{"id":86178,"date":"2025-06-01T03:39:36","date_gmt":"2025-06-01T03:39:36","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=86178"},"modified":"2025-06-01T03:39:36","modified_gmt":"2025-06-01T03:39:36","slug":"an-electric-bulb-is-connected-to-a-110-v-generator-the-current-is-0-2","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/an-electric-bulb-is-connected-to-a-110-v-generator-the-current-is-0-2\/","title":{"rendered":"An electric bulb is connected to a 110 V generator. The current is 0.2"},"content":{"rendered":"<p>An electric bulb is connected to a 110 V generator. The current is 0.2 A. What is the power of the bulb ?<\/p>\n<p>[amp_mcq option1=&#8221;0.22 W&#8221; option2=&#8221;2.2 W&#8221; option3=&#8221;22 W&#8221; option4=&#8221;220 W&#8221; correct=&#8221;option3&#8243;]<\/p>\n<div class=\"psc-box-pyq-exam-year-detail\">\n<div class=\"pyq-exam\">\n<div class=\"psc-heading\">This question was previously asked in<\/div>\n<div class=\"psc-title line-ellipsis\">UPSC CDS-2 &#8211; 2021<\/div>\n<\/div>\n<div class=\"pyq-exam-psc-buttons\"><a href=\"\/pyq\/pyq-upsc-cds-2-2021.pdf\" target=\"_blank\" class=\"psc-pdf-button\" rel=\"noopener\">Download PDF<\/a><a href=\"\/pyq-upsc-cds-2-2021\" target=\"_blank\" class=\"psc-attempt-button\" rel=\"noopener\">Attempt Online<\/a><\/div>\n<\/div>\n<section id=\"pyq-correct-answer\">\nThe power (P) of an electrical device is given by the product of the voltage (V) across it and the current (I) flowing through it. Given V = 110 V and I = 0.2 A, the power is P = V \u00d7 I = 110 V \u00d7 0.2 A = 22 Watts.<br \/>\n<\/section>\n<section id=\"pyq-key-points\">\nElectrical power (P) is calculated using the formula P = VI, where V is the voltage in volts and I is the current in amperes. The unit of power is the Watt (W).<br \/>\n<\/section>\n<section id=\"pyq-additional-information\">\nOther useful formulas relating power, voltage, current, and resistance (R) are P = I\u00b2R and P = V\u00b2\/R (derived from Ohm&#8217;s Law, V=IR). In this problem, only voltage and current were given, so P=VI is the direct formula to use.<br \/>\n<\/section>\n","protected":false},"excerpt":{"rendered":"<p>An electric bulb is connected to a 110 V generator. The current is 0.2 A. What is the power of the bulb ? [amp_mcq option1=&#8221;0.22 W&#8221; option2=&#8221;2.2 W&#8221; option3=&#8221;22 W&#8221; option4=&#8221;220 W&#8221; correct=&#8221;option3&#8243;] This question was previously asked in UPSC CDS-2 &#8211; 2021 Download PDFAttempt Online The power (P) of an electrical device is given &#8230; <\/p>\n<p class=\"read-more-container\"><a title=\"An electric bulb is connected to a 110 V generator. The current is 0.2\" class=\"read-more button\" href=\"https:\/\/exam.pscnotes.com\/mcq\/an-electric-bulb-is-connected-to-a-110-v-generator-the-current-is-0-2\/#more-86178\">Detailed Solution<span class=\"screen-reader-text\">An electric bulb is connected to a 110 V generator. The current is 0.2<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1088],"tags":[1110,1201,1128],"class_list":["post-86178","post","type-post","status-publish","format-standard","hentry","category-upsc-cds-2","tag-1110","tag-electric-current","tag-physics","no-featured-image-padding"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>An electric bulb is connected to a 110 V generator. The current is 0.2<\/title>\n<meta name=\"description\" content=\"The power (P) of an electrical device is given by the product of the voltage (V) across it and the current (I) flowing through it. Given V = 110 V and I = 0.2 A, the power is P = V \u00d7 I = 110 V \u00d7 0.2 A = 22 Watts. Electrical power (P) is calculated using the formula P = VI, where V is the voltage in volts and I is the current in amperes. The unit of power is the Watt (W).\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/an-electric-bulb-is-connected-to-a-110-v-generator-the-current-is-0-2\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"An electric bulb is connected to a 110 V generator. The current is 0.2\" \/>\n<meta property=\"og:description\" content=\"The power (P) of an electrical device is given by the product of the voltage (V) across it and the current (I) flowing through it. Given V = 110 V and I = 0.2 A, the power is P = V \u00d7 I = 110 V \u00d7 0.2 A = 22 Watts. Electrical power (P) is calculated using the formula P = VI, where V is the voltage in volts and I is the current in amperes. The unit of power is the Watt (W).\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/an-electric-bulb-is-connected-to-a-110-v-generator-the-current-is-0-2\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T03:39:36+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"An electric bulb is connected to a 110 V generator. The current is 0.2","description":"The power (P) of an electrical device is given by the product of the voltage (V) across it and the current (I) flowing through it. Given V = 110 V and I = 0.2 A, the power is P = V \u00d7 I = 110 V \u00d7 0.2 A = 22 Watts. Electrical power (P) is calculated using the formula P = VI, where V is the voltage in volts and I is the current in amperes. The unit of power is the Watt (W).","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/an-electric-bulb-is-connected-to-a-110-v-generator-the-current-is-0-2\/","og_locale":"en_US","og_type":"article","og_title":"An electric bulb is connected to a 110 V generator. The current is 0.2","og_description":"The power (P) of an electrical device is given by the product of the voltage (V) across it and the current (I) flowing through it. Given V = 110 V and I = 0.2 A, the power is P = V \u00d7 I = 110 V \u00d7 0.2 A = 22 Watts. Electrical power (P) is calculated using the formula P = VI, where V is the voltage in volts and I is the current in amperes. The unit of power is the Watt (W).","og_url":"https:\/\/exam.pscnotes.com\/mcq\/an-electric-bulb-is-connected-to-a-110-v-generator-the-current-is-0-2\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T03:39:36+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/an-electric-bulb-is-connected-to-a-110-v-generator-the-current-is-0-2\/","url":"https:\/\/exam.pscnotes.com\/mcq\/an-electric-bulb-is-connected-to-a-110-v-generator-the-current-is-0-2\/","name":"An electric bulb is connected to a 110 V generator. The current is 0.2","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T03:39:36+00:00","dateModified":"2025-06-01T03:39:36+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The power (P) of an electrical device is given by the product of the voltage (V) across it and the current (I) flowing through it. Given V = 110 V and I = 0.2 A, the power is P = V \u00d7 I = 110 V \u00d7 0.2 A = 22 Watts. Electrical power (P) is calculated using the formula P = VI, where V is the voltage in volts and I is the current in amperes. The unit of power is the Watt (W).","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/an-electric-bulb-is-connected-to-a-110-v-generator-the-current-is-0-2\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/an-electric-bulb-is-connected-to-a-110-v-generator-the-current-is-0-2\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/an-electric-bulb-is-connected-to-a-110-v-generator-the-current-is-0-2\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC CDS-2","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-cds-2\/"},{"@type":"ListItem","position":3,"name":"An electric bulb is connected to a 110 V generator. The current is 0.2"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/86178","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=86178"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/86178\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=86178"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=86178"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=86178"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}