{"id":88184,"date":"2025-06-01T07:04:10","date_gmt":"2025-06-01T07:04:10","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=88184"},"modified":"2025-06-01T07:04:10","modified_gmt":"2025-06-01T07:04:10","slug":"the-acceleration-due-to-gravity-g-for-objects-on-or-near-the-surface","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/the-acceleration-due-to-gravity-g-for-objects-on-or-near-the-surface\/","title":{"rendered":"The acceleration due to gravity ‘g’ for objects on or near the surface"},"content":{"rendered":"

The acceleration due to gravity ‘g’ for objects on or near the surface of earth is related to the universal gravitational constant ‘G’ as (‘M’ is the mass of the earth and ‘R’ is its radius):<\/p>\n

[amp_mcq option1=”G = g $\\frac{\\text{M}}{\\text{R}^2}$” option2=”g = G $\\frac{\\text{M}}{\\text{R}^2}$” option3=”M = $\\frac{\\text{gG}}{\\text{R}^2}$” option4=”R = $\\frac{\\text{gG}}{\\text{M}^2}$” correct=”option2″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC NDA-2 – 2015<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe correct option is B, g = G $\\frac{\\text{M}}{\\text{R}^2}$.
\n<\/section>\n
\nThe acceleration due to gravity ‘g’ on the surface of the Earth is caused by the gravitational force exerted by the Earth on an object. According to Newton’s Law of Universal Gravitation, the force (F) between the Earth (mass M) and an object (mass m) on its surface (distance R from the center, where R is the Earth’s radius) is given by F = G $\\frac{\\text{Mm}}{\\text{R}^2}$, where G is the universal gravitational constant. This gravitational force is also the object’s weight, W, which is given by W = mg (by Newton’s second law, where ‘g’ is the acceleration due to this force). Equating the two expressions for the force (F = W), we get mg = G $\\frac{\\text{Mm}}{\\text{R}^2}$. Dividing both sides by the mass of the object ‘m’ gives the relationship for the acceleration due to gravity: g = G $\\frac{\\text{M}}{\\text{R}^2}$.
\n<\/section>\n
\nThis formula shows that the acceleration due to gravity ‘g’ is independent of the mass of the object itself and depends only on the mass and radius of the planet (or celestial body) and the universal gravitational constant G. The value of ‘g’ varies slightly across the Earth’s surface due to factors like altitude, latitude, and local geological variations.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

The acceleration due to gravity ‘g’ for objects on or near the surface of earth is related to the universal gravitational constant ‘G’ as (‘M’ is the mass of the earth and ‘R’ is its radius): [amp_mcq option1=”G = g $\\frac{\\text{M}}{\\text{R}^2}$” option2=”g = G $\\frac{\\text{M}}{\\text{R}^2}$” option3=”M = $\\frac{\\text{gG}}{\\text{R}^2}$” option4=”R = $\\frac{\\text{gG}}{\\text{M}^2}$” correct=”option2″] This question was … <\/p>\n

Detailed SolutionThe acceleration due to gravity ‘g’ for objects on or near the surface<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1094],"tags":[1443,1129,1128],"class_list":["post-88184","post","type-post","status-publish","format-standard","hentry","category-upsc-nda-2","tag-1443","tag-mechanics","tag-physics","no-featured-image-padding"],"yoast_head":"\nThe acceleration due to gravity 'g' for objects on or near the surface<\/title>\n<meta name=\"description\" content=\"The correct option is B, g = G $frac{text{M}}{text{R}^2}$. The acceleration due to gravity 'g' on the surface of the Earth is caused by the gravitational force exerted by the Earth on an object. According to Newton's Law of Universal Gravitation, the force (F) between the Earth (mass M) and an object (mass m) on its surface (distance R from the center, where R is the Earth's radius) is given by F = G $frac{text{Mm}}{text{R}^2}$, where G is the universal gravitational constant. This gravitational force is also the object's weight, W, which is given by W = mg (by Newton's second law, where 'g' is the acceleration due to this force). Equating the two expressions for the force (F = W), we get mg = G $frac{text{Mm}}{text{R}^2}$. Dividing both sides by the mass of the object 'm' gives the relationship for the acceleration due to gravity: g = G $frac{text{M}}{text{R}^2}$.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/the-acceleration-due-to-gravity-g-for-objects-on-or-near-the-surface\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"The acceleration due to gravity 'g' for objects on or near the surface\" \/>\n<meta property=\"og:description\" content=\"The correct option is B, g = G $frac{text{M}}{text{R}^2}$. The acceleration due to gravity 'g' on the surface of the Earth is caused by the gravitational force exerted by the Earth on an object. According to Newton's Law of Universal Gravitation, the force (F) between the Earth (mass M) and an object (mass m) on its surface (distance R from the center, where R is the Earth's radius) is given by F = G $frac{text{Mm}}{text{R}^2}$, where G is the universal gravitational constant. This gravitational force is also the object's weight, W, which is given by W = mg (by Newton's second law, where 'g' is the acceleration due to this force). Equating the two expressions for the force (F = W), we get mg = G $frac{text{Mm}}{text{R}^2}$. Dividing both sides by the mass of the object 'm' gives the relationship for the acceleration due to gravity: g = G $frac{text{M}}{text{R}^2}$.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/the-acceleration-due-to-gravity-g-for-objects-on-or-near-the-surface\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T07:04:10+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"2 minutes\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"The acceleration due to gravity 'g' for objects on or near the surface","description":"The correct option is B, g = G $frac{text{M}}{text{R}^2}$. The acceleration due to gravity 'g' on the surface of the Earth is caused by the gravitational force exerted by the Earth on an object. According to Newton's Law of Universal Gravitation, the force (F) between the Earth (mass M) and an object (mass m) on its surface (distance R from the center, where R is the Earth's radius) is given by F = G $frac{text{Mm}}{text{R}^2}$, where G is the universal gravitational constant. This gravitational force is also the object's weight, W, which is given by W = mg (by Newton's second law, where 'g' is the acceleration due to this force). Equating the two expressions for the force (F = W), we get mg = G $frac{text{Mm}}{text{R}^2}$. Dividing both sides by the mass of the object 'm' gives the relationship for the acceleration due to gravity: g = G $frac{text{M}}{text{R}^2}$.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/the-acceleration-due-to-gravity-g-for-objects-on-or-near-the-surface\/","og_locale":"en_US","og_type":"article","og_title":"The acceleration due to gravity 'g' for objects on or near the surface","og_description":"The correct option is B, g = G $frac{text{M}}{text{R}^2}$. The acceleration due to gravity 'g' on the surface of the Earth is caused by the gravitational force exerted by the Earth on an object. According to Newton's Law of Universal Gravitation, the force (F) between the Earth (mass M) and an object (mass m) on its surface (distance R from the center, where R is the Earth's radius) is given by F = G $frac{text{Mm}}{text{R}^2}$, where G is the universal gravitational constant. This gravitational force is also the object's weight, W, which is given by W = mg (by Newton's second law, where 'g' is the acceleration due to this force). Equating the two expressions for the force (F = W), we get mg = G $frac{text{Mm}}{text{R}^2}$. Dividing both sides by the mass of the object 'm' gives the relationship for the acceleration due to gravity: g = G $frac{text{M}}{text{R}^2}$.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/the-acceleration-due-to-gravity-g-for-objects-on-or-near-the-surface\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T07:04:10+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"2 minutes"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/the-acceleration-due-to-gravity-g-for-objects-on-or-near-the-surface\/","url":"https:\/\/exam.pscnotes.com\/mcq\/the-acceleration-due-to-gravity-g-for-objects-on-or-near-the-surface\/","name":"The acceleration due to gravity 'g' for objects on or near the surface","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T07:04:10+00:00","dateModified":"2025-06-01T07:04:10+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The correct option is B, g = G $\\frac{\\text{M}}{\\text{R}^2}$. The acceleration due to gravity 'g' on the surface of the Earth is caused by the gravitational force exerted by the Earth on an object. According to Newton's Law of Universal Gravitation, the force (F) between the Earth (mass M) and an object (mass m) on its surface (distance R from the center, where R is the Earth's radius) is given by F = G $\\frac{\\text{Mm}}{\\text{R}^2}$, where G is the universal gravitational constant. This gravitational force is also the object's weight, W, which is given by W = mg (by Newton's second law, where 'g' is the acceleration due to this force). Equating the two expressions for the force (F = W), we get mg = G $\\frac{\\text{Mm}}{\\text{R}^2}$. 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