{"id":87931,"date":"2025-06-01T06:58:04","date_gmt":"2025-06-01T06:58:04","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=87931"},"modified":"2025-06-01T06:58:04","modified_gmt":"2025-06-01T06:58:04","slug":"a-stone-is-thrown-horizontally-from-the-top-of-a-20-m-high-building-wi","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/a-stone-is-thrown-horizontally-from-the-top-of-a-20-m-high-building-wi\/","title":{"rendered":"A stone is thrown horizontally from the top of a 20 m high building wi"},"content":{"rendered":"

A stone is thrown horizontally from the top of a 20 m high building with a speed of 12 m\/s. It hits the ground at a distance R from the building. Taking g = 10 m\/s\u00b2 and neglecting air resistance will give:<\/p>\n

[amp_mcq option1=”R=12m” option2=”R=18m” option3=”R=24m” option4=”R=30m” correct=”option3″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC NDA-1 – 2023<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe correct option is C.
\n<\/section>\n
\nFor projectile motion, the horizontal and vertical components of motion are independent (neglecting air resistance). The time it takes for the stone to hit the ground is determined by the vertical distance and the acceleration due to gravity. The horizontal distance (range) is then calculated by multiplying the horizontal velocity by the time of flight.
\n<\/section>\n
\nThe vertical motion is governed by $y = v_{y0}t + \\frac{1}{2}gt^2$. Since the stone is thrown horizontally, $v_{y0} = 0$. The height is $y = 20$ m and $g = 10$ m\/s\u00b2. So, $20 = 0 \\cdot t + \\frac{1}{2} \\cdot 10 \\cdot t^2 \\implies 20 = 5t^2 \\implies t^2 = 4 \\implies t = 2$ s (time of flight). The horizontal motion is uniform with velocity $v_x = 12$ m\/s. The range $R$ is given by $R = v_x \\cdot t = 12 \\text{ m\/s} \\cdot 2 \\text{ s} = 24$ m.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

A stone is thrown horizontally from the top of a 20 m high building with a speed of 12 m\/s. It hits the ground at a distance R from the building. Taking g = 10 m\/s\u00b2 and neglecting air resistance will give: [amp_mcq option1=”R=12m” option2=”R=18m” option3=”R=24m” option4=”R=30m” correct=”option3″] This question was previously asked in UPSC … <\/p>\n

Detailed SolutionA stone is thrown horizontally from the top of a 20 m high building wi<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1093],"tags":[1105,1421,1128],"class_list":["post-87931","post","type-post","status-publish","format-standard","hentry","category-upsc-nda-1","tag-1105","tag-motion-under-gravity","tag-physics","no-featured-image-padding"],"yoast_head":"\nA stone is thrown horizontally from the top of a 20 m high building wi<\/title>\n<meta name=\"description\" content=\"The correct option is C. For projectile motion, the horizontal and vertical components of motion are independent (neglecting air resistance). The time it takes for the stone to hit the ground is determined by the vertical distance and the acceleration due to gravity. The horizontal distance (range) is then calculated by multiplying the horizontal velocity by the time of flight.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/a-stone-is-thrown-horizontally-from-the-top-of-a-20-m-high-building-wi\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"A stone is thrown horizontally from the top of a 20 m high building wi\" \/>\n<meta property=\"og:description\" content=\"The correct option is C. For projectile motion, the horizontal and vertical components of motion are independent (neglecting air resistance). The time it takes for the stone to hit the ground is determined by the vertical distance and the acceleration due to gravity. The horizontal distance (range) is then calculated by multiplying the horizontal velocity by the time of flight.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/a-stone-is-thrown-horizontally-from-the-top-of-a-20-m-high-building-wi\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T06:58:04+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"A stone is thrown horizontally from the top of a 20 m high building wi","description":"The correct option is C. 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