{"id":87405,"date":"2025-06-01T06:42:31","date_gmt":"2025-06-01T06:42:31","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=87405"},"modified":"2025-06-01T06:42:31","modified_gmt":"2025-06-01T06:42:31","slug":"the-motion-of-a-car-along-a-straight-path-is-shown-by-the-following-fi","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/the-motion-of-a-car-along-a-straight-path-is-shown-by-the-following-fi\/","title":{"rendered":"The motion of a car along a straight path is shown by the following fi"},"content":{"rendered":"

The motion of a car along a straight path is shown by the following figure :
\n[Figure shows a line starting from O (0km) and points A (25km), B (35km), C (60km) along the path]
\nThe car starts from O and reaches at A, B and C at different instants of time. During its motion from O to C and back to B, the distance covered and the magnitude of the displacement are, respectively<\/p>\n

[amp_mcq option1=”25 km and 60 km” option2=”95 km and 35 km” option3=”60 km and 25 km” option4=”85 km and 35 km” correct=”option4″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC NDA-1 – 2016<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe correct answer is D) 85 km and 35 km.
\n<\/section>\n
\n– The car starts from O (0 km). It goes to C (60 km) and then comes back to B (35 km).
\n– Distance is the total path length covered. The car travels from O to C (60 km) and then from C back to B (60 km – 35 km = 25 km). Total distance covered = 60 km + 25 km = 85 km.
\n– Displacement is the straight-line distance and direction from the initial position to the final position. Initial position is O (0 km). Final position is B (35 km). The displacement is B – O = 35 km – 0 km = 35 km in the positive direction. The magnitude of displacement is 35 km.
\n<\/section>\n
\nDistance is a scalar quantity representing the total length of the path traveled. Displacement is a vector quantity representing the change in position from the starting point to the ending point. Its magnitude is the shortest distance between the initial and final points, and its direction is from initial to final.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

The motion of a car along a straight path is shown by the following figure : [Figure shows a line starting from O (0km) and points A (25km), B (35km), C (60km) along the path] The car starts from O and reaches at A, B and C at different instants of time. During its motion … <\/p>\n

Detailed SolutionThe motion of a car along a straight path is shown by the following fi<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1093],"tags":[1098,1129,1128],"class_list":["post-87405","post","type-post","status-publish","format-standard","hentry","category-upsc-nda-1","tag-1098","tag-mechanics","tag-physics","no-featured-image-padding"],"yoast_head":"\nThe motion of a car along a straight path is shown by the following fi<\/title>\n<meta name=\"description\" content=\"The correct answer is D) 85 km and 35 km. - The car starts from O (0 km). It goes to C (60 km) and then comes back to B (35 km). - Distance is the total path length covered. The car travels from O to C (60 km) and then from C back to B (60 km - 35 km = 25 km). Total distance covered = 60 km + 25 km = 85 km. - Displacement is the straight-line distance and direction from the initial position to the final position. Initial position is O (0 km). Final position is B (35 km). The displacement is B - O = 35 km - 0 km = 35 km in the positive direction. The magnitude of displacement is 35 km.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/the-motion-of-a-car-along-a-straight-path-is-shown-by-the-following-fi\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"The motion of a car along a straight path is shown by the following fi\" \/>\n<meta property=\"og:description\" content=\"The correct answer is D) 85 km and 35 km. - The car starts from O (0 km). It goes to C (60 km) and then comes back to B (35 km). - Distance is the total path length covered. The car travels from O to C (60 km) and then from C back to B (60 km - 35 km = 25 km). Total distance covered = 60 km + 25 km = 85 km. - Displacement is the straight-line distance and direction from the initial position to the final position. Initial position is O (0 km). Final position is B (35 km). The displacement is B - O = 35 km - 0 km = 35 km in the positive direction. The magnitude of displacement is 35 km.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/the-motion-of-a-car-along-a-straight-path-is-shown-by-the-following-fi\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T06:42:31+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"The motion of a car along a straight path is shown by the following fi","description":"The correct answer is D) 85 km and 35 km. - The car starts from O (0 km). It goes to C (60 km) and then comes back to B (35 km). - Distance is the total path length covered. The car travels from O to C (60 km) and then from C back to B (60 km - 35 km = 25 km). Total distance covered = 60 km + 25 km = 85 km. - Displacement is the straight-line distance and direction from the initial position to the final position. Initial position is O (0 km). Final position is B (35 km). The displacement is B - O = 35 km - 0 km = 35 km in the positive direction. The magnitude of displacement is 35 km.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/the-motion-of-a-car-along-a-straight-path-is-shown-by-the-following-fi\/","og_locale":"en_US","og_type":"article","og_title":"The motion of a car along a straight path is shown by the following fi","og_description":"The correct answer is D) 85 km and 35 km. - The car starts from O (0 km). It goes to C (60 km) and then comes back to B (35 km). - Distance is the total path length covered. The car travels from O to C (60 km) and then from C back to B (60 km - 35 km = 25 km). Total distance covered = 60 km + 25 km = 85 km. - Displacement is the straight-line distance and direction from the initial position to the final position. Initial position is O (0 km). Final position is B (35 km). The displacement is B - O = 35 km - 0 km = 35 km in the positive direction. The magnitude of displacement is 35 km.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/the-motion-of-a-car-along-a-straight-path-is-shown-by-the-following-fi\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T06:42:31+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/the-motion-of-a-car-along-a-straight-path-is-shown-by-the-following-fi\/","url":"https:\/\/exam.pscnotes.com\/mcq\/the-motion-of-a-car-along-a-straight-path-is-shown-by-the-following-fi\/","name":"The motion of a car along a straight path is shown by the following fi","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T06:42:31+00:00","dateModified":"2025-06-01T06:42:31+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The correct answer is D) 85 km and 35 km. - The car starts from O (0 km). It goes to C (60 km) and then comes back to B (35 km). - Distance is the total path length covered. The car travels from O to C (60 km) and then from C back to B (60 km - 35 km = 25 km). Total distance covered = 60 km + 25 km = 85 km. - Displacement is the straight-line distance and direction from the initial position to the final position. Initial position is O (0 km). Final position is B (35 km). The displacement is B - O = 35 km - 0 km = 35 km in the positive direction. The magnitude of displacement is 35 km.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/the-motion-of-a-car-along-a-straight-path-is-shown-by-the-following-fi\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/the-motion-of-a-car-along-a-straight-path-is-shown-by-the-following-fi\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/the-motion-of-a-car-along-a-straight-path-is-shown-by-the-following-fi\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC NDA-1","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-nda-1\/"},{"@type":"ListItem","position":3,"name":"The motion of a car along a straight path is shown by the following fi"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/87405","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=87405"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/87405\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=87405"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=87405"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=87405"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}