{"id":87170,"date":"2025-06-01T04:30:34","date_gmt":"2025-06-01T04:30:34","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=87170"},"modified":"2025-06-01T04:30:34","modified_gmt":"2025-06-01T04:30:34","slug":"magnetic-dipole-moment-of-a-square-current-loop-of-side-1-cm-and-carry","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/magnetic-dipole-moment-of-a-square-current-loop-of-side-1-cm-and-carry\/","title":{"rendered":"Magnetic dipole moment of a square current loop of side 1 cm and carry"},"content":{"rendered":"

Magnetic dipole moment of a square current loop of side 1 cm and carrying a current of 0.10 A is :<\/p>\n

[amp_mcq option1=”3.14 \u00d7 10-5<\/sup> A m2<\/sup>” option2=”1.00 \u00d7 10-5<\/sup> A m2<\/sup>” option3=”6.28 \u00d7 10-3<\/sup> A m2<\/sup>” option4=”4.00 \u00d7 10-3<\/sup> A m2<\/sup>” correct=”option2″]<\/p>\n

\n
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This question was previously asked in<\/div>\n
UPSC Geoscientist – 2024<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe magnitude of the magnetic dipole moment (m) of a planar current loop is given by the product of the current (I) flowing through the loop and the area (A) of the loop: m = IA.
\n<\/section>\n
\nThe loop is a square with side length s = 1 cm. Convert the side length to meters: s = 1 cm = 0.01 m = 10\u207b\u00b2 m. The area of the square loop is A = s\u00b2 = (10\u207b\u00b2 m)\u00b2 = 10\u207b\u2074 m\u00b2. The current is I = 0.10 A.
\n<\/section>\n
\nThe magnitude of the magnetic dipole moment is m = I * A = (0.10 A) * (10\u207b\u2074 m\u00b2) = 0.1 * 10\u207b\u2074 A m\u00b2 = 10\u207b\u00b9 * 10\u207b\u2074 A m\u00b2 = 10\u207b\u2075 A m\u00b2. This can also be written as 1.00 \u00d7 10\u207b\u2075 A m\u00b2.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

Magnetic dipole moment of a square current loop of side 1 cm and carrying a current of 0.10 A is : [amp_mcq option1=”3.14 \u00d7 10-5 A m2” option2=”1.00 \u00d7 10-5 A m2” option3=”6.28 \u00d7 10-3 A m2” option4=”4.00 \u00d7 10-3 A m2” correct=”option2″] This question was previously asked in UPSC Geoscientist – 2024 Download PDFAttempt … <\/p>\n

Detailed SolutionMagnetic dipole moment of a square current loop of side 1 cm and carry<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1091],"tags":[1103,1201,1128],"class_list":["post-87170","post","type-post","status-publish","format-standard","hentry","category-upsc-geoscientist","tag-1103","tag-electric-current","tag-physics","no-featured-image-padding"],"yoast_head":"\nMagnetic dipole moment of a square current loop of side 1 cm and carry<\/title>\n<meta name=\"description\" content=\"The magnitude of the magnetic dipole moment (m) of a planar current loop is given by the product of the current (I) flowing through the loop and the area (A) of the loop: m = IA. The loop is a square with side length s = 1 cm. Convert the side length to meters: s = 1 cm = 0.01 m = 10\u207b\u00b2 m. The area of the square loop is A = s\u00b2 = (10\u207b\u00b2 m)\u00b2 = 10\u207b\u2074 m\u00b2. The current is I = 0.10 A.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/magnetic-dipole-moment-of-a-square-current-loop-of-side-1-cm-and-carry\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Magnetic dipole moment of a square current loop of side 1 cm and carry\" \/>\n<meta property=\"og:description\" content=\"The magnitude of the magnetic dipole moment (m) of a planar current loop is given by the product of the current (I) flowing through the loop and the area (A) of the loop: m = IA. The loop is a square with side length s = 1 cm. Convert the side length to meters: s = 1 cm = 0.01 m = 10\u207b\u00b2 m. The area of the square loop is A = s\u00b2 = (10\u207b\u00b2 m)\u00b2 = 10\u207b\u2074 m\u00b2. The current is I = 0.10 A.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/magnetic-dipole-moment-of-a-square-current-loop-of-side-1-cm-and-carry\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T04:30:34+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"Magnetic dipole moment of a square current loop of side 1 cm and carry","description":"The magnitude of the magnetic dipole moment (m) of a planar current loop is given by the product of the current (I) flowing through the loop and the area (A) of the loop: m = IA. 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The area of the square loop is A = s\u00b2 = (10\u207b\u00b2 m)\u00b2 = 10\u207b\u2074 m\u00b2. The current is I = 0.10 A.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/magnetic-dipole-moment-of-a-square-current-loop-of-side-1-cm-and-carry\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T04:30:34+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/magnetic-dipole-moment-of-a-square-current-loop-of-side-1-cm-and-carry\/","url":"https:\/\/exam.pscnotes.com\/mcq\/magnetic-dipole-moment-of-a-square-current-loop-of-side-1-cm-and-carry\/","name":"Magnetic dipole moment of a square current loop of side 1 cm and carry","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T04:30:34+00:00","dateModified":"2025-06-01T04:30:34+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The magnitude of the magnetic dipole moment (m) of a planar current loop is given by the product of the current (I) flowing through the loop and the area (A) of the loop: m = IA. 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