{"id":88154,"date":"2025-06-01T07:03:33","date_gmt":"2025-06-01T07:03:33","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=88154"},"modified":"2025-06-01T07:03:33","modified_gmt":"2025-06-01T07:03:33","slug":"the-following-figure-represents-the-velocity-time-graph-of-a-moving-ca","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/the-following-figure-represents-the-velocity-time-graph-of-a-moving-ca\/","title":{"rendered":"The following figure represents the velocity-time graph of a moving ca"},"content":{"rendered":"<p>The following figure represents the velocity-time graph of a moving car on a road:<br \/>\nWhich segment of the graph represents the retardation?<\/p>\n<p>[amp_mcq option1=&#8221;AB&#8221; option2=&#8221;BC&#8221; option3=&#8221;CD&#8221; option4=&#8221;None&#8221; correct=&#8221;option3&#8243;]<\/p>\n<div class=\"psc-box-pyq-exam-year-detail\">\n<div class=\"pyq-exam\">\n<div class=\"psc-heading\">This question was previously asked in<\/div>\n<div class=\"psc-title line-ellipsis\">UPSC NDA-2 &#8211; 2015<\/div>\n<\/div>\n<div class=\"pyq-exam-psc-buttons\"><a href=\"\/pyq\/pyq-upsc-nda-2-2015.pdf\" target=\"_blank\" class=\"psc-pdf-button\" rel=\"noopener\">Download PDF<\/a><a href=\"\/pyq-upsc-nda-2-2015\" target=\"_blank\" class=\"psc-attempt-button\" rel=\"noopener\">Attempt Online<\/a><\/div>\n<\/div>\n<section id=\"pyq-correct-answer\">\nIn a velocity-time (v-t) graph, acceleration is represented by the slope of the graph. Retardation (or deceleration) occurs when the acceleration is in the opposite direction to the velocity, causing the object to slow down. This corresponds to a negative slope in the v-t graph, assuming positive velocity.<br \/>\n&#8211; Segment AB has a positive slope, indicating positive acceleration (velocity increasing).<br \/>\n&#8211; Segment BC is horizontal, indicating zero slope and thus zero acceleration (constant velocity).<br \/>\n&#8211; Segment CD has a negative slope, indicating negative acceleration. Since the velocity is positive during this segment, a negative acceleration means retardation or deceleration (velocity decreasing).<br \/>\n<\/section>\n<section id=\"pyq-key-points\">\nThe slope of a velocity-time graph represents acceleration. A negative slope indicates deceleration or retardation if the velocity is in the positive direction.<br \/>\n<\/section>\n<section id=\"pyq-additional-information\">\nIf the velocity were negative and the slope were positive, it would also represent slowing down (velocity increasing towards zero from a negative value). In this graph, velocity is positive throughout the plotted segments.<br \/>\n<\/section>\n","protected":false},"excerpt":{"rendered":"<p>The following figure represents the velocity-time graph of a moving car on a road: Which segment of the graph represents the retardation? [amp_mcq option1=&#8221;AB&#8221; option2=&#8221;BC&#8221; option3=&#8221;CD&#8221; option4=&#8221;None&#8221; correct=&#8221;option3&#8243;] This question was previously asked in UPSC NDA-2 &#8211; 2015 Download PDFAttempt Online In a velocity-time (v-t) graph, acceleration is represented by the slope of the graph. &#8230; <\/p>\n<p class=\"read-more-container\"><a title=\"The following figure represents the velocity-time graph of a moving ca\" class=\"read-more button\" href=\"https:\/\/exam.pscnotes.com\/mcq\/the-following-figure-represents-the-velocity-time-graph-of-a-moving-ca\/#more-88154\">Detailed Solution<span class=\"screen-reader-text\">The following figure represents the velocity-time graph of a moving ca<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1094],"tags":[1443,1129,1128],"class_list":["post-88154","post","type-post","status-publish","format-standard","hentry","category-upsc-nda-2","tag-1443","tag-mechanics","tag-physics","no-featured-image-padding"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>The following figure represents the velocity-time graph of a moving ca<\/title>\n<meta name=\"description\" content=\"In a velocity-time (v-t) graph, acceleration is represented by the slope of the graph. Retardation (or deceleration) occurs when the acceleration is in the opposite direction to the velocity, causing the object to slow down. This corresponds to a negative slope in the v-t graph, assuming positive velocity. - Segment AB has a positive slope, indicating positive acceleration (velocity increasing). - Segment BC is horizontal, indicating zero slope and thus zero acceleration (constant velocity). - Segment CD has a negative slope, indicating negative acceleration. Since the velocity is positive during this segment, a negative acceleration means retardation or deceleration (velocity decreasing). The slope of a velocity-time graph represents acceleration. A negative slope indicates deceleration or retardation if the velocity is in the positive direction.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/the-following-figure-represents-the-velocity-time-graph-of-a-moving-ca\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"The following figure represents the velocity-time graph of a moving ca\" \/>\n<meta property=\"og:description\" content=\"In a velocity-time (v-t) graph, acceleration is represented by the slope of the graph. Retardation (or deceleration) occurs when the acceleration is in the opposite direction to the velocity, causing the object to slow down. This corresponds to a negative slope in the v-t graph, assuming positive velocity. - Segment AB has a positive slope, indicating positive acceleration (velocity increasing). - Segment BC is horizontal, indicating zero slope and thus zero acceleration (constant velocity). - Segment CD has a negative slope, indicating negative acceleration. Since the velocity is positive during this segment, a negative acceleration means retardation or deceleration (velocity decreasing). The slope of a velocity-time graph represents acceleration. A negative slope indicates deceleration or retardation if the velocity is in the positive direction.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/the-following-figure-represents-the-velocity-time-graph-of-a-moving-ca\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T07:03:33+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"The following figure represents the velocity-time graph of a moving ca","description":"In a velocity-time (v-t) graph, acceleration is represented by the slope of the graph. Retardation (or deceleration) occurs when the acceleration is in the opposite direction to the velocity, causing the object to slow down. This corresponds to a negative slope in the v-t graph, assuming positive velocity. - Segment AB has a positive slope, indicating positive acceleration (velocity increasing). - Segment BC is horizontal, indicating zero slope and thus zero acceleration (constant velocity). - Segment CD has a negative slope, indicating negative acceleration. Since the velocity is positive during this segment, a negative acceleration means retardation or deceleration (velocity decreasing). The slope of a velocity-time graph represents acceleration. A negative slope indicates deceleration or retardation if the velocity is in the positive direction.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/the-following-figure-represents-the-velocity-time-graph-of-a-moving-ca\/","og_locale":"en_US","og_type":"article","og_title":"The following figure represents the velocity-time graph of a moving ca","og_description":"In a velocity-time (v-t) graph, acceleration is represented by the slope of the graph. Retardation (or deceleration) occurs when the acceleration is in the opposite direction to the velocity, causing the object to slow down. This corresponds to a negative slope in the v-t graph, assuming positive velocity. - Segment AB has a positive slope, indicating positive acceleration (velocity increasing). - Segment BC is horizontal, indicating zero slope and thus zero acceleration (constant velocity). - Segment CD has a negative slope, indicating negative acceleration. Since the velocity is positive during this segment, a negative acceleration means retardation or deceleration (velocity decreasing). The slope of a velocity-time graph represents acceleration. A negative slope indicates deceleration or retardation if the velocity is in the positive direction.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/the-following-figure-represents-the-velocity-time-graph-of-a-moving-ca\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T07:03:33+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/the-following-figure-represents-the-velocity-time-graph-of-a-moving-ca\/","url":"https:\/\/exam.pscnotes.com\/mcq\/the-following-figure-represents-the-velocity-time-graph-of-a-moving-ca\/","name":"The following figure represents the velocity-time graph of a moving ca","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T07:03:33+00:00","dateModified":"2025-06-01T07:03:33+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"In a velocity-time (v-t) graph, acceleration is represented by the slope of the graph. Retardation (or deceleration) occurs when the acceleration is in the opposite direction to the velocity, causing the object to slow down. This corresponds to a negative slope in the v-t graph, assuming positive velocity. - Segment AB has a positive slope, indicating positive acceleration (velocity increasing). - Segment BC is horizontal, indicating zero slope and thus zero acceleration (constant velocity). - Segment CD has a negative slope, indicating negative acceleration. Since the velocity is positive during this segment, a negative acceleration means retardation or deceleration (velocity decreasing). The slope of a velocity-time graph represents acceleration. A negative slope indicates deceleration or retardation if the velocity is in the positive direction.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/the-following-figure-represents-the-velocity-time-graph-of-a-moving-ca\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/the-following-figure-represents-the-velocity-time-graph-of-a-moving-ca\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/the-following-figure-represents-the-velocity-time-graph-of-a-moving-ca\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC NDA-2","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-nda-2\/"},{"@type":"ListItem","position":3,"name":"The following figure represents the velocity-time graph of a moving ca"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/88154","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=88154"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/88154\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=88154"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=88154"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=88154"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}