{"id":87112,"date":"2025-06-01T04:29:15","date_gmt":"2025-06-01T04:29:15","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=87112"},"modified":"2025-06-01T04:29:15","modified_gmt":"2025-06-01T04:29:15","slug":"which-one-of-the-following-represents-the-correct-combination-of-shape","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-represents-the-correct-combination-of-shape\/","title":{"rendered":"Which one of the following represents the correct combination of shape"},"content":{"rendered":"

Which one of the following represents the correct combination of shape and hybridisation of PF\u2085 ?<\/p>\n

[amp_mcq option1=”Square pyramidal, dsp\u00b3” option2=”Trigonal bipyramidal, dsp\u00b3” option3=”Square pyramidal, sp\u00b3d” option4=”Trigonal bipyramidal, sp\u00b3d” correct=”option4″]<\/p>\n

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This question was previously asked in<\/div>\n
UPSC Geoscientist – 2024<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe correct combination of shape and hybridisation of PF\u2085 is Trigonal bipyramidal, sp\u00b3d.
\n<\/section>\n
\nIn PF\u2085, Phosphorus (P) is the central atom. P has 5 valence electrons (Group 15). It forms 5 single bonds with 5 Fluorine atoms.
\nNumber of sigma bonds around P = 5.
\nNumber of lone pairs on P = (Valence electrons on P – number of bonding electrons) \/ 2 = (5 – 5*1) \/ 2 = 0 lone pairs.
\nThe steric number (number of sigma bonds + number of lone pairs) = 5 + 0 = 5.
\nA steric number of 5 corresponds to sp\u00b3d (or dsp\u00b3) hybridization. This hybridization involves one s orbital, three p orbitals, and one d orbital combining to form five hybrid orbitals.
\nAccording to VSEPR theory, when there are 5 electron groups and no lone pairs around the central atom, the electron group geometry is trigonal bipyramidal, and the molecular shape is also trigonal bipyramidal.
\nThe five hybrid orbitals in sp\u00b3d hybridization are directed towards the vertices of a trigonal bipyramid.
\n<\/section>\n
\nIn PF\u2085, the three equatorial P-F bonds are slightly shorter and stronger than the two axial P-F bonds. The F-P-F bond angles are 90\u00b0 (axial-equatorial), 120\u00b0 (equatorial-equatorial), and 180\u00b0 (axial-axial).
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

Which one of the following represents the correct combination of shape and hybridisation of PF\u2085 ? [amp_mcq option1=”Square pyramidal, dsp\u00b3” option2=”Trigonal bipyramidal, dsp\u00b3” option3=”Square pyramidal, sp\u00b3d” option4=”Trigonal bipyramidal, sp\u00b3d” correct=”option4″] This question was previously asked in UPSC Geoscientist – 2024 Download PDFAttempt Online The correct combination of shape and hybridisation of PF\u2085 is Trigonal bipyramidal, … <\/p>\n

Detailed SolutionWhich one of the following represents the correct combination of shape<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1091],"tags":[1103,1162,1096],"class_list":["post-87112","post","type-post","status-publish","format-standard","hentry","category-upsc-geoscientist","tag-1103","tag-atomic-structure","tag-chemistry","no-featured-image-padding"],"yoast_head":"\nWhich one of the following represents the correct combination of shape<\/title>\n<meta name=\"description\" content=\"The correct combination of shape and hybridisation of PF\u2085 is Trigonal bipyramidal, sp\u00b3d. In PF\u2085, Phosphorus (P) is the central atom. P has 5 valence electrons (Group 15). It forms 5 single bonds with 5 Fluorine atoms. Number of sigma bonds around P = 5. Number of lone pairs on P = (Valence electrons on P - number of bonding electrons) \/ 2 = (5 - 5*1) \/ 2 = 0 lone pairs. The steric number (number of sigma bonds + number of lone pairs) = 5 + 0 = 5. A steric number of 5 corresponds to sp\u00b3d (or dsp\u00b3) hybridization. This hybridization involves one s orbital, three p orbitals, and one d orbital combining to form five hybrid orbitals. According to VSEPR theory, when there are 5 electron groups and no lone pairs around the central atom, the electron group geometry is trigonal bipyramidal, and the molecular shape is also trigonal bipyramidal. The five hybrid orbitals in sp\u00b3d hybridization are directed towards the vertices of a trigonal bipyramid.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-represents-the-correct-combination-of-shape\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Which one of the following represents the correct combination of shape\" \/>\n<meta property=\"og:description\" content=\"The correct combination of shape and hybridisation of PF\u2085 is Trigonal bipyramidal, sp\u00b3d. In PF\u2085, Phosphorus (P) is the central atom. P has 5 valence electrons (Group 15). It forms 5 single bonds with 5 Fluorine atoms. Number of sigma bonds around P = 5. Number of lone pairs on P = (Valence electrons on P - number of bonding electrons) \/ 2 = (5 - 5*1) \/ 2 = 0 lone pairs. The steric number (number of sigma bonds + number of lone pairs) = 5 + 0 = 5. A steric number of 5 corresponds to sp\u00b3d (or dsp\u00b3) hybridization. This hybridization involves one s orbital, three p orbitals, and one d orbital combining to form five hybrid orbitals. According to VSEPR theory, when there are 5 electron groups and no lone pairs around the central atom, the electron group geometry is trigonal bipyramidal, and the molecular shape is also trigonal bipyramidal. The five hybrid orbitals in sp\u00b3d hybridization are directed towards the vertices of a trigonal bipyramid.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-represents-the-correct-combination-of-shape\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T04:29:15+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"Which one of the following represents the correct combination of shape","description":"The correct combination of shape and hybridisation of PF\u2085 is Trigonal bipyramidal, sp\u00b3d. In PF\u2085, Phosphorus (P) is the central atom. P has 5 valence electrons (Group 15). It forms 5 single bonds with 5 Fluorine atoms. Number of sigma bonds around P = 5. Number of lone pairs on P = (Valence electrons on P - number of bonding electrons) \/ 2 = (5 - 5*1) \/ 2 = 0 lone pairs. The steric number (number of sigma bonds + number of lone pairs) = 5 + 0 = 5. A steric number of 5 corresponds to sp\u00b3d (or dsp\u00b3) hybridization. This hybridization involves one s orbital, three p orbitals, and one d orbital combining to form five hybrid orbitals. According to VSEPR theory, when there are 5 electron groups and no lone pairs around the central atom, the electron group geometry is trigonal bipyramidal, and the molecular shape is also trigonal bipyramidal. The five hybrid orbitals in sp\u00b3d hybridization are directed towards the vertices of a trigonal bipyramid.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-represents-the-correct-combination-of-shape\/","og_locale":"en_US","og_type":"article","og_title":"Which one of the following represents the correct combination of shape","og_description":"The correct combination of shape and hybridisation of PF\u2085 is Trigonal bipyramidal, sp\u00b3d. In PF\u2085, Phosphorus (P) is the central atom. P has 5 valence electrons (Group 15). It forms 5 single bonds with 5 Fluorine atoms. Number of sigma bonds around P = 5. Number of lone pairs on P = (Valence electrons on P - number of bonding electrons) \/ 2 = (5 - 5*1) \/ 2 = 0 lone pairs. The steric number (number of sigma bonds + number of lone pairs) = 5 + 0 = 5. A steric number of 5 corresponds to sp\u00b3d (or dsp\u00b3) hybridization. This hybridization involves one s orbital, three p orbitals, and one d orbital combining to form five hybrid orbitals. According to VSEPR theory, when there are 5 electron groups and no lone pairs around the central atom, the electron group geometry is trigonal bipyramidal, and the molecular shape is also trigonal bipyramidal. The five hybrid orbitals in sp\u00b3d hybridization are directed towards the vertices of a trigonal bipyramid.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-represents-the-correct-combination-of-shape\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T04:29:15+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-represents-the-correct-combination-of-shape\/","url":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-represents-the-correct-combination-of-shape\/","name":"Which one of the following represents the correct combination of shape","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T04:29:15+00:00","dateModified":"2025-06-01T04:29:15+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The correct combination of shape and hybridisation of PF\u2085 is Trigonal bipyramidal, sp\u00b3d. In PF\u2085, Phosphorus (P) is the central atom. P has 5 valence electrons (Group 15). It forms 5 single bonds with 5 Fluorine atoms. Number of sigma bonds around P = 5. Number of lone pairs on P = (Valence electrons on P - number of bonding electrons) \/ 2 = (5 - 5*1) \/ 2 = 0 lone pairs. The steric number (number of sigma bonds + number of lone pairs) = 5 + 0 = 5. A steric number of 5 corresponds to sp\u00b3d (or dsp\u00b3) hybridization. This hybridization involves one s orbital, three p orbitals, and one d orbital combining to form five hybrid orbitals. According to VSEPR theory, when there are 5 electron groups and no lone pairs around the central atom, the electron group geometry is trigonal bipyramidal, and the molecular shape is also trigonal bipyramidal. The five hybrid orbitals in sp\u00b3d hybridization are directed towards the vertices of a trigonal bipyramid.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-represents-the-correct-combination-of-shape\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-represents-the-correct-combination-of-shape\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-represents-the-correct-combination-of-shape\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC Geoscientist","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-geoscientist\/"},{"@type":"ListItem","position":3,"name":"Which one of the following represents the correct combination of shape"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/87112","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=87112"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/87112\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=87112"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=87112"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=87112"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}