{"id":87101,"date":"2025-06-01T04:29:02","date_gmt":"2025-06-01T04:29:02","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=87101"},"modified":"2025-06-01T04:29:02","modified_gmt":"2025-06-01T04:29:02","slug":"nucleus-%c2%b2%e2%81%b4%e2%81%b0u-which-has-a-binding-energy-per-nucleon-as-7%c2%b76-mev-disin","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/nucleus-%c2%b2%e2%81%b4%e2%81%b0u-which-has-a-binding-energy-per-nucleon-as-7%c2%b76-mev-disin\/","title":{"rendered":"Nucleus \u00b2\u2074\u2070U, which has a binding energy per nucleon as 7\u00b76 MeV, disin"},"content":{"rendered":"

Nucleus \u00b2\u2074\u2070U, which has a binding energy per nucleon as 7\u00b76 MeV, disintegrates into two nuclei of \u00b9\u00b9\u2079\u22c5\u2075Sn. Take \u00b9\u00b9\u2079\u22c5\u2075Sn elements atomic mass number as 120 and binding energy per nucleon as 8\u00b74 MeV. Which one among the following is the correct value of the energy released in the disintegration process ?<\/p>\n

[amp_mcq option1=”192 MeV” option2=”190 MeV” option3=”188 MeV” option4=”3840 MeV” correct=”option1″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC Geoscientist – 2024<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nCorrect Answer: A
\n<\/section>\n
\n– The initial nucleus is \u00b2\u2074\u2070U with A=240 and binding energy per nucleon = 7.6 MeV. Total binding energy of \u00b2\u2074\u2070U = 240 * 7.6 MeV.
\n– The nucleus disintegrates into two nuclei of \u00b9\u00b9\u2079\u22c5\u2075Sn. We are given to use the atomic mass number as 120 for calculation. So, the two product nuclei have A=120 and binding energy per nucleon = 8.4 MeV.
\n– Total binding energy of the two product nuclei = 2 * (120 * 8.4 MeV).
\n– The energy released in a nuclear reaction is the difference between the total binding energy of the products and the total binding energy of the reactants. Energy released = (Total binding energy of products) – (Total binding energy of reactants).
\n– Energy released = (2 * 120 * 8.4 MeV) – (240 * 7.6 MeV)
\n– Energy released = (240 * 8.4 MeV) – (240 * 7.6 MeV)
\n– Energy released = 240 * (8.4 – 7.6) MeV
\n– Energy released = 240 * 0.8 MeV
\n– Energy released = 192 MeV.
\n<\/section>\n
\nBinding energy represents the energy required to separate the nucleons (protons and neutrons) in a nucleus. A higher binding energy per nucleon indicates a more stable nucleus. In nuclear reactions like fission or fusion, energy is released when the products are more stable (have higher binding energy per nucleon) than the reactants. The mass difference between the reactant and product nuclei (mass defect) is converted into energy according to Einstein’s famous equation E=mc\u00b2. The energy released can also be calculated from the difference in binding energies, as shown here.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

Nucleus \u00b2\u2074\u2070U, which has a binding energy per nucleon as 7\u00b76 MeV, disintegrates into two nuclei of \u00b9\u00b9\u2079\u22c5\u2075Sn. Take \u00b9\u00b9\u2079\u22c5\u2075Sn elements atomic mass number as 120 and binding energy per nucleon as 8\u00b74 MeV. Which one among the following is the correct value of the energy released in the disintegration process ? [amp_mcq option1=”192 MeV” … <\/p>\n

Detailed SolutionNucleus \u00b2\u2074\u2070U, which has a binding energy per nucleon as 7\u00b76 MeV, disin<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1091],"tags":[1103,1203,1128],"class_list":["post-87101","post","type-post","status-publish","format-standard","hentry","category-upsc-geoscientist","tag-1103","tag-nuclear-physics","tag-physics","no-featured-image-padding"],"yoast_head":"\nNucleus \u00b2\u2074\u2070U, which has a binding energy per nucleon as 7\u00b76 MeV, disin<\/title>\n<meta name=\"description\" content=\"Correct Answer: A - The initial nucleus is \u00b2\u2074\u2070U with A=240 and binding energy per nucleon = 7.6 MeV. Total binding energy of \u00b2\u2074\u2070U = 240 * 7.6 MeV. - The nucleus disintegrates into two nuclei of \u00b9\u00b9\u2079\u22c5\u2075Sn. We are given to use the atomic mass number as 120 for calculation. So, the two product nuclei have A=120 and binding energy per nucleon = 8.4 MeV. - Total binding energy of the two product nuclei = 2 * (120 * 8.4 MeV). - The energy released in a nuclear reaction is the difference between the total binding energy of the products and the total binding energy of the reactants. Energy released = (Total binding energy of products) - (Total binding energy of reactants). - Energy released = (2 * 120 * 8.4 MeV) - (240 * 7.6 MeV) - Energy released = (240 * 8.4 MeV) - (240 * 7.6 MeV) - Energy released = 240 * (8.4 - 7.6) MeV - Energy released = 240 * 0.8 MeV - Energy released = 192 MeV.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/nucleus-\u00b2\u2074\u2070u-which-has-a-binding-energy-per-nucleon-as-7\u00b76-mev-disin\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Nucleus \u00b2\u2074\u2070U, which has a binding energy per nucleon as 7\u00b76 MeV, disin\" \/>\n<meta property=\"og:description\" content=\"Correct Answer: A - The initial nucleus is \u00b2\u2074\u2070U with A=240 and binding energy per nucleon = 7.6 MeV. Total binding energy of \u00b2\u2074\u2070U = 240 * 7.6 MeV. - The nucleus disintegrates into two nuclei of \u00b9\u00b9\u2079\u22c5\u2075Sn. We are given to use the atomic mass number as 120 for calculation. So, the two product nuclei have A=120 and binding energy per nucleon = 8.4 MeV. - Total binding energy of the two product nuclei = 2 * (120 * 8.4 MeV). - The energy released in a nuclear reaction is the difference between the total binding energy of the products and the total binding energy of the reactants. Energy released = (Total binding energy of products) - (Total binding energy of reactants). - Energy released = (2 * 120 * 8.4 MeV) - (240 * 7.6 MeV) - Energy released = (240 * 8.4 MeV) - (240 * 7.6 MeV) - Energy released = 240 * (8.4 - 7.6) MeV - Energy released = 240 * 0.8 MeV - Energy released = 192 MeV.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/nucleus-\u00b2\u2074\u2070u-which-has-a-binding-energy-per-nucleon-as-7\u00b76-mev-disin\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T04:29:02+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"Nucleus \u00b2\u2074\u2070U, which has a binding energy per nucleon as 7\u00b76 MeV, disin","description":"Correct Answer: A - The initial nucleus is \u00b2\u2074\u2070U with A=240 and binding energy per nucleon = 7.6 MeV. Total binding energy of \u00b2\u2074\u2070U = 240 * 7.6 MeV. - The nucleus disintegrates into two nuclei of \u00b9\u00b9\u2079\u22c5\u2075Sn. We are given to use the atomic mass number as 120 for calculation. So, the two product nuclei have A=120 and binding energy per nucleon = 8.4 MeV. - Total binding energy of the two product nuclei = 2 * (120 * 8.4 MeV). - The energy released in a nuclear reaction is the difference between the total binding energy of the products and the total binding energy of the reactants. Energy released = (Total binding energy of products) - (Total binding energy of reactants). - Energy released = (2 * 120 * 8.4 MeV) - (240 * 7.6 MeV) - Energy released = (240 * 8.4 MeV) - (240 * 7.6 MeV) - Energy released = 240 * (8.4 - 7.6) MeV - Energy released = 240 * 0.8 MeV - Energy released = 192 MeV.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/nucleus-\u00b2\u2074\u2070u-which-has-a-binding-energy-per-nucleon-as-7\u00b76-mev-disin\/","og_locale":"en_US","og_type":"article","og_title":"Nucleus \u00b2\u2074\u2070U, which has a binding energy per nucleon as 7\u00b76 MeV, disin","og_description":"Correct Answer: A - The initial nucleus is \u00b2\u2074\u2070U with A=240 and binding energy per nucleon = 7.6 MeV. Total binding energy of \u00b2\u2074\u2070U = 240 * 7.6 MeV. - The nucleus disintegrates into two nuclei of \u00b9\u00b9\u2079\u22c5\u2075Sn. We are given to use the atomic mass number as 120 for calculation. So, the two product nuclei have A=120 and binding energy per nucleon = 8.4 MeV. - Total binding energy of the two product nuclei = 2 * (120 * 8.4 MeV). - The energy released in a nuclear reaction is the difference between the total binding energy of the products and the total binding energy of the reactants. Energy released = (Total binding energy of products) - (Total binding energy of reactants). - Energy released = (2 * 120 * 8.4 MeV) - (240 * 7.6 MeV) - Energy released = (240 * 8.4 MeV) - (240 * 7.6 MeV) - Energy released = 240 * (8.4 - 7.6) MeV - Energy released = 240 * 0.8 MeV - Energy released = 192 MeV.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/nucleus-\u00b2\u2074\u2070u-which-has-a-binding-energy-per-nucleon-as-7\u00b76-mev-disin\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T04:29:02+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/nucleus-%c2%b2%e2%81%b4%e2%81%b0u-which-has-a-binding-energy-per-nucleon-as-7%c2%b76-mev-disin\/","url":"https:\/\/exam.pscnotes.com\/mcq\/nucleus-%c2%b2%e2%81%b4%e2%81%b0u-which-has-a-binding-energy-per-nucleon-as-7%c2%b76-mev-disin\/","name":"Nucleus \u00b2\u2074\u2070U, which has a binding energy per nucleon as 7\u00b76 MeV, disin","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T04:29:02+00:00","dateModified":"2025-06-01T04:29:02+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"Correct Answer: A - The initial nucleus is \u00b2\u2074\u2070U with A=240 and binding energy per nucleon = 7.6 MeV. Total binding energy of \u00b2\u2074\u2070U = 240 * 7.6 MeV. - The nucleus disintegrates into two nuclei of \u00b9\u00b9\u2079\u22c5\u2075Sn. We are given to use the atomic mass number as 120 for calculation. So, the two product nuclei have A=120 and binding energy per nucleon = 8.4 MeV. - Total binding energy of the two product nuclei = 2 * (120 * 8.4 MeV). - The energy released in a nuclear reaction is the difference between the total binding energy of the products and the total binding energy of the reactants. Energy released = (Total binding energy of products) - (Total binding energy of reactants). - Energy released = (2 * 120 * 8.4 MeV) - (240 * 7.6 MeV) - Energy released = (240 * 8.4 MeV) - (240 * 7.6 MeV) - Energy released = 240 * (8.4 - 7.6) MeV - Energy released = 240 * 0.8 MeV - Energy released = 192 MeV.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/nucleus-%c2%b2%e2%81%b4%e2%81%b0u-which-has-a-binding-energy-per-nucleon-as-7%c2%b76-mev-disin\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/nucleus-%c2%b2%e2%81%b4%e2%81%b0u-which-has-a-binding-energy-per-nucleon-as-7%c2%b76-mev-disin\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/nucleus-%c2%b2%e2%81%b4%e2%81%b0u-which-has-a-binding-energy-per-nucleon-as-7%c2%b76-mev-disin\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC Geoscientist","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-geoscientist\/"},{"@type":"ListItem","position":3,"name":"Nucleus \u00b2\u2074\u2070U, which has a binding energy per nucleon as 7\u00b76 MeV, disin"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/87101","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=87101"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/87101\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=87101"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=87101"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=87101"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}