{"id":87372,"date":"2025-06-01T06:41:53","date_gmt":"2025-06-01T06:41:53","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=87372"},"modified":"2025-06-01T06:41:53","modified_gmt":"2025-06-01T06:41:53","slug":"a-lady-is-standing-in-front-of-a-plane-mirror-at-a-distance-of-1-m-fro","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/a-lady-is-standing-in-front-of-a-plane-mirror-at-a-distance-of-1-m-fro\/","title":{"rendered":"A lady is standing in front of a plane mirror at a distance of 1 m fro"},"content":{"rendered":"

A lady is standing in front of a plane mirror at a distance of 1 m from it. She walks 60 cm towards the mirror. The distance of her image now from herself (ignoring the thickness of the mirror) is<\/p>\n

[amp_mcq option1=”40 cm” option2=”60 cm” option3=”80 cm” option4=”120 cm” correct=”option3″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC NDA-1 – 2016<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nIn a plane mirror, the image formed is virtual, erect, and located at the same distance behind the mirror as the object is in front of the mirror.
\nInitially, the lady is at a distance of 1 m (100 cm) from the mirror. Her image is formed 100 cm behind the mirror. The distance between the lady and her image is 100 cm (lady to mirror) + 100 cm (mirror to image) = 200 cm.
\nThe lady walks 60 cm towards the mirror. Her new distance from the mirror is 100 cm – 60 cm = 40 cm.
\nHer new image is formed 40 cm behind the mirror.
\nThe new distance between the lady and her image is her distance from the mirror + her image’s distance from the mirror = 40 cm + 40 cm = 80 cm.
\n<\/section>\n
\n– Plane mirror property: Object distance from mirror = Image distance from mirror.
\n– Image is behind the mirror.
\n– Distance between object and image is (object distance) + (image distance) = 2 * (object distance).
\n<\/section>\n
\nThe image in a plane mirror is laterally inverted (left-right reversal). The magnification is +1 (image is same size as object and erect). The concept of image distance behind the mirror being equal to object distance in front is key to solving this problem.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

A lady is standing in front of a plane mirror at a distance of 1 m from it. She walks 60 cm towards the mirror. The distance of her image now from herself (ignoring the thickness of the mirror) is [amp_mcq option1=”40 cm” option2=”60 cm” option3=”80 cm” option4=”120 cm” correct=”option3″] This question was previously asked … <\/p>\n

Detailed SolutionA lady is standing in front of a plane mirror at a distance of 1 m fro<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1093],"tags":[1098,1153,1128],"class_list":["post-87372","post","type-post","status-publish","format-standard","hentry","category-upsc-nda-1","tag-1098","tag-optics","tag-physics","no-featured-image-padding"],"yoast_head":"\nA lady is standing in front of a plane mirror at a distance of 1 m fro<\/title>\n<meta name=\"description\" content=\"In a plane mirror, the image formed is virtual, erect, and located at the same distance behind the mirror as the object is in front of the mirror. Initially, the lady is at a distance of 1 m (100 cm) from the mirror. Her image is formed 100 cm behind the mirror. The distance between the lady and her image is 100 cm (lady to mirror) + 100 cm (mirror to image) = 200 cm. The lady walks 60 cm towards the mirror. Her new distance from the mirror is 100 cm - 60 cm = 40 cm. Her new image is formed 40 cm behind the mirror. The new distance between the lady and her image is her distance from the mirror + her image's distance from the mirror = 40 cm + 40 cm = 80 cm. - Plane mirror property: Object distance from mirror = Image distance from mirror. - Image is behind the mirror. - Distance between object and image is (object distance) + (image distance) = 2 * (object distance).\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/a-lady-is-standing-in-front-of-a-plane-mirror-at-a-distance-of-1-m-fro\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"A lady is standing in front of a plane mirror at a distance of 1 m fro\" \/>\n<meta property=\"og:description\" content=\"In a plane mirror, the image formed is virtual, erect, and located at the same distance behind the mirror as the object is in front of the mirror. Initially, the lady is at a distance of 1 m (100 cm) from the mirror. Her image is formed 100 cm behind the mirror. The distance between the lady and her image is 100 cm (lady to mirror) + 100 cm (mirror to image) = 200 cm. The lady walks 60 cm towards the mirror. Her new distance from the mirror is 100 cm - 60 cm = 40 cm. Her new image is formed 40 cm behind the mirror. The new distance between the lady and her image is her distance from the mirror + her image's distance from the mirror = 40 cm + 40 cm = 80 cm. - Plane mirror property: Object distance from mirror = Image distance from mirror. - Image is behind the mirror. - Distance between object and image is (object distance) + (image distance) = 2 * (object distance).\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/a-lady-is-standing-in-front-of-a-plane-mirror-at-a-distance-of-1-m-fro\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T06:41:53+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"A lady is standing in front of a plane mirror at a distance of 1 m fro","description":"In a plane mirror, the image formed is virtual, erect, and located at the same distance behind the mirror as the object is in front of the mirror. Initially, the lady is at a distance of 1 m (100 cm) from the mirror. Her image is formed 100 cm behind the mirror. The distance between the lady and her image is 100 cm (lady to mirror) + 100 cm (mirror to image) = 200 cm. The lady walks 60 cm towards the mirror. Her new distance from the mirror is 100 cm - 60 cm = 40 cm. Her new image is formed 40 cm behind the mirror. The new distance between the lady and her image is her distance from the mirror + her image's distance from the mirror = 40 cm + 40 cm = 80 cm. - Plane mirror property: Object distance from mirror = Image distance from mirror. - Image is behind the mirror. - Distance between object and image is (object distance) + (image distance) = 2 * (object distance).","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/a-lady-is-standing-in-front-of-a-plane-mirror-at-a-distance-of-1-m-fro\/","og_locale":"en_US","og_type":"article","og_title":"A lady is standing in front of a plane mirror at a distance of 1 m fro","og_description":"In a plane mirror, the image formed is virtual, erect, and located at the same distance behind the mirror as the object is in front of the mirror. Initially, the lady is at a distance of 1 m (100 cm) from the mirror. Her image is formed 100 cm behind the mirror. The distance between the lady and her image is 100 cm (lady to mirror) + 100 cm (mirror to image) = 200 cm. The lady walks 60 cm towards the mirror. Her new distance from the mirror is 100 cm - 60 cm = 40 cm. Her new image is formed 40 cm behind the mirror. The new distance between the lady and her image is her distance from the mirror + her image's distance from the mirror = 40 cm + 40 cm = 80 cm. - Plane mirror property: Object distance from mirror = Image distance from mirror. - Image is behind the mirror. - Distance between object and image is (object distance) + (image distance) = 2 * (object distance).","og_url":"https:\/\/exam.pscnotes.com\/mcq\/a-lady-is-standing-in-front-of-a-plane-mirror-at-a-distance-of-1-m-fro\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T06:41:53+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/a-lady-is-standing-in-front-of-a-plane-mirror-at-a-distance-of-1-m-fro\/","url":"https:\/\/exam.pscnotes.com\/mcq\/a-lady-is-standing-in-front-of-a-plane-mirror-at-a-distance-of-1-m-fro\/","name":"A lady is standing in front of a plane mirror at a distance of 1 m fro","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T06:41:53+00:00","dateModified":"2025-06-01T06:41:53+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"In a plane mirror, the image formed is virtual, erect, and located at the same distance behind the mirror as the object is in front of the mirror. 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The new distance between the lady and her image is her distance from the mirror + her image's distance from the mirror = 40 cm + 40 cm = 80 cm. - Plane mirror property: Object distance from mirror = Image distance from mirror. - Image is behind the mirror. - Distance between object and image is (object distance) + (image distance) = 2 * (object distance).","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/a-lady-is-standing-in-front-of-a-plane-mirror-at-a-distance-of-1-m-fro\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/a-lady-is-standing-in-front-of-a-plane-mirror-at-a-distance-of-1-m-fro\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/a-lady-is-standing-in-front-of-a-plane-mirror-at-a-distance-of-1-m-fro\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC NDA-1","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-nda-1\/"},{"@type":"ListItem","position":3,"name":"A lady is standing in front of a plane mirror at a distance of 1 m fro"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/87372","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=87372"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/87372\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=87372"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=87372"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=87372"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}