{"id":87693,"date":"2025-06-01T06:51:23","date_gmt":"2025-06-01T06:51:23","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=87693"},"modified":"2025-06-01T06:51:23","modified_gmt":"2025-06-01T06:51:23","slug":"in-the-given-velocity-v-versus-time-t-graph-accelerated-and-decel","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/in-the-given-velocity-v-versus-time-t-graph-accelerated-and-decel\/","title":{"rendered":"In the given velocity (V) versus time (t) graph, accelerated and decel"},"content":{"rendered":"

In the given velocity (V) versus time (t) graph, accelerated and decelerated motions are respectively represented by line segments<\/p>\n

[amp_mcq option1=”CD and BC” option2=”BC and AB” option3=”CD and AB” option4=”AB and CD” correct=”option3″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC NDA-1 – 2019<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nIn a velocity-time graph, accelerated motion is represented by a line segment with a positive slope (velocity increasing with time), and decelerated motion (or retardation) is represented by a line segment with a negative slope (velocity decreasing with time).
\n<\/section>\n
\nLine segment CD has a positive slope, indicating that velocity is increasing with time, which is accelerated motion. Line segment AB has a negative slope, indicating that velocity is decreasing with time, which is decelerated motion.
\n<\/section>\n
\nLine segment BC represents motion with constant velocity, meaning zero acceleration. The question asks for accelerated motion followed by decelerated motion, which corresponds to segments CD and AB respectively.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

In the given velocity (V) versus time (t) graph, accelerated and decelerated motions are respectively represented by line segments [amp_mcq option1=”CD and BC” option2=”BC and AB” option3=”CD and AB” option4=”AB and CD” correct=”option3″] This question was previously asked in UPSC NDA-1 – 2019 Download PDFAttempt Online In a velocity-time graph, accelerated motion is represented by … <\/p>\n

Detailed SolutionIn the given velocity (V) versus time (t) graph, accelerated and decel<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1093],"tags":[1119,1129,1128],"class_list":["post-87693","post","type-post","status-publish","format-standard","hentry","category-upsc-nda-1","tag-1119","tag-mechanics","tag-physics","no-featured-image-padding"],"yoast_head":"\nIn the given velocity (V) versus time (t) graph, accelerated and decel<\/title>\n<meta name=\"description\" content=\"In a velocity-time graph, accelerated motion is represented by a line segment with a positive slope (velocity increasing with time), and decelerated motion (or retardation) is represented by a line segment with a negative slope (velocity decreasing with time). Line segment CD has a positive slope, indicating that velocity is increasing with time, which is accelerated motion. Line segment AB has a negative slope, indicating that velocity is decreasing with time, which is decelerated motion.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/in-the-given-velocity-v-versus-time-t-graph-accelerated-and-decel\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"In the given velocity (V) versus time (t) graph, accelerated and decel\" \/>\n<meta property=\"og:description\" content=\"In a velocity-time graph, accelerated motion is represented by a line segment with a positive slope (velocity increasing with time), and decelerated motion (or retardation) is represented by a line segment with a negative slope (velocity decreasing with time). Line segment CD has a positive slope, indicating that velocity is increasing with time, which is accelerated motion. 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