen is +1, so Carbon is -4 (since CH\u2084 is neutral). - In O\u2082: Oxygen is 0 (elemental form). - In CO\u2082: Oxygen is -2, so Carbon is +4 (since CO\u2082 is neutral). - In H\u2082O: Hydrogen is +1, so Oxygen is -2 (since H\u2082O is neutral). Carbon&#039;s oxidation state changes from -4 to +4 (increase), so Carbon is oxidized. Hydrogen&#039;s oxidation state remains +1 (no change), so Hydrogen is neither oxidized nor reduced. Oxygen&#039;s oxidation state changes from 0 to -2 (decrease), so Oxygen is reduced.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-reaction-ch\u2084-2o\u2082-\u2192-co\u2082-2h\u2082owhich-of-the-f\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T07:10:01+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"Consider the following reaction: CH\u2084 + 2O\u2082 \u2192 CO\u2082 + 2H\u2082O Which of the f","description":"Statement 1 is correct: Carbon is oxidized. Statements 2, 3, and 4 are incorrect. Oxidation is the process where an atom or molecule loses electrons or increases its oxidation state. Reduction is the process where an atom or molecule gains electrons or decreases its oxidation state. In the given reaction (combustion of methane), let's look at the oxidation states: - In CH\u2084: Hydrogen is +1, so Carbon is -4 (since CH\u2084 is neutral). - In O\u2082: Oxygen is 0 (elemental form). - In CO\u2082: Oxygen is -2, so Carbon is +4 (since CO\u2082 is neutral). - In H\u2082O: Hydrogen is +1, so Oxygen is -2 (since H\u2082O is neutral). Carbon's oxidation state changes from -4 to +4 (increase), so Carbon is oxidized. Hydrogen's oxidation state remains +1 (no change), so Hydrogen is neither oxidized nor reduced. Oxygen's oxidation state changes from 0 to -2 (decrease), so Oxygen is reduced.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-reaction-ch\u2084-2o\u2082-\u2192-co\u2082-2h\u2082owhich-of-the-f\/","og_locale":"en_US","og_type":"article","og_title":"Consider the following reaction: CH\u2084 + 2O\u2082 \u2192 CO\u2082 + 2H\u2082O Which of the f","og_description":"Statement 1 is correct: Carbon is oxidized. Statements 2, 3, and 4 are incorrect. Oxidation is the process where an atom or molecule loses electrons or increases its oxidation state. Reduction is the process where an atom or molecule gains electrons or decreases its oxidation state. In the given reaction (combustion of methane), let's look at the oxidation states: - In CH\u2084: Hydrogen is +1, so Carbon is -4 (since CH\u2084 is neutral). - In O\u2082: Oxygen is 0 (elemental form). - In CO\u2082: Oxygen is -2, so Carbon is +4 (since CO\u2082 is neutral). - In H\u2082O: Hydrogen is +1, so Oxygen is -2 (since H\u2082O is neutral). Carbon's oxidation state changes from -4 to +4 (increase), so Carbon is oxidized. Hydrogen's oxidation state remains +1 (no change), so Hydrogen is neither oxidized nor reduced. Oxygen's oxidation state changes from 0 to -2 (decrease), so Oxygen is reduced.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-reaction-ch\u2084-2o\u2082-\u2192-co\u2082-2h\u2082owhich-of-the-f\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T07:10:01+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-reaction-ch%e2%82%84-2o%e2%82%82-%e2%86%92-co%e2%82%82-2h%e2%82%82owhich-of-the-f\/","url":"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-reaction-ch%e2%82%84-2o%e2%82%82-%e2%86%92-co%e2%82%82-2h%e2%82%82owhich-of-the-f\/","name":"Consider the following reaction: CH\u2084 + 2O\u2082 \u2192 CO\u2082 + 2H\u2082O Which of the f","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T07:10:01+00:00","dateModified":"2025-06-01T07:10:01+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"Statement 1 is correct: Carbon is oxidized. Statements 2, 3, and 4 are incorrect. Oxidation is the process where an atom or molecule loses electrons or increases its oxidation state. Reduction is the process where an atom or molecule gains electrons or decreases its oxidation state. In the given reaction (combustion of methane), let's look at the oxidation states: - In CH\u2084: Hydrogen is +1, so Carbon is -4 (since CH\u2084 is neutral). - In O\u2082: Oxygen is 0 (elemental form). - In CO\u2082: Oxygen is -2, so Carbon is +4 (since CO\u2082 is neutral). - In H\u2082O: Hydrogen is +1, so Oxygen is -2 (since H\u2082O is neutral). Carbon's oxidation state changes from -4 to +4 (increase), so Carbon is oxidized. Hydrogen's oxidation state remains +1 (no change), so Hydrogen is neither oxidized nor reduced. Oxygen's oxidation state changes from 0 to -2 (decrease), so Oxygen is reduced.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-reaction-ch%e2%82%84-2o%e2%82%82-%e2%86%92-co%e2%82%82-2h%e2%82%82owhich-of-the-f\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-reaction-ch%e2%82%84-2o%e2%82%82-%e2%86%92-co%e2%82%82-2h%e2%82%82owhich-of-the-f\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-reaction-ch%e2%82%84-2o%e2%82%82-%e2%86%92-co%e2%82%82-2h%e2%82%82owhich-of-the-f\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC NDA-2","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-nda-2\/"},{"@type":"ListItem","position":3,"name":"Consider the following reaction: CH\u2084 + 2O\u2082 \u2192 CO\u2082 + 2H\u2082O Which of the f"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/88418","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=88418"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/88418\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=88418"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=88418"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=88418"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}