{"id":87171,"date":"2025-06-01T04:30:36","date_gmt":"2025-06-01T04:30:36","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=87171"},"modified":"2025-06-01T04:30:36","modified_gmt":"2025-06-01T04:30:36","slug":"ions-in-a-solution-are-subject-to-a-uniform-electric-field-if-each-io","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/ions-in-a-solution-are-subject-to-a-uniform-electric-field-if-each-io\/","title":{"rendered":"Ions in a solution are subject to a uniform electric field. If each io"},"content":{"rendered":"

Ions in a solution are subject to a uniform electric field. If each ion carries charge q and has radius R, then the ionic current I due to the applied field will depend on q and R as :<\/p>\n

[amp_mcq option1=”I \u221d qR2<\/sup>” option2=”I \u221d q2<\/sup>R” option3=”I \u221d qR0<\/sup>” option4=”I \u221d q2<\/sup>R-1<\/sup>” correct=”option4″]<\/p>\n

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This question was previously asked in<\/div>\n
UPSC Geoscientist – 2024<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nIons in a solution move under the influence of an electric field (drift velocity), and this motion constitutes an ionic current. The drift velocity is proportional to the electric force and inversely proportional to the viscous drag force.
\n<\/section>\n
\nThe electric force on an ion is F_e = qE. Assuming Stokes’ law for the viscous drag force in a solution, F_d = 6\u03c0\u03b7Rv, where \u03b7 is viscosity, R is the ion’s radius, and v is its drift velocity. In steady state, F_e = F_d, so qE = 6\u03c0\u03b7Rv. The drift velocity is v = qE \/ (6\u03c0\u03b7R). The ionic current I is proportional to the charge of each ion (q), the number density of ions (n), their drift velocity (v), and the cross-sectional area (A): I = nqvA.
\n<\/section>\n
\nSubstituting the expression for drift velocity, I \u221d q * (qE\/R) * A (assuming n, E, \u03b7, A are constant). Thus, I \u221d q\u00b2\/R = q\u00b2R\u207b\u00b9.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

Ions in a solution are subject to a uniform electric field. If each ion carries charge q and has radius R, then the ionic current I due to the applied field will depend on q and R as : [amp_mcq option1=”I \u221d qR2” option2=”I \u221d q2R” option3=”I \u221d qR0” option4=”I \u221d q2R-1” correct=”option4″] This question … <\/p>\n

Detailed SolutionIons in a solution are subject to a uniform electric field. If each io<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1091],"tags":[1103,1201,1128],"class_list":["post-87171","post","type-post","status-publish","format-standard","hentry","category-upsc-geoscientist","tag-1103","tag-electric-current","tag-physics","no-featured-image-padding"],"yoast_head":"\nIons in a solution are subject to a uniform electric field. If each io<\/title>\n<meta name=\"description\" content=\"Ions in a solution move under the influence of an electric field (drift velocity), and this motion constitutes an ionic current. The drift velocity is proportional to the electric force and inversely proportional to the viscous drag force. The electric force on an ion is F_e = qE. Assuming Stokes' law for the viscous drag force in a solution, F_d = 6\u03c0\u03b7Rv, where \u03b7 is viscosity, R is the ion's radius, and v is its drift velocity. In steady state, F_e = F_d, so qE = 6\u03c0\u03b7Rv. The drift velocity is v = qE \/ (6\u03c0\u03b7R). The ionic current I is proportional to the charge of each ion (q), the number density of ions (n), their drift velocity (v), and the cross-sectional area (A): I = nqvA.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/ions-in-a-solution-are-subject-to-a-uniform-electric-field-if-each-io\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Ions in a solution are subject to a uniform electric field. If each io\" \/>\n<meta property=\"og:description\" content=\"Ions in a solution move under the influence of an electric field (drift velocity), and this motion constitutes an ionic current. The drift velocity is proportional to the electric force and inversely proportional to the viscous drag force. The electric force on an ion is F_e = qE. Assuming Stokes' law for the viscous drag force in a solution, F_d = 6\u03c0\u03b7Rv, where \u03b7 is viscosity, R is the ion's radius, and v is its drift velocity. In steady state, F_e = F_d, so qE = 6\u03c0\u03b7Rv. The drift velocity is v = qE \/ (6\u03c0\u03b7R). The ionic current I is proportional to the charge of each ion (q), the number density of ions (n), their drift velocity (v), and the cross-sectional area (A): I = nqvA.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/ions-in-a-solution-are-subject-to-a-uniform-electric-field-if-each-io\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T04:30:36+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"Ions in a solution are subject to a uniform electric field. If each io","description":"Ions in a solution move under the influence of an electric field (drift velocity), and this motion constitutes an ionic current. The drift velocity is proportional to the electric force and inversely proportional to the viscous drag force. The electric force on an ion is F_e = qE. Assuming Stokes' law for the viscous drag force in a solution, F_d = 6\u03c0\u03b7Rv, where \u03b7 is viscosity, R is the ion's radius, and v is its drift velocity. In steady state, F_e = F_d, so qE = 6\u03c0\u03b7Rv. The drift velocity is v = qE \/ (6\u03c0\u03b7R). The ionic current I is proportional to the charge of each ion (q), the number density of ions (n), their drift velocity (v), and the cross-sectional area (A): I = nqvA.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/ions-in-a-solution-are-subject-to-a-uniform-electric-field-if-each-io\/","og_locale":"en_US","og_type":"article","og_title":"Ions in a solution are subject to a uniform electric field. If each io","og_description":"Ions in a solution move under the influence of an electric field (drift velocity), and this motion constitutes an ionic current. The drift velocity is proportional to the electric force and inversely proportional to the viscous drag force. The electric force on an ion is F_e = qE. Assuming Stokes' law for the viscous drag force in a solution, F_d = 6\u03c0\u03b7Rv, where \u03b7 is viscosity, R is the ion's radius, and v is its drift velocity. In steady state, F_e = F_d, so qE = 6\u03c0\u03b7Rv. The drift velocity is v = qE \/ (6\u03c0\u03b7R). The ionic current I is proportional to the charge of each ion (q), the number density of ions (n), their drift velocity (v), and the cross-sectional area (A): I = nqvA.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/ions-in-a-solution-are-subject-to-a-uniform-electric-field-if-each-io\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T04:30:36+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/ions-in-a-solution-are-subject-to-a-uniform-electric-field-if-each-io\/","url":"https:\/\/exam.pscnotes.com\/mcq\/ions-in-a-solution-are-subject-to-a-uniform-electric-field-if-each-io\/","name":"Ions in a solution are subject to a uniform electric field. If each io","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T04:30:36+00:00","dateModified":"2025-06-01T04:30:36+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"Ions in a solution move under the influence of an electric field (drift velocity), and this motion constitutes an ionic current. The drift velocity is proportional to the electric force and inversely proportional to the viscous drag force. The electric force on an ion is F_e = qE. Assuming Stokes' law for the viscous drag force in a solution, F_d = 6\u03c0\u03b7Rv, where \u03b7 is viscosity, R is the ion's radius, and v is its drift velocity. In steady state, F_e = F_d, so qE = 6\u03c0\u03b7Rv. The drift velocity is v = qE \/ (6\u03c0\u03b7R). The ionic current I is proportional to the charge of each ion (q), the number density of ions (n), their drift velocity (v), and the cross-sectional area (A): I = nqvA.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/ions-in-a-solution-are-subject-to-a-uniform-electric-field-if-each-io\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/ions-in-a-solution-are-subject-to-a-uniform-electric-field-if-each-io\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/ions-in-a-solution-are-subject-to-a-uniform-electric-field-if-each-io\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC Geoscientist","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-geoscientist\/"},{"@type":"ListItem","position":3,"name":"Ions in a solution are subject to a uniform electric field. 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