{"id":87063,"date":"2025-06-01T04:27:20","date_gmt":"2025-06-01T04:27:20","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=87063"},"modified":"2025-06-01T04:27:20","modified_gmt":"2025-06-01T04:27:20","slug":"in-which-of-the-following-situations-will-an-applied-force-do-negative","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/in-which-of-the-following-situations-will-an-applied-force-do-negative\/","title":{"rendered":"In which of the following situations will an applied force do negative"},"content":{"rendered":"

In which of the following situations will an applied force do negative work on a body?<\/p>\n

[amp_mcq option1=”The applied force and displacement of the body are at 135\u00b0 to each other” option2=”The applied force and displacement of the body are parallel to each other” option3=”The applied force and displacement of the body are perpendicular to each other” option4=”The applied force and displacement of the body are at 45\u00b0 to each other” correct=”option1″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC Geoscientist – 2023<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe correct answer is A) The applied force and displacement of the body are at 135\u00b0 to each other.
\n<\/section>\n
\nWork done by a constant force $\\vec{F}$ on a body that undergoes a displacement $\\vec{d}$ is given by the dot product: $W = \\vec{F} \\cdot \\vec{d} = |\\vec{F}| |\\vec{d}| \\cos \\theta$, where $\\theta$ is the angle between the force and displacement vectors.
\nWork is negative when $\\cos \\theta$ is negative. This occurs when the angle $\\theta$ is between 90\u00b0 and 270\u00b0 (exclusive of 90\u00b0 and 270\u00b0 where work is zero).
\nLet’s examine the options:
\nA) Angle is 135\u00b0. $\\cos 135\u00b0 = -1\/\\sqrt{2}$. Since $\\cos \\theta$ is negative, the work done is negative.
\nB) Angle is 0\u00b0 (same direction) or 180\u00b0 (opposite direction). If $\\theta=0\u00b0$, $\\cos 0\u00b0 = 1$, work is positive. If $\\theta=180\u00b0$, $\\cos 180\u00b0 = -1$, work is negative. So, parallel force and displacement *can* result in negative work (if opposite directions), but doesn’t *always*.
\nC) Angle is 90\u00b0. $\\cos 90\u00b0 = 0$. Work is zero.
\nD) Angle is 45\u00b0. $\\cos 45\u00b0 = 1\/\\sqrt{2}$. Since $\\cos \\theta$ is positive, work is positive.
\nOption A is the only situation listed that guarantees the work done by the applied force is negative.
\n<\/section>\n
\nExamples of negative work include the work done by friction when an object slides, the work done by air resistance on a moving object, or the work done by gravity when an object is lifted upwards. In these cases, the force (friction, air resistance, gravity) is generally opposite in direction to the displacement (motion), corresponding to an angle of 180\u00b0 or a component of the force opposing the displacement direction.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

In which of the following situations will an applied force do negative work on a body? [amp_mcq option1=”The applied force and displacement of the body are at 135\u00b0 to each other” option2=”The applied force and displacement of the body are parallel to each other” option3=”The applied force and displacement of the body are perpendicular to … <\/p>\n

Detailed SolutionIn which of the following situations will an applied force do negative<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1091],"tags":[1105,1129,1128],"class_list":["post-87063","post","type-post","status-publish","format-standard","hentry","category-upsc-geoscientist","tag-1105","tag-mechanics","tag-physics","no-featured-image-padding"],"yoast_head":"\nIn which of the following situations will an applied force do negative<\/title>\n<meta name=\"description\" content=\"The correct answer is A) The applied force and displacement of the body are at 135\u00b0 to each other. Work done by a constant force $vec{F}$ on a body that undergoes a displacement $vec{d}$ is given by the dot product: $W = vec{F} cdot vec{d} = |vec{F}| |vec{d}| cos theta$, where $theta$ is the angle between the force and displacement vectors. Work is negative when $cos theta$ is negative. This occurs when the angle $theta$ is between 90\u00b0 and 270\u00b0 (exclusive of 90\u00b0 and 270\u00b0 where work is zero). Let's examine the options: A) Angle is 135\u00b0. $cos 135\u00b0 = -1\/sqrt{2}$. Since $cos theta$ is negative, the work done is negative. B) Angle is 0\u00b0 (same direction) or 180\u00b0 (opposite direction). If $theta=0\u00b0$, $cos 0\u00b0 = 1$, work is positive. If $theta=180\u00b0$, $cos 180\u00b0 = -1$, work is negative. So, parallel force and displacement *can* result in negative work (if opposite directions), but doesn't *always*. C) Angle is 90\u00b0. $cos 90\u00b0 = 0$. Work is zero. D) Angle is 45\u00b0. $cos 45\u00b0 = 1\/sqrt{2}$. Since $cos theta$ is positive, work is positive. Option A is the only situation listed that guarantees the work done by the applied force is negative.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/in-which-of-the-following-situations-will-an-applied-force-do-negative\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"In which of the following situations will an applied force do negative\" \/>\n<meta property=\"og:description\" content=\"The correct answer is A) The applied force and displacement of the body are at 135\u00b0 to each other. Work done by a constant force $vec{F}$ on a body that undergoes a displacement $vec{d}$ is given by the dot product: $W = vec{F} cdot vec{d} = |vec{F}| |vec{d}| cos theta$, where $theta$ is the angle between the force and displacement vectors. Work is negative when $cos theta$ is negative. This occurs when the angle $theta$ is between 90\u00b0 and 270\u00b0 (exclusive of 90\u00b0 and 270\u00b0 where work is zero). Let's examine the options: A) Angle is 135\u00b0. $cos 135\u00b0 = -1\/sqrt{2}$. Since $cos theta$ is negative, the work done is negative. B) Angle is 0\u00b0 (same direction) or 180\u00b0 (opposite direction). If $theta=0\u00b0$, $cos 0\u00b0 = 1$, work is positive. If $theta=180\u00b0$, $cos 180\u00b0 = -1$, work is negative. So, parallel force and displacement *can* result in negative work (if opposite directions), but doesn't *always*. C) Angle is 90\u00b0. $cos 90\u00b0 = 0$. Work is zero. D) Angle is 45\u00b0. $cos 45\u00b0 = 1\/sqrt{2}$. Since $cos theta$ is positive, work is positive. Option A is the only situation listed that guarantees the work done by the applied force is negative.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/in-which-of-the-following-situations-will-an-applied-force-do-negative\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T04:27:20+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"2 minutes\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"In which of the following situations will an applied force do negative","description":"The correct answer is A) The applied force and displacement of the body are at 135\u00b0 to each other. Work done by a constant force $vec{F}$ on a body that undergoes a displacement $vec{d}$ is given by the dot product: $W = vec{F} cdot vec{d} = |vec{F}| |vec{d}| cos theta$, where $theta$ is the angle between the force and displacement vectors. Work is negative when $cos theta$ is negative. This occurs when the angle $theta$ is between 90\u00b0 and 270\u00b0 (exclusive of 90\u00b0 and 270\u00b0 where work is zero). Let's examine the options: A) Angle is 135\u00b0. $cos 135\u00b0 = -1\/sqrt{2}$. Since $cos theta$ is negative, the work done is negative. B) Angle is 0\u00b0 (same direction) or 180\u00b0 (opposite direction). If $theta=0\u00b0$, $cos 0\u00b0 = 1$, work is positive. If $theta=180\u00b0$, $cos 180\u00b0 = -1$, work is negative. So, parallel force and displacement *can* result in negative work (if opposite directions), but doesn't *always*. C) Angle is 90\u00b0. $cos 90\u00b0 = 0$. Work is zero. D) Angle is 45\u00b0. $cos 45\u00b0 = 1\/sqrt{2}$. Since $cos theta$ is positive, work is positive. Option A is the only situation listed that guarantees the work done by the applied force is negative.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/in-which-of-the-following-situations-will-an-applied-force-do-negative\/","og_locale":"en_US","og_type":"article","og_title":"In which of the following situations will an applied force do negative","og_description":"The correct answer is A) The applied force and displacement of the body are at 135\u00b0 to each other. Work done by a constant force $vec{F}$ on a body that undergoes a displacement $vec{d}$ is given by the dot product: $W = vec{F} cdot vec{d} = |vec{F}| |vec{d}| cos theta$, where $theta$ is the angle between the force and displacement vectors. Work is negative when $cos theta$ is negative. This occurs when the angle $theta$ is between 90\u00b0 and 270\u00b0 (exclusive of 90\u00b0 and 270\u00b0 where work is zero). Let's examine the options: A) Angle is 135\u00b0. $cos 135\u00b0 = -1\/sqrt{2}$. Since $cos theta$ is negative, the work done is negative. B) Angle is 0\u00b0 (same direction) or 180\u00b0 (opposite direction). If $theta=0\u00b0$, $cos 0\u00b0 = 1$, work is positive. If $theta=180\u00b0$, $cos 180\u00b0 = -1$, work is negative. So, parallel force and displacement *can* result in negative work (if opposite directions), but doesn't *always*. C) Angle is 90\u00b0. $cos 90\u00b0 = 0$. Work is zero. D) Angle is 45\u00b0. $cos 45\u00b0 = 1\/sqrt{2}$. Since $cos theta$ is positive, work is positive. Option A is the only situation listed that guarantees the work done by the applied force is negative.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/in-which-of-the-following-situations-will-an-applied-force-do-negative\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T04:27:20+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"2 minutes"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/in-which-of-the-following-situations-will-an-applied-force-do-negative\/","url":"https:\/\/exam.pscnotes.com\/mcq\/in-which-of-the-following-situations-will-an-applied-force-do-negative\/","name":"In which of the following situations will an applied force do negative","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T04:27:20+00:00","dateModified":"2025-06-01T04:27:20+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The correct answer is A) The applied force and displacement of the body are at 135\u00b0 to each other. Work done by a constant force $\\vec{F}$ on a body that undergoes a displacement $\\vec{d}$ is given by the dot product: $W = \\vec{F} \\cdot \\vec{d} = |\\vec{F}| |\\vec{d}| \\cos \\theta$, where $\\theta$ is the angle between the force and displacement vectors. Work is negative when $\\cos \\theta$ is negative. This occurs when the angle $\\theta$ is between 90\u00b0 and 270\u00b0 (exclusive of 90\u00b0 and 270\u00b0 where work is zero). Let's examine the options: A) Angle is 135\u00b0. $\\cos 135\u00b0 = -1\/\\sqrt{2}$. Since $\\cos \\theta$ is negative, the work done is negative. B) Angle is 0\u00b0 (same direction) or 180\u00b0 (opposite direction). If $\\theta=0\u00b0$, $\\cos 0\u00b0 = 1$, work is positive. If $\\theta=180\u00b0$, $\\cos 180\u00b0 = -1$, work is negative. So, parallel force and displacement *can* result in negative work (if opposite directions), but doesn't *always*. C) Angle is 90\u00b0. $\\cos 90\u00b0 = 0$. Work is zero. D) Angle is 45\u00b0. $\\cos 45\u00b0 = 1\/\\sqrt{2}$. Since $\\cos \\theta$ is positive, work is positive. Option A is the only situation listed that guarantees the work done by the applied force is negative.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/in-which-of-the-following-situations-will-an-applied-force-do-negative\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/in-which-of-the-following-situations-will-an-applied-force-do-negative\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/in-which-of-the-following-situations-will-an-applied-force-do-negative\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC Geoscientist","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-geoscientist\/"},{"@type":"ListItem","position":3,"name":"In which of the following situations will an applied force do negative"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/87063","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=87063"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/87063\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=87063"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=87063"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=87063"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}