{"id":87256,"date":"2025-06-01T06:38:41","date_gmt":"2025-06-01T06:38:41","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=87256"},"modified":"2025-06-01T06:38:41","modified_gmt":"2025-06-01T06:38:41","slug":"if-a-charged-particle-q-is-projected-with-certain-velocity-parallel","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/if-a-charged-particle-q-is-projected-with-certain-velocity-parallel\/","title":{"rendered":"If a charged particle (+q) is projected with certain velocity parallel"},"content":{"rendered":"

If a charged particle (+q) is projected with certain velocity parallel to the magnetic field, then it will<\/p>\n

[amp_mcq option1=”trace helical path” option2=”trace circular path” option3=”continue its motion without any change” option4=”come to rest instantly” correct=”option3″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC NDA-1 – 2015<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe correct answer is continue its motion without any change. The magnetic force on a charged particle is given by the Lorentz force formula: F = q(v x B), where q is the charge, v is the velocity vector, and B is the magnetic field vector.
\n<\/section>\n
\nWhen the velocity vector (v) is parallel to the magnetic field vector (B), the cross product (v x B) is zero. Therefore, the magnetic force (F) on the charged particle is zero. With no force acting on it, the particle will continue to move in a straight line with constant velocity according to Newton’s first law of motion.
\n<\/section>\n
\nA charged particle traces a circular path when its velocity is perpendicular to a uniform magnetic field, and a helical path when its velocity has components both parallel and perpendicular to the field. A magnetic field alone does no work on a charged particle, only changes its direction of motion (unless the velocity is parallel or anti-parallel to the field).
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

If a charged particle (+q) is projected with certain velocity parallel to the magnetic field, then it will [amp_mcq option1=”trace helical path” option2=”trace circular path” option3=”continue its motion without any change” option4=”come to rest instantly” correct=”option3″] This question was previously asked in UPSC NDA-1 – 2015 Download PDFAttempt Online The correct answer is continue its … <\/p>\n

Detailed SolutionIf a charged particle (+q) is projected with certain velocity parallel<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1093],"tags":[1443,1201,1128],"class_list":["post-87256","post","type-post","status-publish","format-standard","hentry","category-upsc-nda-1","tag-1443","tag-electric-current","tag-physics","no-featured-image-padding"],"yoast_head":"\nIf a charged particle (+q) is projected with certain velocity parallel<\/title>\n<meta name=\"description\" content=\"The correct answer is continue its motion without any change. The magnetic force on a charged particle is given by the Lorentz force formula: F = q(v x B), where q is the charge, v is the velocity vector, and B is the magnetic field vector. When the velocity vector (v) is parallel to the magnetic field vector (B), the cross product (v x B) is zero. Therefore, the magnetic force (F) on the charged particle is zero. With no force acting on it, the particle will continue to move in a straight line with constant velocity according to Newton's first law of motion.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/if-a-charged-particle-q-is-projected-with-certain-velocity-parallel\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"If a charged particle (+q) is projected with certain velocity parallel\" \/>\n<meta property=\"og:description\" content=\"The correct answer is continue its motion without any change. The magnetic force on a charged particle is given by the Lorentz force formula: F = q(v x B), where q is the charge, v is the velocity vector, and B is the magnetic field vector. When the velocity vector (v) is parallel to the magnetic field vector (B), the cross product (v x B) is zero. Therefore, the magnetic force (F) on the charged particle is zero. With no force acting on it, the particle will continue to move in a straight line with constant velocity according to Newton's first law of motion.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/if-a-charged-particle-q-is-projected-with-certain-velocity-parallel\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T06:38:41+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"If a charged particle (+q) is projected with certain velocity parallel","description":"The correct answer is continue its motion without any change. The magnetic force on a charged particle is given by the Lorentz force formula: F = q(v x B), where q is the charge, v is the velocity vector, and B is the magnetic field vector. When the velocity vector (v) is parallel to the magnetic field vector (B), the cross product (v x B) is zero. Therefore, the magnetic force (F) on the charged particle is zero. With no force acting on it, the particle will continue to move in a straight line with constant velocity according to Newton's first law of motion.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/if-a-charged-particle-q-is-projected-with-certain-velocity-parallel\/","og_locale":"en_US","og_type":"article","og_title":"If a charged particle (+q) is projected with certain velocity parallel","og_description":"The correct answer is continue its motion without any change. The magnetic force on a charged particle is given by the Lorentz force formula: F = q(v x B), where q is the charge, v is the velocity vector, and B is the magnetic field vector. When the velocity vector (v) is parallel to the magnetic field vector (B), the cross product (v x B) is zero. Therefore, the magnetic force (F) on the charged particle is zero. With no force acting on it, the particle will continue to move in a straight line with constant velocity according to Newton's first law of motion.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/if-a-charged-particle-q-is-projected-with-certain-velocity-parallel\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T06:38:41+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/if-a-charged-particle-q-is-projected-with-certain-velocity-parallel\/","url":"https:\/\/exam.pscnotes.com\/mcq\/if-a-charged-particle-q-is-projected-with-certain-velocity-parallel\/","name":"If a charged particle (+q) is projected with certain velocity parallel","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T06:38:41+00:00","dateModified":"2025-06-01T06:38:41+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The correct answer is continue its motion without any change. The magnetic force on a charged particle is given by the Lorentz force formula: F = q(v x B), where q is the charge, v is the velocity vector, and B is the magnetic field vector. When the velocity vector (v) is parallel to the magnetic field vector (B), the cross product (v x B) is zero. Therefore, the magnetic force (F) on the charged particle is zero. With no force acting on it, the particle will continue to move in a straight line with constant velocity according to Newton's first law of motion.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/if-a-charged-particle-q-is-projected-with-certain-velocity-parallel\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/if-a-charged-particle-q-is-projected-with-certain-velocity-parallel\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/if-a-charged-particle-q-is-projected-with-certain-velocity-parallel\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC NDA-1","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-nda-1\/"},{"@type":"ListItem","position":3,"name":"If a charged particle (+q) is projected with certain velocity parallel"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/87256","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=87256"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/87256\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=87256"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=87256"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=87256"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}