{"id":87863,"date":"2025-06-01T06:55:46","date_gmt":"2025-06-01T06:55:46","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=87863"},"modified":"2025-06-01T06:55:46","modified_gmt":"2025-06-01T06:55:46","slug":"for-an-element-with-atomic-number-35-which-one-of-the-following-will","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/for-an-element-with-atomic-number-35-which-one-of-the-following-will\/","title":{"rendered":"For an element with atomic number 35, which one of the following will"},"content":{"rendered":"

For an element with atomic number 35, which one of the following will be the correct number of electrons in its valence shell based on Bohr’s model of an atom?<\/p>\n

[amp_mcq option1=”1″ option2=”3″ option3=”5″ option4=”7″ correct=”option4″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC NDA-1 – 2022<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe correct answer is 7. An element with atomic number 35 is Bromine (Br), which is a halogen in Group 17 of the periodic table and typically has 7 valence electrons.
\n<\/section>\n
\n– Bohr’s model describes electrons orbiting the nucleus in specific energy levels or shells (K, L, M, N, etc.).
\n– The maximum number of electrons a shell can hold is generally given by 2n\u00b2, where n is the shell number (n=1 for K, n=2 for L, etc.).
\n– For atomic number 35 (Bromine), we fill the shells sequentially:
\n – K shell (n=1): 2 electrons (capacity 2)
\n – L shell (n=2): 8 electrons (capacity 8)
\n – M shell (n=3): 18 electrons (capacity 18)
\n – N shell (n=4): The remaining electrons: 35 – (2 + 8 + 18) = 35 – 28 = 7 electrons.
\n– The outermost shell is the valence shell, which is the N shell in this case.
\n– The number of electrons in the valence shell is 7.
\n<\/section>\n
\nWhile the simple Bohr model doesn’t fully explain the filling order of electrons in multi-electron atoms due to subshells, the concept of valence electrons in the outermost shell is fundamental. Elements in the same group of the periodic table generally have the same number of valence electrons (e.g., Halogens in Group 17 all have 7 valence electrons), which determines their chemical properties.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

For an element with atomic number 35, which one of the following will be the correct number of electrons in its valence shell based on Bohr’s model of an atom? [amp_mcq option1=”1″ option2=”3″ option3=”5″ option4=”7″ correct=”option4″] This question was previously asked in UPSC NDA-1 – 2022 Download PDFAttempt Online The correct answer is 7. An … <\/p>\n

Detailed SolutionFor an element with atomic number 35, which one of the following will<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1093],"tags":[1108,1162,1096],"class_list":["post-87863","post","type-post","status-publish","format-standard","hentry","category-upsc-nda-1","tag-1108","tag-atomic-structure","tag-chemistry","no-featured-image-padding"],"yoast_head":"\nFor an element with atomic number 35, which one of the following will<\/title>\n<meta name=\"description\" content=\"The correct answer is 7. An element with atomic number 35 is Bromine (Br), which is a halogen in Group 17 of the periodic table and typically has 7 valence electrons. - Bohr's model describes electrons orbiting the nucleus in specific energy levels or shells (K, L, M, N, etc.). - The maximum number of electrons a shell can hold is generally given by 2n\u00b2, where n is the shell number (n=1 for K, n=2 for L, etc.). - For atomic number 35 (Bromine), we fill the shells sequentially: - K shell (n=1): 2 electrons (capacity 2) - L shell (n=2): 8 electrons (capacity 8) - M shell (n=3): 18 electrons (capacity 18) - N shell (n=4): The remaining electrons: 35 - (2 + 8 + 18) = 35 - 28 = 7 electrons. - The outermost shell is the valence shell, which is the N shell in this case. - The number of electrons in the valence shell is 7.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/for-an-element-with-atomic-number-35-which-one-of-the-following-will\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"For an element with atomic number 35, which one of the following will\" \/>\n<meta property=\"og:description\" content=\"The correct answer is 7. An element with atomic number 35 is Bromine (Br), which is a halogen in Group 17 of the periodic table and typically has 7 valence electrons. - Bohr's model describes electrons orbiting the nucleus in specific energy levels or shells (K, L, M, N, etc.). - The maximum number of electrons a shell can hold is generally given by 2n\u00b2, where n is the shell number (n=1 for K, n=2 for L, etc.). - For atomic number 35 (Bromine), we fill the shells sequentially: - K shell (n=1): 2 electrons (capacity 2) - L shell (n=2): 8 electrons (capacity 8) - M shell (n=3): 18 electrons (capacity 18) - N shell (n=4): The remaining electrons: 35 - (2 + 8 + 18) = 35 - 28 = 7 electrons. - The outermost shell is the valence shell, which is the N shell in this case. - The number of electrons in the valence shell is 7.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/for-an-element-with-atomic-number-35-which-one-of-the-following-will\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T06:55:46+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"For an element with atomic number 35, which one of the following will","description":"The correct answer is 7. An element with atomic number 35 is Bromine (Br), which is a halogen in Group 17 of the periodic table and typically has 7 valence electrons. - Bohr's model describes electrons orbiting the nucleus in specific energy levels or shells (K, L, M, N, etc.). - The maximum number of electrons a shell can hold is generally given by 2n\u00b2, where n is the shell number (n=1 for K, n=2 for L, etc.). - For atomic number 35 (Bromine), we fill the shells sequentially: - K shell (n=1): 2 electrons (capacity 2) - L shell (n=2): 8 electrons (capacity 8) - M shell (n=3): 18 electrons (capacity 18) - N shell (n=4): The remaining electrons: 35 - (2 + 8 + 18) = 35 - 28 = 7 electrons. - The outermost shell is the valence shell, which is the N shell in this case. - The number of electrons in the valence shell is 7.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/for-an-element-with-atomic-number-35-which-one-of-the-following-will\/","og_locale":"en_US","og_type":"article","og_title":"For an element with atomic number 35, which one of the following will","og_description":"The correct answer is 7. An element with atomic number 35 is Bromine (Br), which is a halogen in Group 17 of the periodic table and typically has 7 valence electrons. - Bohr's model describes electrons orbiting the nucleus in specific energy levels or shells (K, L, M, N, etc.). - The maximum number of electrons a shell can hold is generally given by 2n\u00b2, where n is the shell number (n=1 for K, n=2 for L, etc.). - For atomic number 35 (Bromine), we fill the shells sequentially: - K shell (n=1): 2 electrons (capacity 2) - L shell (n=2): 8 electrons (capacity 8) - M shell (n=3): 18 electrons (capacity 18) - N shell (n=4): The remaining electrons: 35 - (2 + 8 + 18) = 35 - 28 = 7 electrons. - The outermost shell is the valence shell, which is the N shell in this case. - The number of electrons in the valence shell is 7.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/for-an-element-with-atomic-number-35-which-one-of-the-following-will\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T06:55:46+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/for-an-element-with-atomic-number-35-which-one-of-the-following-will\/","url":"https:\/\/exam.pscnotes.com\/mcq\/for-an-element-with-atomic-number-35-which-one-of-the-following-will\/","name":"For an element with atomic number 35, which one of the following will","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T06:55:46+00:00","dateModified":"2025-06-01T06:55:46+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The correct answer is 7. An element with atomic number 35 is Bromine (Br), which is a halogen in Group 17 of the periodic table and typically has 7 valence electrons. - Bohr's model describes electrons orbiting the nucleus in specific energy levels or shells (K, L, M, N, etc.). - The maximum number of electrons a shell can hold is generally given by 2n\u00b2, where n is the shell number (n=1 for K, n=2 for L, etc.). - For atomic number 35 (Bromine), we fill the shells sequentially: - K shell (n=1): 2 electrons (capacity 2) - L shell (n=2): 8 electrons (capacity 8) - M shell (n=3): 18 electrons (capacity 18) - N shell (n=4): The remaining electrons: 35 - (2 + 8 + 18) = 35 - 28 = 7 electrons. - The outermost shell is the valence shell, which is the N shell in this case. - The number of electrons in the valence shell is 7.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/for-an-element-with-atomic-number-35-which-one-of-the-following-will\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/for-an-element-with-atomic-number-35-which-one-of-the-following-will\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/for-an-element-with-atomic-number-35-which-one-of-the-following-will\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC NDA-1","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-nda-1\/"},{"@type":"ListItem","position":3,"name":"For an element with atomic number 35, which one of the following will"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/87863","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=87863"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/87863\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=87863"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=87863"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=87863"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}