{"id":87380,"date":"2025-06-01T06:42:03","date_gmt":"2025-06-01T06:42:03","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=87380"},"modified":"2025-06-01T06:42:03","modified_gmt":"2025-06-01T06:42:03","slug":"a-simple-circuit-contains-a-12-v-battery-and-a-bulb-having-24-ohm-resi","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/a-simple-circuit-contains-a-12-v-battery-and-a-bulb-having-24-ohm-resi\/","title":{"rendered":"A simple circuit contains a 12 V battery and a bulb having 24 ohm resi"},"content":{"rendered":"

A simple circuit contains a 12 V battery and a bulb having 24 ohm resistance. When you turn on the switch, the ammeter connected in the circuit would read<\/p>\n

[amp_mcq option1=”0\u00b75 A” option2=”2 A” option3=”4 A” option4=”5 A” correct=”option1″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC NDA-1 – 2016<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe correct option is A.
\n<\/section>\n
\nThis question can be solved using Ohm’s Law, which states that the voltage (V) across a resistor is directly proportional to the current (I) flowing through it, provided the temperature and other physical conditions remain unchanged. The relationship is given by V = I \u00d7 R, where R is the resistance.
\nGiven:
\nVoltage, V = 12 V
\nResistance, R = 24 ohm
\nWe need to find the current, I.
\nRearranging Ohm’s Law: I = V \/ R
\nSubstituting the given values: I = 12 V \/ 24 ohm = 0.5 A.
\nThe ammeter connected in the circuit measures the current, so it would read 0.5 A.
\n<\/section>\n
\nAn ammeter is always connected in series with the component whose current is to be measured. A voltmeter is connected in parallel to measure voltage. Resistance is a measure of the opposition to current flow.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

A simple circuit contains a 12 V battery and a bulb having 24 ohm resistance. When you turn on the switch, the ammeter connected in the circuit would read [amp_mcq option1=”0\u00b75 A” option2=”2 A” option3=”4 A” option4=”5 A” correct=”option1″] This question was previously asked in UPSC NDA-1 – 2016 Download PDFAttempt Online The correct option … <\/p>\n

Detailed SolutionA simple circuit contains a 12 V battery and a bulb having 24 ohm resi<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1093],"tags":[1098,1201,1128],"class_list":["post-87380","post","type-post","status-publish","format-standard","hentry","category-upsc-nda-1","tag-1098","tag-electric-current","tag-physics","no-featured-image-padding"],"yoast_head":"\nA simple circuit contains a 12 V battery and a bulb having 24 ohm resi<\/title>\n<meta name=\"description\" content=\"The correct option is A. This question can be solved using Ohm's Law, which states that the voltage (V) across a resistor is directly proportional to the current (I) flowing through it, provided the temperature and other physical conditions remain unchanged. The relationship is given by V = I \u00d7 R, where R is the resistance. Given: Voltage, V = 12 V Resistance, R = 24 ohm We need to find the current, I. Rearranging Ohm's Law: I = V \/ R Substituting the given values: I = 12 V \/ 24 ohm = 0.5 A. The ammeter connected in the circuit measures the current, so it would read 0.5 A.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/a-simple-circuit-contains-a-12-v-battery-and-a-bulb-having-24-ohm-resi\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"A simple circuit contains a 12 V battery and a bulb having 24 ohm resi\" \/>\n<meta property=\"og:description\" content=\"The correct option is A. This question can be solved using Ohm's Law, which states that the voltage (V) across a resistor is directly proportional to the current (I) flowing through it, provided the temperature and other physical conditions remain unchanged. The relationship is given by V = I \u00d7 R, where R is the resistance. Given: Voltage, V = 12 V Resistance, R = 24 ohm We need to find the current, I. Rearranging Ohm's Law: I = V \/ R Substituting the given values: I = 12 V \/ 24 ohm = 0.5 A. The ammeter connected in the circuit measures the current, so it would read 0.5 A.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/a-simple-circuit-contains-a-12-v-battery-and-a-bulb-having-24-ohm-resi\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T06:42:03+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"A simple circuit contains a 12 V battery and a bulb having 24 ohm resi","description":"The correct option is A. This question can be solved using Ohm's Law, which states that the voltage (V) across a resistor is directly proportional to the current (I) flowing through it, provided the temperature and other physical conditions remain unchanged. The relationship is given by V = I \u00d7 R, where R is the resistance. Given: Voltage, V = 12 V Resistance, R = 24 ohm We need to find the current, I. Rearranging Ohm's Law: I = V \/ R Substituting the given values: I = 12 V \/ 24 ohm = 0.5 A. The ammeter connected in the circuit measures the current, so it would read 0.5 A.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/a-simple-circuit-contains-a-12-v-battery-and-a-bulb-having-24-ohm-resi\/","og_locale":"en_US","og_type":"article","og_title":"A simple circuit contains a 12 V battery and a bulb having 24 ohm resi","og_description":"The correct option is A. This question can be solved using Ohm's Law, which states that the voltage (V) across a resistor is directly proportional to the current (I) flowing through it, provided the temperature and other physical conditions remain unchanged. The relationship is given by V = I \u00d7 R, where R is the resistance. Given: Voltage, V = 12 V Resistance, R = 24 ohm We need to find the current, I. Rearranging Ohm's Law: I = V \/ R Substituting the given values: I = 12 V \/ 24 ohm = 0.5 A. The ammeter connected in the circuit measures the current, so it would read 0.5 A.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/a-simple-circuit-contains-a-12-v-battery-and-a-bulb-having-24-ohm-resi\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T06:42:03+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/a-simple-circuit-contains-a-12-v-battery-and-a-bulb-having-24-ohm-resi\/","url":"https:\/\/exam.pscnotes.com\/mcq\/a-simple-circuit-contains-a-12-v-battery-and-a-bulb-having-24-ohm-resi\/","name":"A simple circuit contains a 12 V battery and a bulb having 24 ohm resi","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T06:42:03+00:00","dateModified":"2025-06-01T06:42:03+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The correct option is A. 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