{"id":87381,"date":"2025-06-01T06:42:04","date_gmt":"2025-06-01T06:42:04","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=87381"},"modified":"2025-06-01T06:42:04","modified_gmt":"2025-06-01T06:42:04","slug":"three-resistors-with-magnitudes-2-4-and-8-ohm-are-connected-in-parall","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/three-resistors-with-magnitudes-2-4-and-8-ohm-are-connected-in-parall\/","title":{"rendered":"Three resistors with magnitudes 2, 4 and 8 ohm are connected in parall"},"content":{"rendered":"

Three resistors with magnitudes 2, 4 and 8 ohm are connected in parallel. The equivalent resistance of the system would be<\/p>\n

[amp_mcq option1=”less than 2 ohm” option2=”more than 2 ohm but less than 4 ohm” option3=”4 ohm” option4=”14 ohm” correct=”option1″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC NDA-1 – 2016<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe correct option is A.
\n<\/section>\n
\nWhen resistors are connected in parallel, the reciprocal of the equivalent resistance (Req) is equal to the sum of the reciprocals of the individual resistances.
\nGiven resistances are R\u2081 = 2 ohm, R\u2082 = 4 ohm, and R\u2083 = 8 ohm.
\nThe formula for equivalent resistance in parallel is:
\n1\/Req = 1\/R\u2081 + 1\/R\u2082 + 1\/R\u2083
\nSubstituting the values:
\n1\/Req = 1\/2 + 1\/4 + 1\/8
\nTo add these fractions, find a common denominator, which is 8:
\n1\/Req = 4\/8 + 2\/8 + 1\/8
\n1\/Req = (4 + 2 + 1) \/ 8
\n1\/Req = 7\/8
\nNow, take the reciprocal to find Req:
\nReq = 8\/7 ohm
\nTo compare this value with the options, calculate the decimal value: Req \u2248 1.14 ohm.
\nA key principle of parallel resistance is that the equivalent resistance is *always less than the smallest individual resistance* in the combination. In this case, the smallest resistance is 2 ohm, and 8\/7 ohm (approx 1.14 ohm) is indeed less than 2 ohm.
\n<\/section>\n
\nConnecting resistors in parallel provides multiple paths for the current to flow, effectively reducing the overall resistance of the circuit. Connecting resistors in series adds their resistances, resulting in a total resistance greater than any individual resistance.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

Three resistors with magnitudes 2, 4 and 8 ohm are connected in parallel. The equivalent resistance of the system would be [amp_mcq option1=”less than 2 ohm” option2=”more than 2 ohm but less than 4 ohm” option3=”4 ohm” option4=”14 ohm” correct=”option1″] This question was previously asked in UPSC NDA-1 – 2016 Download PDFAttempt Online The correct … <\/p>\n

Detailed SolutionThree resistors with magnitudes 2, 4 and 8 ohm are connected in parall<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1093],"tags":[1098,1201,1128],"class_list":["post-87381","post","type-post","status-publish","format-standard","hentry","category-upsc-nda-1","tag-1098","tag-electric-current","tag-physics","no-featured-image-padding"],"yoast_head":"\nThree resistors with magnitudes 2, 4 and 8 ohm are connected in parall<\/title>\n<meta name=\"description\" content=\"The correct option is A. When resistors are connected in parallel, the reciprocal of the equivalent resistance (Req) is equal to the sum of the reciprocals of the individual resistances. Given resistances are R\u2081 = 2 ohm, R\u2082 = 4 ohm, and R\u2083 = 8 ohm. The formula for equivalent resistance in parallel is: 1\/Req = 1\/R\u2081 + 1\/R\u2082 + 1\/R\u2083 Substituting the values: 1\/Req = 1\/2 + 1\/4 + 1\/8 To add these fractions, find a common denominator, which is 8: 1\/Req = 4\/8 + 2\/8 + 1\/8 1\/Req = (4 + 2 + 1) \/ 8 1\/Req = 7\/8 Now, take the reciprocal to find Req: Req = 8\/7 ohm To compare this value with the options, calculate the decimal value: Req \u2248 1.14 ohm. A key principle of parallel resistance is that the equivalent resistance is *always less than the smallest individual resistance* in the combination. In this case, the smallest resistance is 2 ohm, and 8\/7 ohm (approx 1.14 ohm) is indeed less than 2 ohm.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/three-resistors-with-magnitudes-2-4-and-8-ohm-are-connected-in-parall\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Three resistors with magnitudes 2, 4 and 8 ohm are connected in parall\" \/>\n<meta property=\"og:description\" content=\"The correct option is A. When resistors are connected in parallel, the reciprocal of the equivalent resistance (Req) is equal to the sum of the reciprocals of the individual resistances. Given resistances are R\u2081 = 2 ohm, R\u2082 = 4 ohm, and R\u2083 = 8 ohm. The formula for equivalent resistance in parallel is: 1\/Req = 1\/R\u2081 + 1\/R\u2082 + 1\/R\u2083 Substituting the values: 1\/Req = 1\/2 + 1\/4 + 1\/8 To add these fractions, find a common denominator, which is 8: 1\/Req = 4\/8 + 2\/8 + 1\/8 1\/Req = (4 + 2 + 1) \/ 8 1\/Req = 7\/8 Now, take the reciprocal to find Req: Req = 8\/7 ohm To compare this value with the options, calculate the decimal value: Req \u2248 1.14 ohm. A key principle of parallel resistance is that the equivalent resistance is *always less than the smallest individual resistance* in the combination. In this case, the smallest resistance is 2 ohm, and 8\/7 ohm (approx 1.14 ohm) is indeed less than 2 ohm.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/three-resistors-with-magnitudes-2-4-and-8-ohm-are-connected-in-parall\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T06:42:04+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"Three resistors with magnitudes 2, 4 and 8 ohm are connected in parall","description":"The correct option is A. When resistors are connected in parallel, the reciprocal of the equivalent resistance (Req) is equal to the sum of the reciprocals of the individual resistances. Given resistances are R\u2081 = 2 ohm, R\u2082 = 4 ohm, and R\u2083 = 8 ohm. The formula for equivalent resistance in parallel is: 1\/Req = 1\/R\u2081 + 1\/R\u2082 + 1\/R\u2083 Substituting the values: 1\/Req = 1\/2 + 1\/4 + 1\/8 To add these fractions, find a common denominator, which is 8: 1\/Req = 4\/8 + 2\/8 + 1\/8 1\/Req = (4 + 2 + 1) \/ 8 1\/Req = 7\/8 Now, take the reciprocal to find Req: Req = 8\/7 ohm To compare this value with the options, calculate the decimal value: Req \u2248 1.14 ohm. A key principle of parallel resistance is that the equivalent resistance is *always less than the smallest individual resistance* in the combination. In this case, the smallest resistance is 2 ohm, and 8\/7 ohm (approx 1.14 ohm) is indeed less than 2 ohm.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/three-resistors-with-magnitudes-2-4-and-8-ohm-are-connected-in-parall\/","og_locale":"en_US","og_type":"article","og_title":"Three resistors with magnitudes 2, 4 and 8 ohm are connected in parall","og_description":"The correct option is A. When resistors are connected in parallel, the reciprocal of the equivalent resistance (Req) is equal to the sum of the reciprocals of the individual resistances. Given resistances are R\u2081 = 2 ohm, R\u2082 = 4 ohm, and R\u2083 = 8 ohm. The formula for equivalent resistance in parallel is: 1\/Req = 1\/R\u2081 + 1\/R\u2082 + 1\/R\u2083 Substituting the values: 1\/Req = 1\/2 + 1\/4 + 1\/8 To add these fractions, find a common denominator, which is 8: 1\/Req = 4\/8 + 2\/8 + 1\/8 1\/Req = (4 + 2 + 1) \/ 8 1\/Req = 7\/8 Now, take the reciprocal to find Req: Req = 8\/7 ohm To compare this value with the options, calculate the decimal value: Req \u2248 1.14 ohm. A key principle of parallel resistance is that the equivalent resistance is *always less than the smallest individual resistance* in the combination. In this case, the smallest resistance is 2 ohm, and 8\/7 ohm (approx 1.14 ohm) is indeed less than 2 ohm.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/three-resistors-with-magnitudes-2-4-and-8-ohm-are-connected-in-parall\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T06:42:04+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/three-resistors-with-magnitudes-2-4-and-8-ohm-are-connected-in-parall\/","url":"https:\/\/exam.pscnotes.com\/mcq\/three-resistors-with-magnitudes-2-4-and-8-ohm-are-connected-in-parall\/","name":"Three resistors with magnitudes 2, 4 and 8 ohm are connected in parall","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T06:42:04+00:00","dateModified":"2025-06-01T06:42:04+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The correct option is A. When resistors are connected in parallel, the reciprocal of the equivalent resistance (Req) is equal to the sum of the reciprocals of the individual resistances. Given resistances are R\u2081 = 2 ohm, R\u2082 = 4 ohm, and R\u2083 = 8 ohm. The formula for equivalent resistance in parallel is: 1\/Req = 1\/R\u2081 + 1\/R\u2082 + 1\/R\u2083 Substituting the values: 1\/Req = 1\/2 + 1\/4 + 1\/8 To add these fractions, find a common denominator, which is 8: 1\/Req = 4\/8 + 2\/8 + 1\/8 1\/Req = (4 + 2 + 1) \/ 8 1\/Req = 7\/8 Now, take the reciprocal to find Req: Req = 8\/7 ohm To compare this value with the options, calculate the decimal value: Req \u2248 1.14 ohm. A key principle of parallel resistance is that the equivalent resistance is *always less than the smallest individual resistance* in the combination. In this case, the smallest resistance is 2 ohm, and 8\/7 ohm (approx 1.14 ohm) is indeed less than 2 ohm.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/three-resistors-with-magnitudes-2-4-and-8-ohm-are-connected-in-parall\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/three-resistors-with-magnitudes-2-4-and-8-ohm-are-connected-in-parall\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/three-resistors-with-magnitudes-2-4-and-8-ohm-are-connected-in-parall\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC NDA-1","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-nda-1\/"},{"@type":"ListItem","position":3,"name":"Three resistors with magnitudes 2, 4 and 8 ohm are connected in parall"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/87381","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=87381"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/87381\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=87381"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=87381"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=87381"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}