{"id":88245,"date":"2025-06-01T07:06:20","date_gmt":"2025-06-01T07:06:20","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=88245"},"modified":"2025-06-01T07:06:20","modified_gmt":"2025-06-01T07:06:20","slug":"combination-of-one-volume-of-nitrogen-with-three-volumes-of-hydrogen","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/combination-of-one-volume-of-nitrogen-with-three-volumes-of-hydrogen\/","title":{"rendered":"Combination of one volume of nitrogen with three volumes of hydrogen"},"content":{"rendered":"

Combination of one volume of nitrogen with three volumes of hydrogen produces<\/p>\n

[amp_mcq option1=”one volume of ammonia” option2=”two volumes of ammonia” option3=”three volumes of ammonia” option4=”one and a half volumes of ammonia” correct=”option2″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC NDA-2 – 2016<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe reaction between nitrogen and hydrogen to produce ammonia is represented by the balanced chemical equation: N\u2082(g) + 3H\u2082(g) \u2192 2NH\u2083(g). According to Avogadro’s law, at the same temperature and pressure, the ratio of the volumes of reacting gases and gaseous products is equal to the ratio of their stoichiometric coefficients in the balanced equation. Thus, 1 volume of nitrogen reacts with 3 volumes of hydrogen to produce 2 volumes of ammonia.
\n<\/section>\n
\n– The balanced equation for the Haber process is N\u2082(g) + 3H\u2082(g) \u2192 2NH\u2083(g).
\n– The stoichiometric coefficients are 1 for N\u2082, 3 for H\u2082, and 2 for NH\u2083.
\n– At constant temperature and pressure, the volume ratio of reacting gases and gaseous products is equal to the mole ratio (and stoichiometric coefficient ratio).
\n<\/section>\n
\nThis principle relating volumes of reacting gases to their stoichiometric coefficients is known as Gay-Lussac’s law of combining volumes.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

Combination of one volume of nitrogen with three volumes of hydrogen produces [amp_mcq option1=”one volume of ammonia” option2=”two volumes of ammonia” option3=”three volumes of ammonia” option4=”one and a half volumes of ammonia” correct=”option2″] This question was previously asked in UPSC NDA-2 – 2016 Download PDFAttempt Online The reaction between nitrogen and hydrogen to produce ammonia … <\/p>\n

Detailed SolutionCombination of one volume of nitrogen with three volumes of hydrogen<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1094],"tags":[1098,1096,1239],"class_list":["post-88245","post","type-post","status-publish","format-standard","hentry","category-upsc-nda-2","tag-1098","tag-chemistry","tag-inorganic-chemistry","no-featured-image-padding"],"yoast_head":"\nCombination of one volume of nitrogen with three volumes of hydrogen<\/title>\n<meta name=\"description\" content=\"The reaction between nitrogen and hydrogen to produce ammonia is represented by the balanced chemical equation: N\u2082(g) + 3H\u2082(g) \u2192 2NH\u2083(g). According to Avogadro's law, at the same temperature and pressure, the ratio of the volumes of reacting gases and gaseous products is equal to the ratio of their stoichiometric coefficients in the balanced equation. Thus, 1 volume of nitrogen reacts with 3 volumes of hydrogen to produce 2 volumes of ammonia. - The balanced equation for the Haber process is N\u2082(g) + 3H\u2082(g) \u2192 2NH\u2083(g). - The stoichiometric coefficients are 1 for N\u2082, 3 for H\u2082, and 2 for NH\u2083. - At constant temperature and pressure, the volume ratio of reacting gases and gaseous products is equal to the mole ratio (and stoichiometric coefficient ratio).\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/combination-of-one-volume-of-nitrogen-with-three-volumes-of-hydrogen\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Combination of one volume of nitrogen with three volumes of hydrogen\" \/>\n<meta property=\"og:description\" content=\"The reaction between nitrogen and hydrogen to produce ammonia is represented by the balanced chemical equation: N\u2082(g) + 3H\u2082(g) \u2192 2NH\u2083(g). According to Avogadro's law, at the same temperature and pressure, the ratio of the volumes of reacting gases and gaseous products is equal to the ratio of their stoichiometric coefficients in the balanced equation. Thus, 1 volume of nitrogen reacts with 3 volumes of hydrogen to produce 2 volumes of ammonia. - The balanced equation for the Haber process is N\u2082(g) + 3H\u2082(g) \u2192 2NH\u2083(g). - The stoichiometric coefficients are 1 for N\u2082, 3 for H\u2082, and 2 for NH\u2083. - At constant temperature and pressure, the volume ratio of reacting gases and gaseous products is equal to the mole ratio (and stoichiometric coefficient ratio).\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/combination-of-one-volume-of-nitrogen-with-three-volumes-of-hydrogen\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T07:06:20+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"Combination of one volume of nitrogen with three volumes of hydrogen","description":"The reaction between nitrogen and hydrogen to produce ammonia is represented by the balanced chemical equation: N\u2082(g) + 3H\u2082(g) \u2192 2NH\u2083(g). According to Avogadro's law, at the same temperature and pressure, the ratio of the volumes of reacting gases and gaseous products is equal to the ratio of their stoichiometric coefficients in the balanced equation. Thus, 1 volume of nitrogen reacts with 3 volumes of hydrogen to produce 2 volumes of ammonia. - The balanced equation for the Haber process is N\u2082(g) + 3H\u2082(g) \u2192 2NH\u2083(g). - The stoichiometric coefficients are 1 for N\u2082, 3 for H\u2082, and 2 for NH\u2083. - At constant temperature and pressure, the volume ratio of reacting gases and gaseous products is equal to the mole ratio (and stoichiometric coefficient ratio).","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/combination-of-one-volume-of-nitrogen-with-three-volumes-of-hydrogen\/","og_locale":"en_US","og_type":"article","og_title":"Combination of one volume of nitrogen with three volumes of hydrogen","og_description":"The reaction between nitrogen and hydrogen to produce ammonia is represented by the balanced chemical equation: N\u2082(g) + 3H\u2082(g) \u2192 2NH\u2083(g). According to Avogadro's law, at the same temperature and pressure, the ratio of the volumes of reacting gases and gaseous products is equal to the ratio of their stoichiometric coefficients in the balanced equation. Thus, 1 volume of nitrogen reacts with 3 volumes of hydrogen to produce 2 volumes of ammonia. - The balanced equation for the Haber process is N\u2082(g) + 3H\u2082(g) \u2192 2NH\u2083(g). - The stoichiometric coefficients are 1 for N\u2082, 3 for H\u2082, and 2 for NH\u2083. - At constant temperature and pressure, the volume ratio of reacting gases and gaseous products is equal to the mole ratio (and stoichiometric coefficient ratio).","og_url":"https:\/\/exam.pscnotes.com\/mcq\/combination-of-one-volume-of-nitrogen-with-three-volumes-of-hydrogen\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T07:06:20+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/combination-of-one-volume-of-nitrogen-with-three-volumes-of-hydrogen\/","url":"https:\/\/exam.pscnotes.com\/mcq\/combination-of-one-volume-of-nitrogen-with-three-volumes-of-hydrogen\/","name":"Combination of one volume of nitrogen with three volumes of hydrogen","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T07:06:20+00:00","dateModified":"2025-06-01T07:06:20+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The reaction between nitrogen and hydrogen to produce ammonia is represented by the balanced chemical equation: N\u2082(g) + 3H\u2082(g) \u2192 2NH\u2083(g). According to Avogadro's law, at the same temperature and pressure, the ratio of the volumes of reacting gases and gaseous products is equal to the ratio of their stoichiometric coefficients in the balanced equation. Thus, 1 volume of nitrogen reacts with 3 volumes of hydrogen to produce 2 volumes of ammonia. - The balanced equation for the Haber process is N\u2082(g) + 3H\u2082(g) \u2192 2NH\u2083(g). - The stoichiometric coefficients are 1 for N\u2082, 3 for H\u2082, and 2 for NH\u2083. - At constant temperature and pressure, the volume ratio of reacting gases and gaseous products is equal to the mole ratio (and stoichiometric coefficient ratio).","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/combination-of-one-volume-of-nitrogen-with-three-volumes-of-hydrogen\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/combination-of-one-volume-of-nitrogen-with-three-volumes-of-hydrogen\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/combination-of-one-volume-of-nitrogen-with-three-volumes-of-hydrogen\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC NDA-2","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-nda-2\/"},{"@type":"ListItem","position":3,"name":"Combination of one volume of nitrogen with three volumes of hydrogen"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/88245","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=88245"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/88245\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=88245"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=88245"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=88245"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}