{"id":87441,"date":"2025-06-01T06:44:16","date_gmt":"2025-06-01T06:44:16","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=87441"},"modified":"2025-06-01T06:44:16","modified_gmt":"2025-06-01T06:44:16","slug":"the-speed-of-a-car-travelling-on-a-straight-road-is-listed-below-at-su","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/the-speed-of-a-car-travelling-on-a-straight-road-is-listed-below-at-su\/","title":{"rendered":"The speed of a car travelling on a straight road is listed below at su"},"content":{"rendered":"<p>The speed of a car travelling on a straight road is listed below at successive intervals of 1 s :<br \/>\n<br \/>\nTime (s) | 0 | 1 | 2 | 3 | 4<br \/>\n&#8212;&#8212;- | &#8211; | &#8211; | &#8211; | &#8211; | &#8211;<br \/>\nSpeed (m\/s) | 0 | 2 | 4 | 6 | 8<br \/>\n<br \/>\nWhich of the following is\/are correct? The car travels<\/p>\n<ul>\n<li>1. with a uniform acceleration of 2 m\/s\u00b2.<\/li>\n<li>2. 16 m in 4 s.<\/li>\n<li>3. with an average speed of 4 m\/s.<\/li>\n<\/ul>\n<p>Select the correct answer using the code given below :<\/p>\n<p>[amp_mcq option1=&#8221;1, 2 and 3&#8243; option2=&#8221;2 and 3 only&#8221; option3=&#8221;1 and 2 only&#8221; option4=&#8221;1 only&#8221; correct=&#8221;option1&#8243;]<\/p>\n<div class=\"psc-box-pyq-exam-year-detail\">\n<div class=\"pyq-exam\">\n<div class=\"psc-heading\">This question was previously asked in<\/div>\n<div class=\"psc-title line-ellipsis\">UPSC NDA-1 &#8211; 2017<\/div>\n<\/div>\n<div class=\"pyq-exam-psc-buttons\"><a href=\"\/pyq\/pyq-upsc-nda-1-2017.pdf\" target=\"_blank\" class=\"psc-pdf-button\" rel=\"noopener\">Download PDF<\/a><a href=\"\/pyq-upsc-nda-1-2017\" target=\"_blank\" class=\"psc-attempt-button\" rel=\"noopener\">Attempt Online<\/a><\/div>\n<\/div>\n<section id=\"pyq-correct-answer\">\nLet&#8217;s analyze each statement based on the given speed data:<br \/>\n1. with a uniform acceleration of 2 m\/s\u00b2: The speed increases by 2 m\/s every second (0 to 2, 2 to 4, 4 to 6, 6 to 8). Acceleration = change in speed \/ change in time = 2 m\/s \/ 1 s = 2 m\/s\u00b2. Since this value is constant, the acceleration is uniform. Statement 1 is correct.<br \/>\n2. 16 m in 4 s: Assuming the car starts from rest (speed = 0 at time = 0) and moves with uniform acceleration (a = 2 m\/s\u00b2), the distance covered in time t is given by s = ut + (1\/2)at\u00b2, where u is the initial speed (0 m\/s). For t = 4s, s = (0)(4) + (1\/2)(2)(4)\u00b2 = 0 + 1 * 16 = 16 m. Statement 2 is correct.<br \/>\n3. with an average speed of 4 m\/s: Average speed is total distance \/ total time. Total distance covered is 16 m (from statement 2) and total time is 4 s. Average speed = 16 m \/ 4 s = 4 m\/s. Statement 3 is correct.<br \/>\nAll three statements are correct.<br \/>\n<\/section>\n<section id=\"pyq-key-points\">\n&#8211; Uniform acceleration means the velocity changes by the same amount in equal intervals of time.<br \/>\n&#8211; For uniformly accelerated motion, cinematic equations can be used to calculate distance, speed, and time.<br \/>\n&#8211; Average speed is calculated as total distance traveled divided by the total time taken.<br \/>\n<\/section>\n<section id=\"pyq-additional-information\">\nIn uniformly accelerated motion starting from rest, the speed at time t is v = at, and the distance covered is s = (1\/2)at\u00b2. The average speed over a time interval is (initial speed + final speed) \/ 2 if acceleration is uniform. In this case, average speed over 4s is (0 + 8)\/2 = 4 m\/s, confirming statement 3.<br \/>\n<\/section>\n","protected":false},"excerpt":{"rendered":"<p>The speed of a car travelling on a straight road is listed below at successive intervals of 1 s : Time (s) | 0 | 1 | 2 | 3 | 4 &#8212;&#8212;- | &#8211; | &#8211; | &#8211; | &#8211; | &#8211; Speed (m\/s) | 0 | 2 | 4 | 6 | 8 &#8230; <\/p>\n<p class=\"read-more-container\"><a title=\"The speed of a car travelling on a straight road is listed below at su\" class=\"read-more button\" href=\"https:\/\/exam.pscnotes.com\/mcq\/the-speed-of-a-car-travelling-on-a-straight-road-is-listed-below-at-su\/#more-87441\">Detailed Solution<span class=\"screen-reader-text\">The speed of a car travelling on a straight road is listed below at su<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1093],"tags":[1101,1129,1128],"class_list":["post-87441","post","type-post","status-publish","format-standard","hentry","category-upsc-nda-1","tag-1101","tag-mechanics","tag-physics","no-featured-image-padding"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>The speed of a car travelling on a straight road is listed below at su<\/title>\n<meta name=\"description\" content=\"Let&#039;s analyze each statement based on the given speed data: 1. with a uniform acceleration of 2 m\/s\u00b2: The speed increases by 2 m\/s every second (0 to 2, 2 to 4, 4 to 6, 6 to 8). Acceleration = change in speed \/ change in time = 2 m\/s \/ 1 s = 2 m\/s\u00b2. Since this value is constant, the acceleration is uniform. Statement 1 is correct. 2. 16 m in 4 s: Assuming the car starts from rest (speed = 0 at time = 0) and moves with uniform acceleration (a = 2 m\/s\u00b2), the distance covered in time t is given by s = ut + (1\/2)at\u00b2, where u is the initial speed (0 m\/s). For t = 4s, s = (0)(4) + (1\/2)(2)(4)\u00b2 = 0 + 1 * 16 = 16 m. Statement 2 is correct. 3. with an average speed of 4 m\/s: Average speed is total distance \/ total time. Total distance covered is 16 m (from statement 2) and total time is 4 s. Average speed = 16 m \/ 4 s = 4 m\/s. Statement 3 is correct. All three statements are correct. - Uniform acceleration means the velocity changes by the same amount in equal intervals of time. - For uniformly accelerated motion, cinematic equations can be used to calculate distance, speed, and time. - Average speed is calculated as total distance traveled divided by the total time taken.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/the-speed-of-a-car-travelling-on-a-straight-road-is-listed-below-at-su\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"The speed of a car travelling on a straight road is listed below at su\" \/>\n<meta property=\"og:description\" content=\"Let&#039;s analyze each statement based on the given speed data: 1. with a uniform acceleration of 2 m\/s\u00b2: The speed increases by 2 m\/s every second (0 to 2, 2 to 4, 4 to 6, 6 to 8). Acceleration = change in speed \/ change in time = 2 m\/s \/ 1 s = 2 m\/s\u00b2. Since this value is constant, the acceleration is uniform. Statement 1 is correct. 2. 16 m in 4 s: Assuming the car starts from rest (speed = 0 at time = 0) and moves with uniform acceleration (a = 2 m\/s\u00b2), the distance covered in time t is given by s = ut + (1\/2)at\u00b2, where u is the initial speed (0 m\/s). For t = 4s, s = (0)(4) + (1\/2)(2)(4)\u00b2 = 0 + 1 * 16 = 16 m. Statement 2 is correct. 3. with an average speed of 4 m\/s: Average speed is total distance \/ total time. Total distance covered is 16 m (from statement 2) and total time is 4 s. Average speed = 16 m \/ 4 s = 4 m\/s. Statement 3 is correct. All three statements are correct. - Uniform acceleration means the velocity changes by the same amount in equal intervals of time. - For uniformly accelerated motion, cinematic equations can be used to calculate distance, speed, and time. - Average speed is calculated as total distance traveled divided by the total time taken.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/the-speed-of-a-car-travelling-on-a-straight-road-is-listed-below-at-su\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T06:44:16+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"2 minutes\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"The speed of a car travelling on a straight road is listed below at su","description":"Let's analyze each statement based on the given speed data: 1. with a uniform acceleration of 2 m\/s\u00b2: The speed increases by 2 m\/s every second (0 to 2, 2 to 4, 4 to 6, 6 to 8). Acceleration = change in speed \/ change in time = 2 m\/s \/ 1 s = 2 m\/s\u00b2. Since this value is constant, the acceleration is uniform. Statement 1 is correct. 2. 16 m in 4 s: Assuming the car starts from rest (speed = 0 at time = 0) and moves with uniform acceleration (a = 2 m\/s\u00b2), the distance covered in time t is given by s = ut + (1\/2)at\u00b2, where u is the initial speed (0 m\/s). For t = 4s, s = (0)(4) + (1\/2)(2)(4)\u00b2 = 0 + 1 * 16 = 16 m. Statement 2 is correct. 3. with an average speed of 4 m\/s: Average speed is total distance \/ total time. Total distance covered is 16 m (from statement 2) and total time is 4 s. Average speed = 16 m \/ 4 s = 4 m\/s. Statement 3 is correct. All three statements are correct. - Uniform acceleration means the velocity changes by the same amount in equal intervals of time. - For uniformly accelerated motion, cinematic equations can be used to calculate distance, speed, and time. - Average speed is calculated as total distance traveled divided by the total time taken.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/the-speed-of-a-car-travelling-on-a-straight-road-is-listed-below-at-su\/","og_locale":"en_US","og_type":"article","og_title":"The speed of a car travelling on a straight road is listed below at su","og_description":"Let's analyze each statement based on the given speed data: 1. with a uniform acceleration of 2 m\/s\u00b2: The speed increases by 2 m\/s every second (0 to 2, 2 to 4, 4 to 6, 6 to 8). Acceleration = change in speed \/ change in time = 2 m\/s \/ 1 s = 2 m\/s\u00b2. Since this value is constant, the acceleration is uniform. Statement 1 is correct. 2. 16 m in 4 s: Assuming the car starts from rest (speed = 0 at time = 0) and moves with uniform acceleration (a = 2 m\/s\u00b2), the distance covered in time t is given by s = ut + (1\/2)at\u00b2, where u is the initial speed (0 m\/s). For t = 4s, s = (0)(4) + (1\/2)(2)(4)\u00b2 = 0 + 1 * 16 = 16 m. Statement 2 is correct. 3. with an average speed of 4 m\/s: Average speed is total distance \/ total time. Total distance covered is 16 m (from statement 2) and total time is 4 s. Average speed = 16 m \/ 4 s = 4 m\/s. Statement 3 is correct. All three statements are correct. - Uniform acceleration means the velocity changes by the same amount in equal intervals of time. - For uniformly accelerated motion, cinematic equations can be used to calculate distance, speed, and time. - Average speed is calculated as total distance traveled divided by the total time taken.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/the-speed-of-a-car-travelling-on-a-straight-road-is-listed-below-at-su\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T06:44:16+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"2 minutes"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/the-speed-of-a-car-travelling-on-a-straight-road-is-listed-below-at-su\/","url":"https:\/\/exam.pscnotes.com\/mcq\/the-speed-of-a-car-travelling-on-a-straight-road-is-listed-below-at-su\/","name":"The speed of a car travelling on a straight road is listed below at su","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T06:44:16+00:00","dateModified":"2025-06-01T06:44:16+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"Let's analyze each statement based on the given speed data: 1. with a uniform acceleration of 2 m\/s\u00b2: The speed increases by 2 m\/s every second (0 to 2, 2 to 4, 4 to 6, 6 to 8). Acceleration = change in speed \/ change in time = 2 m\/s \/ 1 s = 2 m\/s\u00b2. Since this value is constant, the acceleration is uniform. Statement 1 is correct. 2. 16 m in 4 s: Assuming the car starts from rest (speed = 0 at time = 0) and moves with uniform acceleration (a = 2 m\/s\u00b2), the distance covered in time t is given by s = ut + (1\/2)at\u00b2, where u is the initial speed (0 m\/s). For t = 4s, s = (0)(4) + (1\/2)(2)(4)\u00b2 = 0 + 1 * 16 = 16 m. Statement 2 is correct. 3. with an average speed of 4 m\/s: Average speed is total distance \/ total time. Total distance covered is 16 m (from statement 2) and total time is 4 s. Average speed = 16 m \/ 4 s = 4 m\/s. Statement 3 is correct. All three statements are correct. - Uniform acceleration means the velocity changes by the same amount in equal intervals of time. - For uniformly accelerated motion, cinematic equations can be used to calculate distance, speed, and time. - Average speed is calculated as total distance traveled divided by the total time taken.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/the-speed-of-a-car-travelling-on-a-straight-road-is-listed-below-at-su\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/the-speed-of-a-car-travelling-on-a-straight-road-is-listed-below-at-su\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/the-speed-of-a-car-travelling-on-a-straight-road-is-listed-below-at-su\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC NDA-1","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-nda-1\/"},{"@type":"ListItem","position":3,"name":"The speed of a car travelling on a straight road is listed below at su"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/87441","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=87441"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/87441\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=87441"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=87441"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=87441"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}