{"id":88106,"date":"2025-06-01T07:01:40","date_gmt":"2025-06-01T07:01:40","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=88106"},"modified":"2025-06-01T07:01:40","modified_gmt":"2025-06-01T07:01:40","slug":"consider-the-following-electric-circuit-circuit-diagram-is-present","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-electric-circuit-circuit-diagram-is-present\/","title":{"rendered":"Consider the following electric circuit :\n[Circuit diagram is present"},"content":{"rendered":"

Consider the following electric circuit :
\n[Circuit diagram is present in the image]
\nThe current in the above electric circuit is :<\/p>\n

[amp_mcq option1=”1 A” option2=”(10\/15) A” option3=”2 A” option4=”1.5 A” correct=”option2″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC NDA-1 – 2024<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
The current in the electric circuit is (10\/15) A.<\/section>\n
The circuit consists of a 10V battery connected to two resistors, 5 ohms and 10 ohms, in series. For resistors connected in series, the total resistance (R_total) is the sum of individual resistances. R_total = 5 \u03a9 + 10 \u03a9 = 15 \u03a9. According to Ohm’s Law, the current (I) flowing through the circuit is given by V = I * R_total, where V is the voltage. Therefore, I = V \/ R_total = 10 V \/ 15 \u03a9 = (10\/15) A.<\/section>\n
The fraction (10\/15) can be simplified to (2\/3) A. The options provide the unsimplified fraction (10\/15) A as option B. If the resistors were in parallel, the total resistance would be calculated differently (1\/R_total = 1\/R1 + 1\/R2).<\/section>\n","protected":false},"excerpt":{"rendered":"

Consider the following electric circuit : [Circuit diagram is present in the image] The current in the above electric circuit is : [amp_mcq option1=”1 A” option2=”(10\/15) A” option3=”2 A” option4=”1.5 A” correct=”option2″] This question was previously asked in UPSC NDA-1 – 2024 Download PDFAttempt Online The current in the electric circuit is (10\/15) A. The … <\/p>\n

Detailed SolutionConsider the following electric circuit :
\n[Circuit diagram is present<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1093],"tags":[1103,1201,1128],"class_list":["post-88106","post","type-post","status-publish","format-standard","hentry","category-upsc-nda-1","tag-1103","tag-electric-current","tag-physics","no-featured-image-padding"],"yoast_head":"\nConsider the following electric circuit : [Circuit diagram is present<\/title>\n<meta name=\"description\" content=\"The current in the electric circuit is (10\/15) A. The circuit consists of a 10V battery connected to two resistors, 5 ohms and 10 ohms, in series. For resistors connected in series, the total resistance (R_total) is the sum of individual resistances. R_total = 5 \u03a9 + 10 \u03a9 = 15 \u03a9. According to Ohm's Law, the current (I) flowing through the circuit is given by V = I * R_total, where V is the voltage. Therefore, I = V \/ R_total = 10 V \/ 15 \u03a9 = (10\/15) A.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-electric-circuit-circuit-diagram-is-present\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Consider the following electric circuit : [Circuit diagram is present\" \/>\n<meta property=\"og:description\" content=\"The current in the electric circuit is (10\/15) A. The circuit consists of a 10V battery connected to two resistors, 5 ohms and 10 ohms, in series. For resistors connected in series, the total resistance (R_total) is the sum of individual resistances. R_total = 5 \u03a9 + 10 \u03a9 = 15 \u03a9. According to Ohm's Law, the current (I) flowing through the circuit is given by V = I * R_total, where V is the voltage. Therefore, I = V \/ R_total = 10 V \/ 15 \u03a9 = (10\/15) A.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-electric-circuit-circuit-diagram-is-present\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T07:01:40+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"Consider the following electric circuit : [Circuit diagram is present","description":"The current in the electric circuit is (10\/15) A. The circuit consists of a 10V battery connected to two resistors, 5 ohms and 10 ohms, in series. For resistors connected in series, the total resistance (R_total) is the sum of individual resistances. R_total = 5 \u03a9 + 10 \u03a9 = 15 \u03a9. According to Ohm's Law, the current (I) flowing through the circuit is given by V = I * R_total, where V is the voltage. Therefore, I = V \/ R_total = 10 V \/ 15 \u03a9 = (10\/15) A.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-electric-circuit-circuit-diagram-is-present\/","og_locale":"en_US","og_type":"article","og_title":"Consider the following electric circuit : [Circuit diagram is present","og_description":"The current in the electric circuit is (10\/15) A. The circuit consists of a 10V battery connected to two resistors, 5 ohms and 10 ohms, in series. For resistors connected in series, the total resistance (R_total) is the sum of individual resistances. R_total = 5 \u03a9 + 10 \u03a9 = 15 \u03a9. According to Ohm's Law, the current (I) flowing through the circuit is given by V = I * R_total, where V is the voltage. Therefore, I = V \/ R_total = 10 V \/ 15 \u03a9 = (10\/15) A.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-electric-circuit-circuit-diagram-is-present\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T07:01:40+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-electric-circuit-circuit-diagram-is-present\/","url":"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-electric-circuit-circuit-diagram-is-present\/","name":"Consider the following electric circuit : [Circuit diagram is present","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T07:01:40+00:00","dateModified":"2025-06-01T07:01:40+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The current in the electric circuit is (10\/15) A. The circuit consists of a 10V battery connected to two resistors, 5 ohms and 10 ohms, in series. For resistors connected in series, the total resistance (R_total) is the sum of individual resistances. R_total = 5 \u03a9 + 10 \u03a9 = 15 \u03a9. According to Ohm's Law, the current (I) flowing through the circuit is given by V = I * R_total, where V is the voltage. 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