{"id":88252,"date":"2025-06-01T07:06:28","date_gmt":"2025-06-01T07:06:28","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=88252"},"modified":"2025-06-01T07:06:28","modified_gmt":"2025-06-01T07:06:28","slug":"a-ball-is-thrown-vertically-upward-from-the-ground-with-a-speed-of-25","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/a-ball-is-thrown-vertically-upward-from-the-ground-with-a-speed-of-25\/","title":{"rendered":"A ball is thrown vertically upward from the ground with a speed of 25-"},"content":{"rendered":"

A ball is thrown vertically upward from the ground with a speed of 25-2 m\/s. The ball will reach the highest point of its journey in<\/p>\n

[amp_mcq option1=”5\u00b714 s” option2=”3\u00b757 s” option3=”2\u00b757 s” option4=”1\u00b729 s” correct=”option3″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC NDA-2 – 2016<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nUsing the kinematic equation $v = u + at$, where $v$ is final velocity, $u$ is initial velocity, $a$ is acceleration, and $t$ is time.
\n<\/section>\n
\nGiven initial velocity $u = 25.2 \\text{ m\/s}$ upwards, and acceleration due to gravity $a = -9.8 \\text{ m\/s}^2$ (assuming upward is positive). At the highest point, the velocity $v = 0 \\text{ m\/s}$.
\n<\/section>\n
\nSubstituting the values into the equation: $0 = 25.2 + (-9.8)t$.
\nSolving for $t$: $9.8t = 25.2$, so $t = 25.2 \/ 9.8 = 252 \/ 98 = 126 \/ 49 = 18 \/ 7 \\approx 2.57$ seconds.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

A ball is thrown vertically upward from the ground with a speed of 25-2 m\/s. The ball will reach the highest point of its journey in [amp_mcq option1=”5\u00b714 s” option2=”3\u00b757 s” option3=”2\u00b757 s” option4=”1\u00b729 s” correct=”option3″] This question was previously asked in UPSC NDA-2 – 2016 Download PDFAttempt Online Using the kinematic equation $v = … <\/p>\n

Detailed SolutionA ball is thrown vertically upward from the ground with a speed of 25-<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1094],"tags":[1098,1421,1128],"class_list":["post-88252","post","type-post","status-publish","format-standard","hentry","category-upsc-nda-2","tag-1098","tag-motion-under-gravity","tag-physics","no-featured-image-padding"],"yoast_head":"\nA ball is thrown vertically upward from the ground with a speed of 25-<\/title>\n<meta name=\"description\" content=\"Using the kinematic equation $v = u + at$, where $v$ is final velocity, $u$ is initial velocity, $a$ is acceleration, and $t$ is time. Given initial velocity $u = 25.2 text{ m\/s}$ upwards, and acceleration due to gravity $a = -9.8 text{ m\/s}^2$ (assuming upward is positive). At the highest point, the velocity $v = 0 text{ m\/s}$.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/a-ball-is-thrown-vertically-upward-from-the-ground-with-a-speed-of-25\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"A ball is thrown vertically upward from the ground with a speed of 25-\" \/>\n<meta property=\"og:description\" content=\"Using the kinematic equation $v = u + at$, where $v$ is final velocity, $u$ is initial velocity, $a$ is acceleration, and $t$ is time. Given initial velocity $u = 25.2 text{ m\/s}$ upwards, and acceleration due to gravity $a = -9.8 text{ m\/s}^2$ (assuming upward is positive). At the highest point, the velocity $v = 0 text{ m\/s}$.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/a-ball-is-thrown-vertically-upward-from-the-ground-with-a-speed-of-25\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T07:06:28+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"A ball is thrown vertically upward from the ground with a speed of 25-","description":"Using the kinematic equation $v = u + at$, where $v$ is final velocity, $u$ is initial velocity, $a$ is acceleration, and $t$ is time. 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