{"id":87691,"date":"2025-06-01T06:51:21","date_gmt":"2025-06-01T06:51:21","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=87691"},"modified":"2025-06-01T06:51:21","modified_gmt":"2025-06-01T06:51:21","slug":"the-figure-shown-above-gives-the-time-t-versus-position-x-graphs-o","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/the-figure-shown-above-gives-the-time-t-versus-position-x-graphs-o\/","title":{"rendered":"The figure shown above gives the time (t) versus position (x) graphs o"},"content":{"rendered":"

The figure shown above gives the time (t) versus position (x) graphs of three objects A, B and C. Which one of the following is the correct relation between their speeds $V_A$, $V_B$ and $V_C$, respectively at any instant (t > 0)?<\/p>\n

[amp_mcq option1=”$V_A < V_B < V_C$\" option2=\"$V_A > V_B > V_C$” option3=”$V_A = V_B = V_C \\ne 0$” option4=”$V_A = V_B = V_C = 0$” correct=”option2″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC NDA-1 – 2019<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe speeds of the three objects are represented by the slope of their position-time graphs. The correct relation between their speeds is $V_A > V_B > V_C$.
\n<\/section>\n
\n– In a position-time (x-t) graph, the velocity (speed if motion is in one direction without change in direction) is given by the slope of the graph ($\\Delta x \/ \\Delta t$).
\n– A steeper slope indicates a higher speed, and a less steep slope indicates a lower speed.
\n– Examining the graph, the line for object A has the steepest slope.
\n– The line for object B has a slope less steep than A but steeper than C.
\n– The line for object C has the least steep slope.
\n– Since all slopes are positive, the objects are moving in the positive direction. The magnitude of the slope represents the speed.
\n<\/section>\n
\nAll three graphs are straight lines, indicating that the objects are moving with constant velocities (uniform motion). If the lines were curved, the slope would change over time, indicating changing velocity (acceleration).
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

The figure shown above gives the time (t) versus position (x) graphs of three objects A, B and C. Which one of the following is the correct relation between their speeds $V_A$, $V_B$ and $V_C$, respectively at any instant (t > 0)? [amp_mcq option1=”$V_A < V_B < V_C$\" option2=\"$V_A > V_B > V_C$” option3=”$V_A = … <\/p>\n

Detailed SolutionThe figure shown above gives the time (t) versus position (x) graphs o<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1093],"tags":[1119,1129,1128],"class_list":["post-87691","post","type-post","status-publish","format-standard","hentry","category-upsc-nda-1","tag-1119","tag-mechanics","tag-physics","no-featured-image-padding"],"yoast_head":"\nThe figure shown above gives the time (t) versus position (x) graphs o<\/title>\n<meta name=\"description\" content=\"The speeds of the three objects are represented by the slope of their position-time graphs. The correct relation between their speeds is $V_A > V_B > V_C$. - In a position-time (x-t) graph, the velocity (speed if motion is in one direction without change in direction) is given by the slope of the graph ($Delta x \/ Delta t$). - A steeper slope indicates a higher speed, and a less steep slope indicates a lower speed. - Examining the graph, the line for object A has the steepest slope. - The line for object B has a slope less steep than A but steeper than C. - The line for object C has the least steep slope. - Since all slopes are positive, the objects are moving in the positive direction. The magnitude of the slope represents the speed.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/the-figure-shown-above-gives-the-time-t-versus-position-x-graphs-o\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"The figure shown above gives the time (t) versus position (x) graphs o\" \/>\n<meta property=\"og:description\" content=\"The speeds of the three objects are represented by the slope of their position-time graphs. The correct relation between their speeds is $V_A > V_B > V_C$. - In a position-time (x-t) graph, the velocity (speed if motion is in one direction without change in direction) is given by the slope of the graph ($Delta x \/ Delta t$). - A steeper slope indicates a higher speed, and a less steep slope indicates a lower speed. - Examining the graph, the line for object A has the steepest slope. - The line for object B has a slope less steep than A but steeper than C. - The line for object C has the least steep slope. - Since all slopes are positive, the objects are moving in the positive direction. 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