{"id":87401,"date":"2025-06-01T06:42:27","date_gmt":"2025-06-01T06:42:27","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=87401"},"modified":"2025-06-01T06:42:27","modified_gmt":"2025-06-01T06:42:27","slug":"the-impulse-on-a-particle-due-to-a-force-acting-on-it-during-a-given-t","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/the-impulse-on-a-particle-due-to-a-force-acting-on-it-during-a-given-t\/","title":{"rendered":"The impulse on a particle due to a force acting on it during a given t"},"content":{"rendered":"

The impulse on a particle due to a force acting on it during a given time interval is equal to the change in its<\/p>\n

[amp_mcq option1=”force” option2=”momentum” option3=”work done” option4=”energy” correct=”option2″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC NDA-1 – 2016<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe impulse on a particle due to a force acting on it during a given time interval is equal to the change in its momentum.
\n<\/section>\n
\nThis is a fundamental principle in physics known as the Impulse-Momentum Theorem. Impulse (J) is defined as the product of the force (F) and the time interval (\u0394t) over which the force acts (J = F\u0394t). Momentum (p) is the product of mass (m) and velocity (v) (p = mv). The theorem states that the impulse applied to an object is equal to the change in its momentum: J = \u0394p = mv_f – mv_i, where v_f is the final velocity and v_i is the initial velocity.
\n<\/section>\n
\nImpulse is a vector quantity, having the same direction as the force. The unit of impulse is Newton-second (N\u00b7s), which is equivalent to the unit of momentum, kilogram-meter per second (kg\u00b7m\/s). The Impulse-Momentum Theorem is derived from Newton’s second law of motion (F = ma = m * \u0394v\/\u0394t) rearranged as F\u0394t = m\u0394v.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

The impulse on a particle due to a force acting on it during a given time interval is equal to the change in its [amp_mcq option1=”force” option2=”momentum” option3=”work done” option4=”energy” correct=”option2″] This question was previously asked in UPSC NDA-1 – 2016 Download PDFAttempt Online The impulse on a particle due to a force acting on … <\/p>\n

Detailed SolutionThe impulse on a particle due to a force acting on it during a given t<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1093],"tags":[1098,1129,1128],"class_list":["post-87401","post","type-post","status-publish","format-standard","hentry","category-upsc-nda-1","tag-1098","tag-mechanics","tag-physics","no-featured-image-padding"],"yoast_head":"\nThe impulse on a particle due to a force acting on it during a given t<\/title>\n<meta name=\"description\" content=\"The impulse on a particle due to a force acting on it during a given time interval is equal to the change in its momentum. This is a fundamental principle in physics known as the Impulse-Momentum Theorem. Impulse (J) is defined as the product of the force (F) and the time interval (\u0394t) over which the force acts (J = F\u0394t). Momentum (p) is the product of mass (m) and velocity (v) (p = mv). The theorem states that the impulse applied to an object is equal to the change in its momentum: J = \u0394p = mv_f - mv_i, where v_f is the final velocity and v_i is the initial velocity.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/the-impulse-on-a-particle-due-to-a-force-acting-on-it-during-a-given-t\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"The impulse on a particle due to a force acting on it during a given t\" \/>\n<meta property=\"og:description\" content=\"The impulse on a particle due to a force acting on it during a given time interval is equal to the change in its momentum. This is a fundamental principle in physics known as the Impulse-Momentum Theorem. Impulse (J) is defined as the product of the force (F) and the time interval (\u0394t) over which the force acts (J = F\u0394t). Momentum (p) is the product of mass (m) and velocity (v) (p = mv). The theorem states that the impulse applied to an object is equal to the change in its momentum: J = \u0394p = mv_f - mv_i, where v_f is the final velocity and v_i is the initial velocity.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/the-impulse-on-a-particle-due-to-a-force-acting-on-it-during-a-given-t\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T06:42:27+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"The impulse on a particle due to a force acting on it during a given t","description":"The impulse on a particle due to a force acting on it during a given time interval is equal to the change in its momentum. 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The theorem states that the impulse applied to an object is equal to the change in its momentum: J = \u0394p = mv_f - mv_i, where v_f is the final velocity and v_i is the initial velocity.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/the-impulse-on-a-particle-due-to-a-force-acting-on-it-during-a-given-t\/","og_locale":"en_US","og_type":"article","og_title":"The impulse on a particle due to a force acting on it during a given t","og_description":"The impulse on a particle due to a force acting on it during a given time interval is equal to the change in its momentum. This is a fundamental principle in physics known as the Impulse-Momentum Theorem. Impulse (J) is defined as the product of the force (F) and the time interval (\u0394t) over which the force acts (J = F\u0394t). Momentum (p) is the product of mass (m) and velocity (v) (p = mv). The theorem states that the impulse applied to an object is equal to the change in its momentum: J = \u0394p = mv_f - mv_i, where v_f is the final velocity and v_i is the initial velocity.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/the-impulse-on-a-particle-due-to-a-force-acting-on-it-during-a-given-t\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T06:42:27+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/the-impulse-on-a-particle-due-to-a-force-acting-on-it-during-a-given-t\/","url":"https:\/\/exam.pscnotes.com\/mcq\/the-impulse-on-a-particle-due-to-a-force-acting-on-it-during-a-given-t\/","name":"The impulse on a particle due to a force acting on it during a given t","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T06:42:27+00:00","dateModified":"2025-06-01T06:42:27+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The impulse on a particle due to a force acting on it during a given time interval is equal to the change in its momentum. 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