{"id":87508,"date":"2025-06-01T06:45:41","date_gmt":"2025-06-01T06:45:41","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=87508"},"modified":"2025-06-01T06:45:41","modified_gmt":"2025-06-01T06:45:41","slug":"a-kelvin-thermometer-and-a-fahrenheit-thermometer-both-give-the-same-r","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/a-kelvin-thermometer-and-a-fahrenheit-thermometer-both-give-the-same-r\/","title":{"rendered":"A Kelvin thermometer and a Fahrenheit thermometer both give the same r"},"content":{"rendered":"

A Kelvin thermometer and a Fahrenheit thermometer both give the same reading for a certain sample. What would be the corresponding reading in a Celsius thermometer?<\/p>\n

[amp_mcq option1=”574″ option2=”301″ option3=”273″ option4=”232″ correct=”option2″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC NDA-1 – 2017<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe question states that a Kelvin thermometer and a Fahrenheit thermometer give the same reading for a certain sample and asks for the corresponding reading in Celsius.
\n<\/section>\n
\nLet the reading on both the Kelvin and Fahrenheit scales be $x$.
\nThe conversion formula from Celsius ($T_C$) to Kelvin ($T_K$) is $T_K = T_C + 273.15$. For many problems, 273 is used as an approximation, but using 273.15 gives a more precise answer.
\nThe conversion formula from Celsius ($T_C$) to Fahrenheit ($T_F$) is $T_F = \\frac{9}{5} T_C + 32$.
\nWe are given $T_K = T_F = x$. So, we have two equations:
\n1) $x = T_C + 273.15$
\n2) $x = \\frac{9}{5} T_C + 32$
\nSet the two expressions for $x$ equal to each other:
\n$T_C + 273.15 = \\frac{9}{5} T_C + 32$
\n$273.15 – 32 = \\frac{9}{5} T_C – T_C$
\n$241.15 = (\\frac{9}{5} – 1) T_C$
\n$241.15 = (\\frac{9-5}{5}) T_C$
\n$241.15 = \\frac{4}{5} T_C$
\n$T_C = \\frac{241.15 \\times 5}{4} = \\frac{1205.75}{4} = 301.4375$
\nThe question asks for the reading in a Celsius thermometer. The calculated value is approximately 301.44. Among the given options, 301 is the closest value.
\n<\/section>\n
\nIf we use the approximation $T_K = T_C + 273$, the calculation becomes:
\n$T_C + 273 = \\frac{9}{5} T_C + 32$
\n$273 – 32 = \\frac{4}{5} T_C$
\n$241 = \\frac{4}{5} T_C$
\n$T_C = \\frac{241 \\times 5}{4} = \\frac{1205}{4} = 301.25$
\nThis value is also very close to 301. This confirms that 301 is the most likely intended answer, allowing for slight rounding or the use of an approximation in the original question setting.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

A Kelvin thermometer and a Fahrenheit thermometer both give the same reading for a certain sample. What would be the corresponding reading in a Celsius thermometer? [amp_mcq option1=”574″ option2=”301″ option3=”273″ option4=”232″ correct=”option2″] This question was previously asked in UPSC NDA-1 – 2017 Download PDFAttempt Online The question states that a Kelvin thermometer and a Fahrenheit … <\/p>\n

Detailed SolutionA Kelvin thermometer and a Fahrenheit thermometer both give the same r<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1093],"tags":[1101,1130,1128],"class_list":["post-87508","post","type-post","status-publish","format-standard","hentry","category-upsc-nda-1","tag-1101","tag-heat-and-thermodynamics","tag-physics","no-featured-image-padding"],"yoast_head":"\nA Kelvin thermometer and a Fahrenheit thermometer both give the same r<\/title>\n<meta name=\"description\" content=\"The question states that a Kelvin thermometer and a Fahrenheit thermometer give the same reading for a certain sample and asks for the corresponding reading in Celsius. Let the reading on both the Kelvin and Fahrenheit scales be $x$. The conversion formula from Celsius ($T_C$) to Kelvin ($T_K$) is $T_K = T_C + 273.15$. For many problems, 273 is used as an approximation, but using 273.15 gives a more precise answer. The conversion formula from Celsius ($T_C$) to Fahrenheit ($T_F$) is $T_F = frac{9}{5} T_C + 32$. We are given $T_K = T_F = x$. So, we have two equations: 1) $x = T_C + 273.15$ 2) $x = frac{9}{5} T_C + 32$ Set the two expressions for $x$ equal to each other: $T_C + 273.15 = frac{9}{5} T_C + 32$ $273.15 - 32 = frac{9}{5} T_C - T_C$ $241.15 = (frac{9}{5} - 1) T_C$ $241.15 = (frac{9-5}{5}) T_C$ $241.15 = frac{4}{5} T_C$ $T_C = frac{241.15 times 5}{4} = frac{1205.75}{4} = 301.4375$ The question asks for the reading in a Celsius thermometer. The calculated value is approximately 301.44. Among the given options, 301 is the closest value.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/a-kelvin-thermometer-and-a-fahrenheit-thermometer-both-give-the-same-r\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"A Kelvin thermometer and a Fahrenheit thermometer both give the same r\" \/>\n<meta property=\"og:description\" content=\"The question states that a Kelvin thermometer and a Fahrenheit thermometer give the same reading for a certain sample and asks for the corresponding reading in Celsius. Let the reading on both the Kelvin and Fahrenheit scales be $x$. The conversion formula from Celsius ($T_C$) to Kelvin ($T_K$) is $T_K = T_C + 273.15$. For many problems, 273 is used as an approximation, but using 273.15 gives a more precise answer. The conversion formula from Celsius ($T_C$) to Fahrenheit ($T_F$) is $T_F = frac{9}{5} T_C + 32$. We are given $T_K = T_F = x$. So, we have two equations: 1) $x = T_C + 273.15$ 2) $x = frac{9}{5} T_C + 32$ Set the two expressions for $x$ equal to each other: $T_C + 273.15 = frac{9}{5} T_C + 32$ $273.15 - 32 = frac{9}{5} T_C - T_C$ $241.15 = (frac{9}{5} - 1) T_C$ $241.15 = (frac{9-5}{5}) T_C$ $241.15 = frac{4}{5} T_C$ $T_C = frac{241.15 times 5}{4} = frac{1205.75}{4} = 301.4375$ The question asks for the reading in a Celsius thermometer. The calculated value is approximately 301.44. Among the given options, 301 is the closest value.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/a-kelvin-thermometer-and-a-fahrenheit-thermometer-both-give-the-same-r\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T06:45:41+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"A Kelvin thermometer and a Fahrenheit thermometer both give the same r","description":"The question states that a Kelvin thermometer and a Fahrenheit thermometer give the same reading for a certain sample and asks for the corresponding reading in Celsius. Let the reading on both the Kelvin and Fahrenheit scales be $x$. The conversion formula from Celsius ($T_C$) to Kelvin ($T_K$) is $T_K = T_C + 273.15$. For many problems, 273 is used as an approximation, but using 273.15 gives a more precise answer. The conversion formula from Celsius ($T_C$) to Fahrenheit ($T_F$) is $T_F = frac{9}{5} T_C + 32$. We are given $T_K = T_F = x$. So, we have two equations: 1) $x = T_C + 273.15$ 2) $x = frac{9}{5} T_C + 32$ Set the two expressions for $x$ equal to each other: $T_C + 273.15 = frac{9}{5} T_C + 32$ $273.15 - 32 = frac{9}{5} T_C - T_C$ $241.15 = (frac{9}{5} - 1) T_C$ $241.15 = (frac{9-5}{5}) T_C$ $241.15 = frac{4}{5} T_C$ $T_C = frac{241.15 times 5}{4} = frac{1205.75}{4} = 301.4375$ The question asks for the reading in a Celsius thermometer. The calculated value is approximately 301.44. Among the given options, 301 is the closest value.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/a-kelvin-thermometer-and-a-fahrenheit-thermometer-both-give-the-same-r\/","og_locale":"en_US","og_type":"article","og_title":"A Kelvin thermometer and a Fahrenheit thermometer both give the same r","og_description":"The question states that a Kelvin thermometer and a Fahrenheit thermometer give the same reading for a certain sample and asks for the corresponding reading in Celsius. Let the reading on both the Kelvin and Fahrenheit scales be $x$. The conversion formula from Celsius ($T_C$) to Kelvin ($T_K$) is $T_K = T_C + 273.15$. For many problems, 273 is used as an approximation, but using 273.15 gives a more precise answer. The conversion formula from Celsius ($T_C$) to Fahrenheit ($T_F$) is $T_F = frac{9}{5} T_C + 32$. We are given $T_K = T_F = x$. So, we have two equations: 1) $x = T_C + 273.15$ 2) $x = frac{9}{5} T_C + 32$ Set the two expressions for $x$ equal to each other: $T_C + 273.15 = frac{9}{5} T_C + 32$ $273.15 - 32 = frac{9}{5} T_C - T_C$ $241.15 = (frac{9}{5} - 1) T_C$ $241.15 = (frac{9-5}{5}) T_C$ $241.15 = frac{4}{5} T_C$ $T_C = frac{241.15 times 5}{4} = frac{1205.75}{4} = 301.4375$ The question asks for the reading in a Celsius thermometer. The calculated value is approximately 301.44. Among the given options, 301 is the closest value.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/a-kelvin-thermometer-and-a-fahrenheit-thermometer-both-give-the-same-r\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T06:45:41+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/a-kelvin-thermometer-and-a-fahrenheit-thermometer-both-give-the-same-r\/","url":"https:\/\/exam.pscnotes.com\/mcq\/a-kelvin-thermometer-and-a-fahrenheit-thermometer-both-give-the-same-r\/","name":"A Kelvin thermometer and a Fahrenheit thermometer both give the same r","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T06:45:41+00:00","dateModified":"2025-06-01T06:45:41+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The question states that a Kelvin thermometer and a Fahrenheit thermometer give the same reading for a certain sample and asks for the corresponding reading in Celsius. Let the reading on both the Kelvin and Fahrenheit scales be $x$. The conversion formula from Celsius ($T_C$) to Kelvin ($T_K$) is $T_K = T_C + 273.15$. For many problems, 273 is used as an approximation, but using 273.15 gives a more precise answer. The conversion formula from Celsius ($T_C$) to Fahrenheit ($T_F$) is $T_F = \\frac{9}{5} T_C + 32$. We are given $T_K = T_F = x$. So, we have two equations: 1) $x = T_C + 273.15$ 2) $x = \\frac{9}{5} T_C + 32$ Set the two expressions for $x$ equal to each other: $T_C + 273.15 = \\frac{9}{5} T_C + 32$ $273.15 - 32 = \\frac{9}{5} T_C - T_C$ $241.15 = (\\frac{9}{5} - 1) T_C$ $241.15 = (\\frac{9-5}{5}) T_C$ $241.15 = \\frac{4}{5} T_C$ $T_C = \\frac{241.15 \\times 5}{4} = \\frac{1205.75}{4} = 301.4375$ The question asks for the reading in a Celsius thermometer. The calculated value is approximately 301.44. Among the given options, 301 is the closest value.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/a-kelvin-thermometer-and-a-fahrenheit-thermometer-both-give-the-same-r\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/a-kelvin-thermometer-and-a-fahrenheit-thermometer-both-give-the-same-r\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/a-kelvin-thermometer-and-a-fahrenheit-thermometer-both-give-the-same-r\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC NDA-1","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-nda-1\/"},{"@type":"ListItem","position":3,"name":"A Kelvin thermometer and a Fahrenheit thermometer both give the same r"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/87508","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=87508"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/87508\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=87508"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=87508"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=87508"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}