{"id":87475,"date":"2025-06-01T06:44:55","date_gmt":"2025-06-01T06:44:55","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=87475"},"modified":"2025-06-01T06:44:55","modified_gmt":"2025-06-01T06:44:55","slug":"which-one-of-the-following-statements-is-correct-about-the-magnificati","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-statements-is-correct-about-the-magnificati\/","title":{"rendered":"Which one of the following statements is correct about the magnificati"},"content":{"rendered":"

Which one of the following statements is correct about the magnification of an optical microscope?<\/p>\n

[amp_mcq option1=”Magnification increases with the increase in focal length of eyepiece” option2=”Magnification increases with the increase in focal length of objective” option3=”Magnification does not depend upon the focal length of eyepiece” option4=”Magnification decreases with the increase in focal length of eyepiece” correct=”option4″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC NDA-1 – 2017<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe correct statement is that magnification decreases with the increase in focal length of eyepiece. The total magnification of an optical microscope is the product of the magnification of the objective lens and the magnification of the eyepiece.
\n<\/section>\n
\nThe magnification of the eyepiece (Me) is given by Me = D\/fe (when the final image is formed at infinity) or Me = 1 + D\/fe (when the final image is formed at the near point, D \u2248 25 cm). In both cases, Me is inversely proportional to the focal length of the eyepiece (fe). A larger fe results in a smaller Me. Similarly, the magnification of the objective lens (Mo) is approximately inversely proportional to its focal length (f\u2080). Mo \u2248 L\/f\u2080, where L is the tube length.
\n<\/section>\n
\nThe total magnification M = Mo * Me. Therefore, increasing the focal length of the eyepiece (fe) decreases the eyepiece magnification (Me), which in turn decreases the total magnification of the microscope. Similarly, increasing the focal length of the objective (f\u2080) decreases the objective magnification (Mo), also decreasing the total magnification.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

Which one of the following statements is correct about the magnification of an optical microscope? [amp_mcq option1=”Magnification increases with the increase in focal length of eyepiece” option2=”Magnification increases with the increase in focal length of objective” option3=”Magnification does not depend upon the focal length of eyepiece” option4=”Magnification decreases with the increase in focal length of … <\/p>\n

Detailed SolutionWhich one of the following statements is correct about the magnificati<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1093],"tags":[1101,1153,1128],"class_list":["post-87475","post","type-post","status-publish","format-standard","hentry","category-upsc-nda-1","tag-1101","tag-optics","tag-physics","no-featured-image-padding"],"yoast_head":"\nWhich one of the following statements is correct about the magnificati<\/title>\n<meta name=\"description\" content=\"The correct statement is that magnification decreases with the increase in focal length of eyepiece. The total magnification of an optical microscope is the product of the magnification of the objective lens and the magnification of the eyepiece. The magnification of the eyepiece (Me) is given by Me = D\/fe (when the final image is formed at infinity) or Me = 1 + D\/fe (when the final image is formed at the near point, D \u2248 25 cm). In both cases, Me is inversely proportional to the focal length of the eyepiece (fe). A larger fe results in a smaller Me. Similarly, the magnification of the objective lens (Mo) is approximately inversely proportional to its focal length (f\u2080). Mo \u2248 L\/f\u2080, where L is the tube length.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-statements-is-correct-about-the-magnificati\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Which one of the following statements is correct about the magnificati\" \/>\n<meta property=\"og:description\" content=\"The correct statement is that magnification decreases with the increase in focal length of eyepiece. The total magnification of an optical microscope is the product of the magnification of the objective lens and the magnification of the eyepiece. The magnification of the eyepiece (Me) is given by Me = D\/fe (when the final image is formed at infinity) or Me = 1 + D\/fe (when the final image is formed at the near point, D \u2248 25 cm). In both cases, Me is inversely proportional to the focal length of the eyepiece (fe). A larger fe results in a smaller Me. Similarly, the magnification of the objective lens (Mo) is approximately inversely proportional to its focal length (f\u2080). Mo \u2248 L\/f\u2080, where L is the tube length.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-statements-is-correct-about-the-magnificati\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T06:44:55+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"Which one of the following statements is correct about the magnificati","description":"The correct statement is that magnification decreases with the increase in focal length of eyepiece. The total magnification of an optical microscope is the product of the magnification of the objective lens and the magnification of the eyepiece. The magnification of the eyepiece (Me) is given by Me = D\/fe (when the final image is formed at infinity) or Me = 1 + D\/fe (when the final image is formed at the near point, D \u2248 25 cm). In both cases, Me is inversely proportional to the focal length of the eyepiece (fe). A larger fe results in a smaller Me. Similarly, the magnification of the objective lens (Mo) is approximately inversely proportional to its focal length (f\u2080). Mo \u2248 L\/f\u2080, where L is the tube length.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-statements-is-correct-about-the-magnificati\/","og_locale":"en_US","og_type":"article","og_title":"Which one of the following statements is correct about the magnificati","og_description":"The correct statement is that magnification decreases with the increase in focal length of eyepiece. The total magnification of an optical microscope is the product of the magnification of the objective lens and the magnification of the eyepiece. The magnification of the eyepiece (Me) is given by Me = D\/fe (when the final image is formed at infinity) or Me = 1 + D\/fe (when the final image is formed at the near point, D \u2248 25 cm). In both cases, Me is inversely proportional to the focal length of the eyepiece (fe). A larger fe results in a smaller Me. Similarly, the magnification of the objective lens (Mo) is approximately inversely proportional to its focal length (f\u2080). Mo \u2248 L\/f\u2080, where L is the tube length.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-statements-is-correct-about-the-magnificati\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T06:44:55+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-statements-is-correct-about-the-magnificati\/","url":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-statements-is-correct-about-the-magnificati\/","name":"Which one of the following statements is correct about the magnificati","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T06:44:55+00:00","dateModified":"2025-06-01T06:44:55+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The correct statement is that magnification decreases with the increase in focal length of eyepiece. The total magnification of an optical microscope is the product of the magnification of the objective lens and the magnification of the eyepiece. The magnification of the eyepiece (Me) is given by Me = D\/fe (when the final image is formed at infinity) or Me = 1 + D\/fe (when the final image is formed at the near point, D \u2248 25 cm). In both cases, Me is inversely proportional to the focal length of the eyepiece (fe). A larger fe results in a smaller Me. Similarly, the magnification of the objective lens (Mo) is approximately inversely proportional to its focal length (f\u2080). Mo \u2248 L\/f\u2080, where L is the tube length.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-statements-is-correct-about-the-magnificati\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-statements-is-correct-about-the-magnificati\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-statements-is-correct-about-the-magnificati\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC NDA-1","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-nda-1\/"},{"@type":"ListItem","position":3,"name":"Which one of the following statements is correct about the magnificati"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/87475","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=87475"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/87475\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=87475"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=87475"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=87475"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}