{"id":87846,"date":"2025-06-01T06:55:21","date_gmt":"2025-06-01T06:55:21","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=87846"},"modified":"2025-06-01T06:55:21","modified_gmt":"2025-06-01T06:55:21","slug":"the-magnetic-field-produced-by-a-current-carrying-straight-wire-at-a-p","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/the-magnetic-field-produced-by-a-current-carrying-straight-wire-at-a-p\/","title":{"rendered":"The magnetic field produced by a current-carrying straight wire at a p"},"content":{"rendered":"

The magnetic field produced by a current-carrying straight wire at a point outside the wire depends<\/p>\n

[amp_mcq option1=”inversely on the distance from it” option2=”directly on the distance from it” option3=”inversely at short distances and directly at large distances from it” option4=”directly on the distance (at short distances) and inversely on the distance (at long distances) from it” correct=”option1″]<\/p>\n

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UPSC NDA-1 – 2022<\/div>\n<\/div>\n
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\nThe magnetic field produced by a current-carrying straight wire at a point outside the wire depends inversely on the distance from it.
\n<\/section>\n
\nThe magnitude of the magnetic field ($B$) at a distance ($r$) from a long, straight conductor carrying current ($I$) is given by the formula $B = \\frac{\\mu_0 I}{2\\pi r}$, where $\\mu_0$ is the permeability of free space.
\n<\/section>\n
\nFrom the formula $B = \\frac{\\mu_0 I}{2\\pi r}$, it is clear that for a constant current $I$, the magnetic field strength $B$ is inversely proportional to the distance $r$ from the wire ($B \\propto \\frac{1}{r}$). This relationship holds true for points outside the wire.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

The magnetic field produced by a current-carrying straight wire at a point outside the wire depends [amp_mcq option1=”inversely on the distance from it” option2=”directly on the distance from it” option3=”inversely at short distances and directly at large distances from it” option4=”directly on the distance (at short distances) and inversely on the distance (at long distances) … <\/p>\n

Detailed SolutionThe magnetic field produced by a current-carrying straight wire at a p<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1093],"tags":[1108,1201,1128],"class_list":["post-87846","post","type-post","status-publish","format-standard","hentry","category-upsc-nda-1","tag-1108","tag-electric-current","tag-physics","no-featured-image-padding"],"yoast_head":"\nThe magnetic field produced by a current-carrying straight wire at a p<\/title>\n<meta name=\"description\" content=\"The magnetic field produced by a current-carrying straight wire at a point outside the wire depends inversely on the distance from it. The magnitude of the magnetic field ($B$) at a distance ($r$) from a long, straight conductor carrying current ($I$) is given by the formula $B = frac{mu_0 I}{2pi r}$, where $mu_0$ is the permeability of free space.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/the-magnetic-field-produced-by-a-current-carrying-straight-wire-at-a-p\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"The magnetic field produced by a current-carrying straight wire at a p\" \/>\n<meta property=\"og:description\" content=\"The magnetic field produced by a current-carrying straight wire at a point outside the wire depends inversely on the distance from it. The magnitude of the magnetic field ($B$) at a distance ($r$) from a long, straight conductor carrying current ($I$) is given by the formula $B = frac{mu_0 I}{2pi r}$, where $mu_0$ is the permeability of free space.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/the-magnetic-field-produced-by-a-current-carrying-straight-wire-at-a-p\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T06:55:21+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"The magnetic field produced by a current-carrying straight wire at a p","description":"The magnetic field produced by a current-carrying straight wire at a point outside the wire depends inversely on the distance from it. 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