{"id":86301,"date":"2025-06-01T03:42:57","date_gmt":"2025-06-01T03:42:57","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=86301"},"modified":"2025-06-01T03:42:57","modified_gmt":"2025-06-01T03:42:57","slug":"if-an-object-of-mass-10-kg-is-moving-with-a-uniform-speed-of-10-m-s-t","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/if-an-object-of-mass-10-kg-is-moving-with-a-uniform-speed-of-10-m-s-t\/","title":{"rendered":"If an object of mass 10 kg is moving with a uniform speed of 10 m\/s, t"},"content":{"rendered":"<p>If an object of mass 10 kg is moving with a uniform speed of 10 m\/s, then the linear momentum and the kinetic energy of the object, respectively, are<\/p>\n<p>[amp_mcq option1=&#8221;100 N.s and 500 J&#8221; option2=&#8221;100 N.s and 1000 J&#8221; option3=&#8221;200 N.s and 500 J&#8221; option4=&#8221;200 N.s and 1000 J&#8221; correct=&#8221;option1&#8243;]<\/p>\n<div class=\"psc-box-pyq-exam-year-detail\">\n<div class=\"pyq-exam\">\n<div class=\"psc-heading\">This question was previously asked in<\/div>\n<div class=\"psc-title line-ellipsis\">UPSC CDS-2 &#8211; 2022<\/div>\n<\/div>\n<div class=\"pyq-exam-psc-buttons\"><a href=\"\/pyq\/pyq-upsc-cds-2-2022.pdf\" target=\"_blank\" class=\"psc-pdf-button\" rel=\"noopener\">Download PDF<\/a><a href=\"\/pyq-upsc-cds-2-2022\" target=\"_blank\" class=\"psc-attempt-button\" rel=\"noopener\">Attempt Online<\/a><\/div>\n<\/div>\n<section id=\"pyq-correct-answer\">\nWe are given the mass and uniform speed of an object and asked to calculate its linear momentum and kinetic energy.<br \/>\n<\/section>\n<section id=\"pyq-key-points\">\n&#8211; Linear momentum (p) is given by the product of mass (m) and velocity (v). The unit of linear momentum is kg.m\/s, which is equivalent to N.s (Newton-second).<br \/>\nGiven m = 10 kg and v = 10 m\/s,<br \/>\np = m * v = 10 kg * 10 m\/s = 100 kg.m\/s = 100 N.s.<\/p>\n<p>&#8211; Kinetic energy (KE) is given by the formula 0.5 * m * v\u00b2. The unit of kinetic energy is Joules (J).<br \/>\nGiven m = 10 kg and v = 10 m\/s,<br \/>\nKE = 0.5 * 10 kg * (10 m\/s)\u00b2 = 0.5 * 10 kg * 100 m\u00b2\/s\u00b2 = 5 * 100 J = 500 J.<\/p>\n<p>Therefore, the linear momentum is 100 N.s and the kinetic energy is 500 J.<br \/>\n<\/section>\n<section id=\"pyq-additional-information\">\nLinear momentum is a vector quantity (direction matters), while kinetic energy is a scalar quantity. The N.s unit for momentum comes from the impulse-momentum theorem, where Impulse (Force x time) equals the change in momentum. 1 Newton = 1 kg.m\/s\u00b2, so 1 N.s = (kg.m\/s\u00b2) * s = kg.m\/s.<br \/>\n<\/section>\n","protected":false},"excerpt":{"rendered":"<p>If an object of mass 10 kg is moving with a uniform speed of 10 m\/s, then the linear momentum and the kinetic energy of the object, respectively, are [amp_mcq option1=&#8221;100 N.s and 500 J&#8221; option2=&#8221;100 N.s and 1000 J&#8221; option3=&#8221;200 N.s and 500 J&#8221; option4=&#8221;200 N.s and 1000 J&#8221; correct=&#8221;option1&#8243;] This question was previously &#8230; <\/p>\n<p class=\"read-more-container\"><a title=\"If an object of mass 10 kg is moving with a uniform speed of 10 m\/s, t\" class=\"read-more button\" href=\"https:\/\/exam.pscnotes.com\/mcq\/if-an-object-of-mass-10-kg-is-moving-with-a-uniform-speed-of-10-m-s-t\/#more-86301\">Detailed Solution<span class=\"screen-reader-text\">If an object of mass 10 kg is moving with a uniform speed of 10 m\/s, t<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1088],"tags":[1108,1129,1128],"class_list":["post-86301","post","type-post","status-publish","format-standard","hentry","category-upsc-cds-2","tag-1108","tag-mechanics","tag-physics","no-featured-image-padding"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>If an object of mass 10 kg is moving with a uniform speed of 10 m\/s, t<\/title>\n<meta name=\"description\" content=\"We are given the mass and uniform speed of an object and asked to calculate its linear momentum and kinetic energy. - Linear momentum (p) is given by the product of mass (m) and velocity (v). The unit of linear momentum is kg.m\/s, which is equivalent to N.s (Newton-second). Given m = 10 kg and v = 10 m\/s, p = m * v = 10 kg * 10 m\/s = 100 kg.m\/s = 100 N.s. - Kinetic energy (KE) is given by the formula 0.5 * m * v\u00b2. The unit of kinetic energy is Joules (J). Given m = 10 kg and v = 10 m\/s, KE = 0.5 * 10 kg * (10 m\/s)\u00b2 = 0.5 * 10 kg * 100 m\u00b2\/s\u00b2 = 5 * 100 J = 500 J. Therefore, the linear momentum is 100 N.s and the kinetic energy is 500 J.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/if-an-object-of-mass-10-kg-is-moving-with-a-uniform-speed-of-10-m-s-t\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"If an object of mass 10 kg is moving with a uniform speed of 10 m\/s, t\" \/>\n<meta property=\"og:description\" content=\"We are given the mass and uniform speed of an object and asked to calculate its linear momentum and kinetic energy. - Linear momentum (p) is given by the product of mass (m) and velocity (v). The unit of linear momentum is kg.m\/s, which is equivalent to N.s (Newton-second). Given m = 10 kg and v = 10 m\/s, p = m * v = 10 kg * 10 m\/s = 100 kg.m\/s = 100 N.s. - Kinetic energy (KE) is given by the formula 0.5 * m * v\u00b2. The unit of kinetic energy is Joules (J). Given m = 10 kg and v = 10 m\/s, KE = 0.5 * 10 kg * (10 m\/s)\u00b2 = 0.5 * 10 kg * 100 m\u00b2\/s\u00b2 = 5 * 100 J = 500 J. Therefore, the linear momentum is 100 N.s and the kinetic energy is 500 J.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/if-an-object-of-mass-10-kg-is-moving-with-a-uniform-speed-of-10-m-s-t\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T03:42:57+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"If an object of mass 10 kg is moving with a uniform speed of 10 m\/s, t","description":"We are given the mass and uniform speed of an object and asked to calculate its linear momentum and kinetic energy. - Linear momentum (p) is given by the product of mass (m) and velocity (v). The unit of linear momentum is kg.m\/s, which is equivalent to N.s (Newton-second). Given m = 10 kg and v = 10 m\/s, p = m * v = 10 kg * 10 m\/s = 100 kg.m\/s = 100 N.s. - Kinetic energy (KE) is given by the formula 0.5 * m * v\u00b2. The unit of kinetic energy is Joules (J). Given m = 10 kg and v = 10 m\/s, KE = 0.5 * 10 kg * (10 m\/s)\u00b2 = 0.5 * 10 kg * 100 m\u00b2\/s\u00b2 = 5 * 100 J = 500 J. Therefore, the linear momentum is 100 N.s and the kinetic energy is 500 J.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/if-an-object-of-mass-10-kg-is-moving-with-a-uniform-speed-of-10-m-s-t\/","og_locale":"en_US","og_type":"article","og_title":"If an object of mass 10 kg is moving with a uniform speed of 10 m\/s, t","og_description":"We are given the mass and uniform speed of an object and asked to calculate its linear momentum and kinetic energy. - Linear momentum (p) is given by the product of mass (m) and velocity (v). The unit of linear momentum is kg.m\/s, which is equivalent to N.s (Newton-second). Given m = 10 kg and v = 10 m\/s, p = m * v = 10 kg * 10 m\/s = 100 kg.m\/s = 100 N.s. - Kinetic energy (KE) is given by the formula 0.5 * m * v\u00b2. The unit of kinetic energy is Joules (J). Given m = 10 kg and v = 10 m\/s, KE = 0.5 * 10 kg * (10 m\/s)\u00b2 = 0.5 * 10 kg * 100 m\u00b2\/s\u00b2 = 5 * 100 J = 500 J. Therefore, the linear momentum is 100 N.s and the kinetic energy is 500 J.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/if-an-object-of-mass-10-kg-is-moving-with-a-uniform-speed-of-10-m-s-t\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T03:42:57+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/if-an-object-of-mass-10-kg-is-moving-with-a-uniform-speed-of-10-m-s-t\/","url":"https:\/\/exam.pscnotes.com\/mcq\/if-an-object-of-mass-10-kg-is-moving-with-a-uniform-speed-of-10-m-s-t\/","name":"If an object of mass 10 kg is moving with a uniform speed of 10 m\/s, t","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T03:42:57+00:00","dateModified":"2025-06-01T03:42:57+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"We are given the mass and uniform speed of an object and asked to calculate its linear momentum and kinetic energy. - Linear momentum (p) is given by the product of mass (m) and velocity (v). The unit of linear momentum is kg.m\/s, which is equivalent to N.s (Newton-second). Given m = 10 kg and v = 10 m\/s, p = m * v = 10 kg * 10 m\/s = 100 kg.m\/s = 100 N.s. - Kinetic energy (KE) is given by the formula 0.5 * m * v\u00b2. The unit of kinetic energy is Joules (J). Given m = 10 kg and v = 10 m\/s, KE = 0.5 * 10 kg * (10 m\/s)\u00b2 = 0.5 * 10 kg * 100 m\u00b2\/s\u00b2 = 5 * 100 J = 500 J. Therefore, the linear momentum is 100 N.s and the kinetic energy is 500 J.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/if-an-object-of-mass-10-kg-is-moving-with-a-uniform-speed-of-10-m-s-t\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/if-an-object-of-mass-10-kg-is-moving-with-a-uniform-speed-of-10-m-s-t\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/if-an-object-of-mass-10-kg-is-moving-with-a-uniform-speed-of-10-m-s-t\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC CDS-2","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-cds-2\/"},{"@type":"ListItem","position":3,"name":"If an object of mass 10 kg is moving with a uniform speed of 10 m\/s, t"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/86301","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=86301"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/86301\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=86301"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=86301"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=86301"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}