{"id":87390,"date":"2025-06-01T06:42:14","date_gmt":"2025-06-01T06:42:14","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=87390"},"modified":"2025-06-01T06:42:14","modified_gmt":"2025-06-01T06:42:14","slug":"which-one-of-the-following-elements-will-not-react-with-dilute-hcl-to","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-elements-will-not-react-with-dilute-hcl-to\/","title":{"rendered":"Which one of the following elements will not react with dilute HCl to"},"content":{"rendered":"

Which one of the following elements will not react with dilute HCl to produce H2<\/sub> ?<\/p>\n

[amp_mcq option1=”Hg” option2=”Al” option3=”Mg” option4=”Fe” correct=”option1″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC NDA-1 – 2016<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe correct answer is A) Hg.
\n<\/section>\n
\nDilute HCl is a non-oxidizing acid. Metals that are more reactive than hydrogen will react with such acids to displace hydrogen gas (H\u2082). The reactivity of metals can be determined from the electrochemical series (or reactivity series). Metals above hydrogen in the series are more reactive and will displace hydrogen from dilute acids. Metals below hydrogen will not. The relevant part of the reactivity series is (from more reactive to less reactive): … Al > Zn > Fe > Pb > H > Cu > Hg > Ag > Au …
\n– Al, Mg, and Fe are all above hydrogen in the series, so they will react with dilute HCl to produce H\u2082 gas.
\n– Hg (Mercury) is below hydrogen in the series, so it will not react with dilute HCl to produce H\u2082 gas.
\n<\/section>\n
\nThe reaction of a reactive metal (M) with dilute HCl is typically represented as: M(s) + nHCl(aq) \u2192 MCl\u2099(aq) + n\/2 H\u2082(g), where ‘n’ is the valency of the metal in the chloride. For example, Mg(s) + 2HCl(aq) \u2192 MgCl\u2082(aq) + H\u2082(g). Metals below hydrogen can react with oxidizing acids (like concentrated nitric acid or hot concentrated sulfuric acid) but produce different products (e.g., oxides of nitrogen or sulfur dioxide) instead of hydrogen gas.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

Which one of the following elements will not react with dilute HCl to produce H2 ? [amp_mcq option1=”Hg” option2=”Al” option3=”Mg” option4=”Fe” correct=”option1″] This question was previously asked in UPSC NDA-1 – 2016 Download PDFAttempt Online The correct answer is A) Hg. Dilute HCl is a non-oxidizing acid. Metals that are more reactive than hydrogen will … <\/p>\n

Detailed SolutionWhich one of the following elements will not react with dilute HCl to<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1093],"tags":[1098,1096,1109],"class_list":["post-87390","post","type-post","status-publish","format-standard","hentry","category-upsc-nda-1","tag-1098","tag-chemistry","tag-metals-minerals-ores-properties-uses","no-featured-image-padding"],"yoast_head":"\nWhich one of the following elements will not react with dilute HCl to<\/title>\n<meta name=\"description\" content=\"The correct answer is A) Hg. Dilute HCl is a non-oxidizing acid. Metals that are more reactive than hydrogen will react with such acids to displace hydrogen gas (H\u2082). The reactivity of metals can be determined from the electrochemical series (or reactivity series). Metals above hydrogen in the series are more reactive and will displace hydrogen from dilute acids. Metals below hydrogen will not. The relevant part of the reactivity series is (from more reactive to less reactive): ... Al > Zn > Fe > Pb > H > Cu > Hg > Ag > Au ... - Al, Mg, and Fe are all above hydrogen in the series, so they will react with dilute HCl to produce H\u2082 gas. - Hg (Mercury) is below hydrogen in the series, so it will not react with dilute HCl to produce H\u2082 gas.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-elements-will-not-react-with-dilute-hcl-to\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Which one of the following elements will not react with dilute HCl to\" \/>\n<meta property=\"og:description\" content=\"The correct answer is A) Hg. Dilute HCl is a non-oxidizing acid. Metals that are more reactive than hydrogen will react with such acids to displace hydrogen gas (H\u2082). The reactivity of metals can be determined from the electrochemical series (or reactivity series). Metals above hydrogen in the series are more reactive and will displace hydrogen from dilute acids. Metals below hydrogen will not. The relevant part of the reactivity series is (from more reactive to less reactive): ... Al > Zn > Fe > Pb > H > Cu > Hg > Ag > Au ... - Al, Mg, and Fe are all above hydrogen in the series, so they will react with dilute HCl to produce H\u2082 gas. - Hg (Mercury) is below hydrogen in the series, so it will not react with dilute HCl to produce H\u2082 gas.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-elements-will-not-react-with-dilute-hcl-to\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T06:42:14+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"Which one of the following elements will not react with dilute HCl to","description":"The correct answer is A) Hg. Dilute HCl is a non-oxidizing acid. Metals that are more reactive than hydrogen will react with such acids to displace hydrogen gas (H\u2082). The reactivity of metals can be determined from the electrochemical series (or reactivity series). Metals above hydrogen in the series are more reactive and will displace hydrogen from dilute acids. Metals below hydrogen will not. The relevant part of the reactivity series is (from more reactive to less reactive): ... Al > Zn > Fe > Pb > H > Cu > Hg > Ag > Au ... - Al, Mg, and Fe are all above hydrogen in the series, so they will react with dilute HCl to produce H\u2082 gas. - Hg (Mercury) is below hydrogen in the series, so it will not react with dilute HCl to produce H\u2082 gas.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-elements-will-not-react-with-dilute-hcl-to\/","og_locale":"en_US","og_type":"article","og_title":"Which one of the following elements will not react with dilute HCl to","og_description":"The correct answer is A) Hg. Dilute HCl is a non-oxidizing acid. Metals that are more reactive than hydrogen will react with such acids to displace hydrogen gas (H\u2082). The reactivity of metals can be determined from the electrochemical series (or reactivity series). Metals above hydrogen in the series are more reactive and will displace hydrogen from dilute acids. Metals below hydrogen will not. The relevant part of the reactivity series is (from more reactive to less reactive): ... Al > Zn > Fe > Pb > H > Cu > Hg > Ag > Au ... - Al, Mg, and Fe are all above hydrogen in the series, so they will react with dilute HCl to produce H\u2082 gas. - Hg (Mercury) is below hydrogen in the series, so it will not react with dilute HCl to produce H\u2082 gas.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-elements-will-not-react-with-dilute-hcl-to\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T06:42:14+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-elements-will-not-react-with-dilute-hcl-to\/","url":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-elements-will-not-react-with-dilute-hcl-to\/","name":"Which one of the following elements will not react with dilute HCl to","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T06:42:14+00:00","dateModified":"2025-06-01T06:42:14+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The correct answer is A) Hg. Dilute HCl is a non-oxidizing acid. Metals that are more reactive than hydrogen will react with such acids to displace hydrogen gas (H\u2082). The reactivity of metals can be determined from the electrochemical series (or reactivity series). Metals above hydrogen in the series are more reactive and will displace hydrogen from dilute acids. Metals below hydrogen will not. The relevant part of the reactivity series is (from more reactive to less reactive): ... Al > Zn > Fe > Pb > H > Cu > Hg > Ag > Au ... - Al, Mg, and Fe are all above hydrogen in the series, so they will react with dilute HCl to produce H\u2082 gas. - Hg (Mercury) is below hydrogen in the series, so it will not react with dilute HCl to produce H\u2082 gas.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-elements-will-not-react-with-dilute-hcl-to\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-elements-will-not-react-with-dilute-hcl-to\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-elements-will-not-react-with-dilute-hcl-to\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC NDA-1","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-nda-1\/"},{"@type":"ListItem","position":3,"name":"Which one of the following elements will not react with dilute HCl to"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/87390","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=87390"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/87390\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=87390"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=87390"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=87390"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}