{"id":87173,"date":"2025-06-01T04:30:38","date_gmt":"2025-06-01T04:30:38","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=87173"},"modified":"2025-06-01T04:30:38","modified_gmt":"2025-06-01T04:30:38","slug":"shown-in-the-circuit-is-a-20-v-battery-connected-to-an-arrangement-of","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/shown-in-the-circuit-is-a-20-v-battery-connected-to-an-arrangement-of\/","title":{"rendered":"Shown in the circuit is a 20 V battery connected to an arrangement of"},"content":{"rendered":"

Shown in the circuit is a 20 V battery connected to an arrangement of four resistors. If the potential difference between points P and Q in the circuit is zero then :<\/p>\n

[amp_mcq option1=”R = 2 \u03a9” option2=”R = 8 \u03a9” option3=”R = 18 \u03a9” option4=”R = 4 \u03a9” correct=”option4″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC Geoscientist – 2024<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe circuit can be analysed as a parallel combination of two series branches. The potential difference between points P and Q is zero when the ratio of resistances in the two branches satisfies the condition for a balanced Wheatstone bridge.
\n<\/section>\n
\nLet the branches be from A to B. Branch 1 has resistors 10\u03a9 and R in series, with P between them. Branch 2 has 5\u03a9 and 10\u03a9 in series, with Q between them. For the potential difference between P and Q to be zero (V_P = V_Q), the potential division must be the same in both branches relative to the terminals A and B. This occurs when the bridge is balanced, i.e., the ratio of resistances in the arms is equal: 10\u03a9 \/ R = 5\u03a9 \/ 10\u03a9.
\n<\/section>\n
\nFrom the balanced bridge condition, 10 \/ R = 5 \/ 10. Cross-multiplying gives 10 * 10 = 5 * R, so 100 = 5R, which means R = 20 \u03a9. However, 20 \u03a9 is not among the options. This suggests a potential error in the question or provided options. Assuming the intended answer is one of the options provided, and based on external information about this specific question from past exams, option B (R=8 \u03a9) is indicated as correct in some sources, despite standard calculation leading to R=20 \u03a9. There is likely an inconsistency in the problem statement as presented or its intended solution.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

Shown in the circuit is a 20 V battery connected to an arrangement of four resistors. If the potential difference between points P and Q in the circuit is zero then : [amp_mcq option1=”R = 2 \u03a9” option2=”R = 8 \u03a9” option3=”R = 18 \u03a9” option4=”R = 4 \u03a9” correct=”option4″] This question was previously asked … <\/p>\n

Detailed SolutionShown in the circuit is a 20 V battery connected to an arrangement of<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1091],"tags":[1103,1201,1128],"class_list":["post-87173","post","type-post","status-publish","format-standard","hentry","category-upsc-geoscientist","tag-1103","tag-electric-current","tag-physics","no-featured-image-padding"],"yoast_head":"\nShown in the circuit is a 20 V battery connected to an arrangement of<\/title>\n<meta name=\"description\" content=\"The circuit can be analysed as a parallel combination of two series branches. The potential difference between points P and Q is zero when the ratio of resistances in the two branches satisfies the condition for a balanced Wheatstone bridge. Let the branches be from A to B. Branch 1 has resistors 10\u03a9 and R in series, with P between them. Branch 2 has 5\u03a9 and 10\u03a9 in series, with Q between them. For the potential difference between P and Q to be zero (V_P = V_Q), the potential division must be the same in both branches relative to the terminals A and B. This occurs when the bridge is balanced, i.e., the ratio of resistances in the arms is equal: 10\u03a9 \/ R = 5\u03a9 \/ 10\u03a9.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/shown-in-the-circuit-is-a-20-v-battery-connected-to-an-arrangement-of\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Shown in the circuit is a 20 V battery connected to an arrangement of\" \/>\n<meta property=\"og:description\" content=\"The circuit can be analysed as a parallel combination of two series branches. The potential difference between points P and Q is zero when the ratio of resistances in the two branches satisfies the condition for a balanced Wheatstone bridge. Let the branches be from A to B. Branch 1 has resistors 10\u03a9 and R in series, with P between them. Branch 2 has 5\u03a9 and 10\u03a9 in series, with Q between them. For the potential difference between P and Q to be zero (V_P = V_Q), the potential division must be the same in both branches relative to the terminals A and B. This occurs when the bridge is balanced, i.e., the ratio of resistances in the arms is equal: 10\u03a9 \/ R = 5\u03a9 \/ 10\u03a9.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/shown-in-the-circuit-is-a-20-v-battery-connected-to-an-arrangement-of\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T04:30:38+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"Shown in the circuit is a 20 V battery connected to an arrangement of","description":"The circuit can be analysed as a parallel combination of two series branches. The potential difference between points P and Q is zero when the ratio of resistances in the two branches satisfies the condition for a balanced Wheatstone bridge. Let the branches be from A to B. Branch 1 has resistors 10\u03a9 and R in series, with P between them. Branch 2 has 5\u03a9 and 10\u03a9 in series, with Q between them. For the potential difference between P and Q to be zero (V_P = V_Q), the potential division must be the same in both branches relative to the terminals A and B. This occurs when the bridge is balanced, i.e., the ratio of resistances in the arms is equal: 10\u03a9 \/ R = 5\u03a9 \/ 10\u03a9.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/shown-in-the-circuit-is-a-20-v-battery-connected-to-an-arrangement-of\/","og_locale":"en_US","og_type":"article","og_title":"Shown in the circuit is a 20 V battery connected to an arrangement of","og_description":"The circuit can be analysed as a parallel combination of two series branches. The potential difference between points P and Q is zero when the ratio of resistances in the two branches satisfies the condition for a balanced Wheatstone bridge. Let the branches be from A to B. Branch 1 has resistors 10\u03a9 and R in series, with P between them. Branch 2 has 5\u03a9 and 10\u03a9 in series, with Q between them. For the potential difference between P and Q to be zero (V_P = V_Q), the potential division must be the same in both branches relative to the terminals A and B. This occurs when the bridge is balanced, i.e., the ratio of resistances in the arms is equal: 10\u03a9 \/ R = 5\u03a9 \/ 10\u03a9.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/shown-in-the-circuit-is-a-20-v-battery-connected-to-an-arrangement-of\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T04:30:38+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/shown-in-the-circuit-is-a-20-v-battery-connected-to-an-arrangement-of\/","url":"https:\/\/exam.pscnotes.com\/mcq\/shown-in-the-circuit-is-a-20-v-battery-connected-to-an-arrangement-of\/","name":"Shown in the circuit is a 20 V battery connected to an arrangement of","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T04:30:38+00:00","dateModified":"2025-06-01T04:30:38+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The circuit can be analysed as a parallel combination of two series branches. 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This occurs when the bridge is balanced, i.e., the ratio of resistances in the arms is equal: 10\u03a9 \/ R = 5\u03a9 \/ 10\u03a9.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/shown-in-the-circuit-is-a-20-v-battery-connected-to-an-arrangement-of\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/shown-in-the-circuit-is-a-20-v-battery-connected-to-an-arrangement-of\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/shown-in-the-circuit-is-a-20-v-battery-connected-to-an-arrangement-of\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC Geoscientist","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-geoscientist\/"},{"@type":"ListItem","position":3,"name":"Shown in the circuit is a 20 V battery connected to an arrangement of"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/87173","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=87173"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/87173\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=87173"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=87173"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=87173"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}