{"id":87839,"date":"2025-06-01T06:55:13","date_gmt":"2025-06-01T06:55:13","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=87839"},"modified":"2025-06-01T06:55:13","modified_gmt":"2025-06-01T06:55:13","slug":"which-one-of-the-following-is-the-correct-molecular-formula-of-ammoniu","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-is-the-correct-molecular-formula-of-ammoniu\/","title":{"rendered":"Which one of the following is the correct molecular formula of ammoniu"},"content":{"rendered":"

Which one of the following is the correct molecular formula of ammonium carbonate if the valency of ammonium ion is (+1) and carbonate anion is (-2) ?<\/p>\n

[amp_mcq option1=”(NH\u2084)\u2082CO\u2083” option2=”NH\u2084(CO\u2083)\u2082” option3=”(NH\u2083)\u2082CO\u2083” option4=”NH\u2084CO\u2083” correct=”option1″]<\/p>\n

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This question was previously asked in<\/div>\n
UPSC NDA-1 – 2022<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nTo form a neutral compound, the total positive charge from the cations must balance the total negative charge from the anions. Given the valencies, the correct ratio of ammonium ions to carbonate ions needs to be determined.
\n<\/section>\n
\nThe valency (or charge) of the ammonium ion (NH\u2084\u207a) is +1. The valency (or charge) of the carbonate anion (CO\u2083\u00b2\u207b) is -2. To form a neutral compound, we need a total positive charge equal in magnitude to the total negative charge. If we take two ammonium ions, the total positive charge is 2 * (+1) = +2. If we take one carbonate ion, the total negative charge is 1 * (-2) = -2. The charges +2 and -2 balance to give a neutral compound. Therefore, the formula is (NH\u2084)\u2082CO\u2083, indicating two ammonium ions for every one carbonate ion.
\n<\/section>\n
\nWhen writing formulas for ionic compounds, the cation is written first, followed by the anion. Subscripts indicate the number of ions required to achieve charge neutrality. If the ion is polyatomic (like NH\u2084\u207a or CO\u2083\u00b2\u207b) and more than one is needed, the ion formula is enclosed in parentheses before the subscript.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

Which one of the following is the correct molecular formula of ammonium carbonate if the valency of ammonium ion is (+1) and carbonate anion is (-2) ? [amp_mcq option1=”(NH\u2084)\u2082CO\u2083” option2=”NH\u2084(CO\u2083)\u2082” option3=”(NH\u2083)\u2082CO\u2083” option4=”NH\u2084CO\u2083” correct=”option1″] This question was previously asked in UPSC NDA-1 – 2022 Download PDFAttempt Online To form a neutral compound, the total positive charge … <\/p>\n

Detailed SolutionWhich one of the following is the correct molecular formula of ammoniu<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1093],"tags":[1108,1096,1239],"class_list":["post-87839","post","type-post","status-publish","format-standard","hentry","category-upsc-nda-1","tag-1108","tag-chemistry","tag-inorganic-chemistry","no-featured-image-padding"],"yoast_head":"\nWhich one of the following is the correct molecular formula of ammoniu<\/title>\n<meta name=\"description\" content=\"To form a neutral compound, the total positive charge from the cations must balance the total negative charge from the anions. Given the valencies, the correct ratio of ammonium ions to carbonate ions needs to be determined. The valency (or charge) of the ammonium ion (NH\u2084\u207a) is +1. The valency (or charge) of the carbonate anion (CO\u2083\u00b2\u207b) is -2. To form a neutral compound, we need a total positive charge equal in magnitude to the total negative charge. If we take two ammonium ions, the total positive charge is 2 * (+1) = +2. If we take one carbonate ion, the total negative charge is 1 * (-2) = -2. The charges +2 and -2 balance to give a neutral compound. Therefore, the formula is (NH\u2084)\u2082CO\u2083, indicating two ammonium ions for every one carbonate ion.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-is-the-correct-molecular-formula-of-ammoniu\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Which one of the following is the correct molecular formula of ammoniu\" \/>\n<meta property=\"og:description\" content=\"To form a neutral compound, the total positive charge from the cations must balance the total negative charge from the anions. Given the valencies, the correct ratio of ammonium ions to carbonate ions needs to be determined. The valency (or charge) of the ammonium ion (NH\u2084\u207a) is +1. The valency (or charge) of the carbonate anion (CO\u2083\u00b2\u207b) is -2. To form a neutral compound, we need a total positive charge equal in magnitude to the total negative charge. If we take two ammonium ions, the total positive charge is 2 * (+1) = +2. If we take one carbonate ion, the total negative charge is 1 * (-2) = -2. The charges +2 and -2 balance to give a neutral compound. Therefore, the formula is (NH\u2084)\u2082CO\u2083, indicating two ammonium ions for every one carbonate ion.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-is-the-correct-molecular-formula-of-ammoniu\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T06:55:13+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"Which one of the following is the correct molecular formula of ammoniu","description":"To form a neutral compound, the total positive charge from the cations must balance the total negative charge from the anions. Given the valencies, the correct ratio of ammonium ions to carbonate ions needs to be determined. The valency (or charge) of the ammonium ion (NH\u2084\u207a) is +1. The valency (or charge) of the carbonate anion (CO\u2083\u00b2\u207b) is -2. To form a neutral compound, we need a total positive charge equal in magnitude to the total negative charge. If we take two ammonium ions, the total positive charge is 2 * (+1) = +2. If we take one carbonate ion, the total negative charge is 1 * (-2) = -2. The charges +2 and -2 balance to give a neutral compound. Therefore, the formula is (NH\u2084)\u2082CO\u2083, indicating two ammonium ions for every one carbonate ion.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-is-the-correct-molecular-formula-of-ammoniu\/","og_locale":"en_US","og_type":"article","og_title":"Which one of the following is the correct molecular formula of ammoniu","og_description":"To form a neutral compound, the total positive charge from the cations must balance the total negative charge from the anions. Given the valencies, the correct ratio of ammonium ions to carbonate ions needs to be determined. The valency (or charge) of the ammonium ion (NH\u2084\u207a) is +1. The valency (or charge) of the carbonate anion (CO\u2083\u00b2\u207b) is -2. To form a neutral compound, we need a total positive charge equal in magnitude to the total negative charge. If we take two ammonium ions, the total positive charge is 2 * (+1) = +2. If we take one carbonate ion, the total negative charge is 1 * (-2) = -2. The charges +2 and -2 balance to give a neutral compound. Therefore, the formula is (NH\u2084)\u2082CO\u2083, indicating two ammonium ions for every one carbonate ion.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-is-the-correct-molecular-formula-of-ammoniu\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T06:55:13+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-is-the-correct-molecular-formula-of-ammoniu\/","url":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-is-the-correct-molecular-formula-of-ammoniu\/","name":"Which one of the following is the correct molecular formula of ammoniu","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T06:55:13+00:00","dateModified":"2025-06-01T06:55:13+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"To form a neutral compound, the total positive charge from the cations must balance the total negative charge from the anions. Given the valencies, the correct ratio of ammonium ions to carbonate ions needs to be determined. The valency (or charge) of the ammonium ion (NH\u2084\u207a) is +1. The valency (or charge) of the carbonate anion (CO\u2083\u00b2\u207b) is -2. To form a neutral compound, we need a total positive charge equal in magnitude to the total negative charge. If we take two ammonium ions, the total positive charge is 2 * (+1) = +2. If we take one carbonate ion, the total negative charge is 1 * (-2) = -2. The charges +2 and -2 balance to give a neutral compound. Therefore, the formula is (NH\u2084)\u2082CO\u2083, indicating two ammonium ions for every one carbonate ion.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-is-the-correct-molecular-formula-of-ammoniu\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-is-the-correct-molecular-formula-of-ammoniu\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-is-the-correct-molecular-formula-of-ammoniu\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC NDA-1","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-nda-1\/"},{"@type":"ListItem","position":3,"name":"Which one of the following is the correct molecular formula of ammoniu"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/87839","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=87839"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/87839\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=87839"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=87839"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=87839"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}