{"id":87109,"date":"2025-06-01T04:29:12","date_gmt":"2025-06-01T04:29:12","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=87109"},"modified":"2025-06-01T04:29:12","modified_gmt":"2025-06-01T04:29:12","slug":"which-one-among-the-following-is-the-correct-arrangement-in-increasing","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/which-one-among-the-following-is-the-correct-arrangement-in-increasing\/","title":{"rendered":"Which one among the following is the correct arrangement in increasing"},"content":{"rendered":"

Which one among the following is the correct arrangement in increasing order of ionic radii of O\u00b2\u207b, F\u207b, Na\u207a, Mg\u00b2\u207a ?<\/p>\n

[amp_mcq option1=”Mg\u00b2\u207a < Na\u207a < F\u207b < O\u00b2\u207b\" option2=\"O\u00b2\u207b < F\u207b < Na\u207a < Mg\u00b2\u207a\" option3=\"Mg\u00b2\u207a < Na\u207a < O\u00b2\u207b < F\u207b\" option4=\"O\u00b2\u207b < F\u207b < Mg\u00b2\u207a < Na\u207a\" correct=\"option1\"]\n\n\n\n

\n
\n
This question was previously asked in<\/div>\n
UPSC Geoscientist – 2024<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe correct arrangement in increasing order of ionic radii is Mg\u00b2\u207a < Na\u207a < F\u207b < O\u00b2\u207b.\n<\/section>\n
\nThe given ions O\u00b2\u207b, F\u207b, Na\u207a, and Mg\u00b2\u207a are isoelectronic species, meaning they all have the same number of electrons (10 electrons, with the electronic configuration $1s^2 2s^2 2p^6$).
\nFor isoelectronic species, the ionic radius decreases as the nuclear charge (atomic number) increases. A higher nuclear charge exerts a stronger attraction on the same number of electrons, pulling them closer to the nucleus and reducing the ionic size.
\nThe atomic numbers are: Oxygen (O) = 8, Fluorine (F) = 9, Sodium (Na) = 11, Magnesium (Mg) = 12.
\nThe effective nuclear charges are approximately +8 for O\u00b2\u207b, +9 for F\u207b, +11 for Na\u207a, and +12 for Mg\u00b2\u207a.
\nAs the nuclear charge increases (from +8 to +12), the attraction on the 10 electrons increases, leading to a decrease in ionic size.
\nOrder of increasing nuclear charge: O\u00b2\u207b (+8) < F\u207b (+9) < Na\u207a (+11) < Mg\u00b2\u207a (+12).\nOrder of decreasing ionic radii: O\u00b2\u207b > F\u207b > Na\u207a > Mg\u00b2\u207a.
\nOrder of increasing ionic radii: Mg\u00b2\u207a < Na\u207a < F\u207b < O\u00b2\u207b.\n<\/section>\n
\nCations are generally smaller than their parent atoms because they lose valence electrons and the remaining electrons are held more tightly by the nucleus. Anions are generally larger than their parent atoms because they gain electrons, increasing electron-electron repulsion and expanding the electron cloud. Among isoelectronic species, negative ions are larger than positive ions, and within negative ions, the size increases with increasing negative charge. Within positive ions, the size decreases with increasing positive charge.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

Which one among the following is the correct arrangement in increasing order of ionic radii of O\u00b2\u207b, F\u207b, Na\u207a, Mg\u00b2\u207a ? [amp_mcq option1=”Mg\u00b2\u207a < Na\u207a < F\u207b < O\u00b2\u207b\" option2=\"O\u00b2\u207b < F\u207b < Na\u207a < Mg\u00b2\u207a\" option3=\"Mg\u00b2\u207a < Na\u207a < O\u00b2\u207b < F\u207b\" option4=\"O\u00b2\u207b < F\u207b < Mg\u00b2\u207a < Na\u207a\" correct=\"option1\"] This question was previously ... \n\n

Detailed SolutionWhich one among the following is the correct arrangement in increasing<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1091],"tags":[1103,1096,1239],"class_list":["post-87109","post","type-post","status-publish","format-standard","hentry","category-upsc-geoscientist","tag-1103","tag-chemistry","tag-inorganic-chemistry","no-featured-image-padding"],"yoast_head":"\nWhich one among the following is the correct arrangement in increasing<\/title>\n<meta name=\"description\" content=\"The correct arrangement in increasing order of ionic radii is Mg\u00b2\u207a < Na\u207a < F\u207b < O\u00b2\u207b. The given ions O\u00b2\u207b, F\u207b, Na\u207a, and Mg\u00b2\u207a are isoelectronic species, meaning they all have the same number of electrons (10 electrons, with the electronic configuration $1s^2 2s^2 2p^6$). For isoelectronic species, the ionic radius decreases as the nuclear charge (atomic number) increases. A higher nuclear charge exerts a stronger attraction on the same number of electrons, pulling them closer to the nucleus and reducing the ionic size. The atomic numbers are: Oxygen (O) = 8, Fluorine (F) = 9, Sodium (Na) = 11, Magnesium (Mg) = 12. The effective nuclear charges are approximately +8 for O\u00b2\u207b, +9 for F\u207b, +11 for Na\u207a, and +12 for Mg\u00b2\u207a. As the nuclear charge increases (from +8 to +12), the attraction on the 10 electrons increases, leading to a decrease in ionic size. Order of increasing nuclear charge: O\u00b2\u207b (+8) < F\u207b (+9) < Na\u207a (+11) < Mg\u00b2\u207a (+12). Order of decreasing ionic radii: O\u00b2\u207b > F\u207b > Na\u207a > Mg\u00b2\u207a. Order of increasing ionic radii: Mg\u00b2\u207a < Na\u207a < F\u207b < O\u00b2\u207b.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/which-one-among-the-following-is-the-correct-arrangement-in-increasing\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Which one among the following is the correct arrangement in increasing\" \/>\n<meta property=\"og:description\" content=\"The correct arrangement in increasing order of ionic radii is Mg\u00b2\u207a < Na\u207a < F\u207b < O\u00b2\u207b. The given ions O\u00b2\u207b, F\u207b, Na\u207a, and Mg\u00b2\u207a are isoelectronic species, meaning they all have the same number of electrons (10 electrons, with the electronic configuration $1s^2 2s^2 2p^6$). For isoelectronic species, the ionic radius decreases as the nuclear charge (atomic number) increases. A higher nuclear charge exerts a stronger attraction on the same number of electrons, pulling them closer to the nucleus and reducing the ionic size. The atomic numbers are: Oxygen (O) = 8, Fluorine (F) = 9, Sodium (Na) = 11, Magnesium (Mg) = 12. The effective nuclear charges are approximately +8 for O\u00b2\u207b, +9 for F\u207b, +11 for Na\u207a, and +12 for Mg\u00b2\u207a. As the nuclear charge increases (from +8 to +12), the attraction on the 10 electrons increases, leading to a decrease in ionic size. Order of increasing nuclear charge: O\u00b2\u207b (+8) < F\u207b (+9) < Na\u207a (+11) < Mg\u00b2\u207a (+12). Order of decreasing ionic radii: O\u00b2\u207b > F\u207b > Na\u207a > Mg\u00b2\u207a. Order of increasing ionic radii: Mg\u00b2\u207a < Na\u207a < F\u207b < O\u00b2\u207b.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/which-one-among-the-following-is-the-correct-arrangement-in-increasing\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T04:29:12+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"Which one among the following is the correct arrangement in increasing","description":"The correct arrangement in increasing order of ionic radii is Mg\u00b2\u207a < Na\u207a < F\u207b < O\u00b2\u207b. The given ions O\u00b2\u207b, F\u207b, Na\u207a, and Mg\u00b2\u207a are isoelectronic species, meaning they all have the same number of electrons (10 electrons, with the electronic configuration $1s^2 2s^2 2p^6$). For isoelectronic species, the ionic radius decreases as the nuclear charge (atomic number) increases. A higher nuclear charge exerts a stronger attraction on the same number of electrons, pulling them closer to the nucleus and reducing the ionic size. The atomic numbers are: Oxygen (O) = 8, Fluorine (F) = 9, Sodium (Na) = 11, Magnesium (Mg) = 12. The effective nuclear charges are approximately +8 for O\u00b2\u207b, +9 for F\u207b, +11 for Na\u207a, and +12 for Mg\u00b2\u207a. As the nuclear charge increases (from +8 to +12), the attraction on the 10 electrons increases, leading to a decrease in ionic size. Order of increasing nuclear charge: O\u00b2\u207b (+8) < F\u207b (+9) < Na\u207a (+11) < Mg\u00b2\u207a (+12). Order of decreasing ionic radii: O\u00b2\u207b > F\u207b > Na\u207a > Mg\u00b2\u207a. Order of increasing ionic radii: Mg\u00b2\u207a < Na\u207a < F\u207b < O\u00b2\u207b.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/which-one-among-the-following-is-the-correct-arrangement-in-increasing\/","og_locale":"en_US","og_type":"article","og_title":"Which one among the following is the correct arrangement in increasing","og_description":"The correct arrangement in increasing order of ionic radii is Mg\u00b2\u207a < Na\u207a < F\u207b < O\u00b2\u207b. The given ions O\u00b2\u207b, F\u207b, Na\u207a, and Mg\u00b2\u207a are isoelectronic species, meaning they all have the same number of electrons (10 electrons, with the electronic configuration $1s^2 2s^2 2p^6$). For isoelectronic species, the ionic radius decreases as the nuclear charge (atomic number) increases. A higher nuclear charge exerts a stronger attraction on the same number of electrons, pulling them closer to the nucleus and reducing the ionic size. The atomic numbers are: Oxygen (O) = 8, Fluorine (F) = 9, Sodium (Na) = 11, Magnesium (Mg) = 12. The effective nuclear charges are approximately +8 for O\u00b2\u207b, +9 for F\u207b, +11 for Na\u207a, and +12 for Mg\u00b2\u207a. As the nuclear charge increases (from +8 to +12), the attraction on the 10 electrons increases, leading to a decrease in ionic size. Order of increasing nuclear charge: O\u00b2\u207b (+8) < F\u207b (+9) < Na\u207a (+11) < Mg\u00b2\u207a (+12). Order of decreasing ionic radii: O\u00b2\u207b > F\u207b > Na\u207a > Mg\u00b2\u207a. Order of increasing ionic radii: Mg\u00b2\u207a < Na\u207a < F\u207b < O\u00b2\u207b.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/which-one-among-the-following-is-the-correct-arrangement-in-increasing\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T04:29:12+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/which-one-among-the-following-is-the-correct-arrangement-in-increasing\/","url":"https:\/\/exam.pscnotes.com\/mcq\/which-one-among-the-following-is-the-correct-arrangement-in-increasing\/","name":"Which one among the following is the correct arrangement in increasing","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T04:29:12+00:00","dateModified":"2025-06-01T04:29:12+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The correct arrangement in increasing order of ionic radii is Mg\u00b2\u207a < Na\u207a < F\u207b < O\u00b2\u207b. The given ions O\u00b2\u207b, F\u207b, Na\u207a, and Mg\u00b2\u207a are isoelectronic species, meaning they all have the same number of electrons (10 electrons, with the electronic configuration $1s^2 2s^2 2p^6$). For isoelectronic species, the ionic radius decreases as the nuclear charge (atomic number) increases. A higher nuclear charge exerts a stronger attraction on the same number of electrons, pulling them closer to the nucleus and reducing the ionic size. The atomic numbers are: Oxygen (O) = 8, Fluorine (F) = 9, Sodium (Na) = 11, Magnesium (Mg) = 12. The effective nuclear charges are approximately +8 for O\u00b2\u207b, +9 for F\u207b, +11 for Na\u207a, and +12 for Mg\u00b2\u207a. As the nuclear charge increases (from +8 to +12), the attraction on the 10 electrons increases, leading to a decrease in ionic size. Order of increasing nuclear charge: O\u00b2\u207b (+8) < F\u207b (+9) < Na\u207a (+11) < Mg\u00b2\u207a (+12). Order of decreasing ionic radii: O\u00b2\u207b > F\u207b > Na\u207a > Mg\u00b2\u207a. Order of increasing ionic radii: Mg\u00b2\u207a < Na\u207a < F\u207b < O\u00b2\u207b.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/which-one-among-the-following-is-the-correct-arrangement-in-increasing\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/which-one-among-the-following-is-the-correct-arrangement-in-increasing\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/which-one-among-the-following-is-the-correct-arrangement-in-increasing\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC Geoscientist","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-geoscientist\/"},{"@type":"ListItem","position":3,"name":"Which one among the following is the correct arrangement in increasing"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/87109","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=87109"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/87109\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=87109"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=87109"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=87109"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}