{"id":86141,"date":"2025-06-01T03:38:34","date_gmt":"2025-06-01T03:38:34","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=86141"},"modified":"2025-06-01T03:38:34","modified_gmt":"2025-06-01T03:38:34","slug":"when-a-light-ray-enters-into-glass-medium-from-water-at-an-angle-of-in","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/when-a-light-ray-enters-into-glass-medium-from-water-at-an-angle-of-in\/","title":{"rendered":"When a light ray enters into glass medium from water at an angle of in"},"content":{"rendered":"

When a light ray enters into glass medium from water at an angle of incidence 0\u00b0, what would be the angle of refraction?<\/p>\n

[amp_mcq option1=”90\u00b0” option2=”45\u00b0” option3=”0\u00b0” option4=”The ray will not enter at all” correct=”option3″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC CDS-2 – 2020<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nWhen a light ray enters a medium from another medium at an angle of incidence of 0\u00b0, this means the ray is incident normally (perpendicularly) to the boundary surface between the two media. According to Snell’s Law of Refraction, n\u2081 sin(i) = n\u2082 sin(r), where n\u2081 and n\u2082 are the refractive indices of the two media, i is the angle of incidence, and r is the angle of refraction. If i = 0\u00b0, then sin(i) = sin(0\u00b0) = 0. The equation becomes n\u2081 * 0 = n\u2082 sin(r), which simplifies to 0 = n\u2082 sin(r). Since the refractive index of glass (n\u2082) is not zero, sin(r) must be zero. The angle whose sine is zero is 0\u00b0. Therefore, the angle of refraction (r) is 0\u00b0. This means the ray passes straight through the boundary without bending.
\n<\/section>\n
\nA light ray incident normally on a boundary between two media passes undeviated, meaning the angle of refraction is also 0\u00b0.
\n<\/section>\n
\nRefraction, or the bending of light, occurs when light changes speed as it passes from one medium to another at an angle. When the incidence is normal (angle of incidence = 0), the change in speed still occurs, but there is no change in direction.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

When a light ray enters into glass medium from water at an angle of incidence 0\u00b0, what would be the angle of refraction? [amp_mcq option1=”90\u00b0” option2=”45\u00b0” option3=”0\u00b0” option4=”The ray will not enter at all” correct=”option3″] This question was previously asked in UPSC CDS-2 – 2020 Download PDFAttempt Online When a light ray enters a medium … <\/p>\n

Detailed SolutionWhen a light ray enters into glass medium from water at an angle of in<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1088],"tags":[1288,1153,1128],"class_list":["post-86141","post","type-post","status-publish","format-standard","hentry","category-upsc-cds-2","tag-1288","tag-optics","tag-physics","no-featured-image-padding"],"yoast_head":"\nWhen a light ray enters into glass medium from water at an angle of in<\/title>\n<meta name=\"description\" content=\"When a light ray enters a medium from another medium at an angle of incidence of 0\u00b0, this means the ray is incident normally (perpendicularly) to the boundary surface between the two media. According to Snell's Law of Refraction, n\u2081 sin(i) = n\u2082 sin(r), where n\u2081 and n\u2082 are the refractive indices of the two media, i is the angle of incidence, and r is the angle of refraction. If i = 0\u00b0, then sin(i) = sin(0\u00b0) = 0. The equation becomes n\u2081 * 0 = n\u2082 sin(r), which simplifies to 0 = n\u2082 sin(r). Since the refractive index of glass (n\u2082) is not zero, sin(r) must be zero. The angle whose sine is zero is 0\u00b0. Therefore, the angle of refraction (r) is 0\u00b0. This means the ray passes straight through the boundary without bending. A light ray incident normally on a boundary between two media passes undeviated, meaning the angle of refraction is also 0\u00b0.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/when-a-light-ray-enters-into-glass-medium-from-water-at-an-angle-of-in\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"When a light ray enters into glass medium from water at an angle of in\" \/>\n<meta property=\"og:description\" content=\"When a light ray enters a medium from another medium at an angle of incidence of 0\u00b0, this means the ray is incident normally (perpendicularly) to the boundary surface between the two media. According to Snell's Law of Refraction, n\u2081 sin(i) = n\u2082 sin(r), where n\u2081 and n\u2082 are the refractive indices of the two media, i is the angle of incidence, and r is the angle of refraction. If i = 0\u00b0, then sin(i) = sin(0\u00b0) = 0. The equation becomes n\u2081 * 0 = n\u2082 sin(r), which simplifies to 0 = n\u2082 sin(r). Since the refractive index of glass (n\u2082) is not zero, sin(r) must be zero. The angle whose sine is zero is 0\u00b0. Therefore, the angle of refraction (r) is 0\u00b0. This means the ray passes straight through the boundary without bending. A light ray incident normally on a boundary between two media passes undeviated, meaning the angle of refraction is also 0\u00b0.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/when-a-light-ray-enters-into-glass-medium-from-water-at-an-angle-of-in\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T03:38:34+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"When a light ray enters into glass medium from water at an angle of in","description":"When a light ray enters a medium from another medium at an angle of incidence of 0\u00b0, this means the ray is incident normally (perpendicularly) to the boundary surface between the two media. According to Snell's Law of Refraction, n\u2081 sin(i) = n\u2082 sin(r), where n\u2081 and n\u2082 are the refractive indices of the two media, i is the angle of incidence, and r is the angle of refraction. If i = 0\u00b0, then sin(i) = sin(0\u00b0) = 0. The equation becomes n\u2081 * 0 = n\u2082 sin(r), which simplifies to 0 = n\u2082 sin(r). Since the refractive index of glass (n\u2082) is not zero, sin(r) must be zero. The angle whose sine is zero is 0\u00b0. Therefore, the angle of refraction (r) is 0\u00b0. This means the ray passes straight through the boundary without bending. A light ray incident normally on a boundary between two media passes undeviated, meaning the angle of refraction is also 0\u00b0.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/when-a-light-ray-enters-into-glass-medium-from-water-at-an-angle-of-in\/","og_locale":"en_US","og_type":"article","og_title":"When a light ray enters into glass medium from water at an angle of in","og_description":"When a light ray enters a medium from another medium at an angle of incidence of 0\u00b0, this means the ray is incident normally (perpendicularly) to the boundary surface between the two media. According to Snell's Law of Refraction, n\u2081 sin(i) = n\u2082 sin(r), where n\u2081 and n\u2082 are the refractive indices of the two media, i is the angle of incidence, and r is the angle of refraction. If i = 0\u00b0, then sin(i) = sin(0\u00b0) = 0. The equation becomes n\u2081 * 0 = n\u2082 sin(r), which simplifies to 0 = n\u2082 sin(r). Since the refractive index of glass (n\u2082) is not zero, sin(r) must be zero. The angle whose sine is zero is 0\u00b0. Therefore, the angle of refraction (r) is 0\u00b0. This means the ray passes straight through the boundary without bending. A light ray incident normally on a boundary between two media passes undeviated, meaning the angle of refraction is also 0\u00b0.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/when-a-light-ray-enters-into-glass-medium-from-water-at-an-angle-of-in\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T03:38:34+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/when-a-light-ray-enters-into-glass-medium-from-water-at-an-angle-of-in\/","url":"https:\/\/exam.pscnotes.com\/mcq\/when-a-light-ray-enters-into-glass-medium-from-water-at-an-angle-of-in\/","name":"When a light ray enters into glass medium from water at an angle of in","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T03:38:34+00:00","dateModified":"2025-06-01T03:38:34+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"When a light ray enters a medium from another medium at an angle of incidence of 0\u00b0, this means the ray is incident normally (perpendicularly) to the boundary surface between the two media. According to Snell's Law of Refraction, n\u2081 sin(i) = n\u2082 sin(r), where n\u2081 and n\u2082 are the refractive indices of the two media, i is the angle of incidence, and r is the angle of refraction. If i = 0\u00b0, then sin(i) = sin(0\u00b0) = 0. The equation becomes n\u2081 * 0 = n\u2082 sin(r), which simplifies to 0 = n\u2082 sin(r). Since the refractive index of glass (n\u2082) is not zero, sin(r) must be zero. The angle whose sine is zero is 0\u00b0. Therefore, the angle of refraction (r) is 0\u00b0. This means the ray passes straight through the boundary without bending. A light ray incident normally on a boundary between two media passes undeviated, meaning the angle of refraction is also 0\u00b0.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/when-a-light-ray-enters-into-glass-medium-from-water-at-an-angle-of-in\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/when-a-light-ray-enters-into-glass-medium-from-water-at-an-angle-of-in\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/when-a-light-ray-enters-into-glass-medium-from-water-at-an-angle-of-in\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC CDS-2","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-cds-2\/"},{"@type":"ListItem","position":3,"name":"When a light ray enters into glass medium from water at an angle of in"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/86141","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=86141"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/86141\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=86141"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=86141"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=86141"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}