{"id":86124,"date":"2025-06-01T03:38:10","date_gmt":"2025-06-01T03:38:10","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=86124"},"modified":"2025-06-01T03:38:10","modified_gmt":"2025-06-01T03:38:10","slug":"if-the-linear-momentum-of-a-moving-object-gets-doubled-due-to-applicat","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/if-the-linear-momentum-of-a-moving-object-gets-doubled-due-to-applicat\/","title":{"rendered":"If the linear momentum of a moving object gets doubled due to applicat"},"content":{"rendered":"

If the linear momentum of a moving object gets doubled due to application of a force, then its kinetic energy will<\/p>\n

[amp_mcq option1=”remain same” option2=”increase by four times” option3=”increase by two times” option4=”increase by eight times” correct=”option2″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC CDS-2 – 2020<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe kinetic energy of the moving object will increase by four times.
\n<\/section>\n
\nThe linear momentum (p) of an object is given by the product of its mass (m) and velocity (v), i.e., p = mv. The kinetic energy (KE) is given by KE = (1\/2)mv\u00b2. We can express KE in terms of momentum: KE = (1\/2)m(p\/m)\u00b2 = p\u00b2\/(2m). If the momentum is doubled (p’ = 2p), the new kinetic energy (KE’) will be KE’ = (p’)\u00b2\/(2m) = (2p)\u00b2\/(2m) = 4p\u00b2\/(2m) = 4 * (p\u00b2\/(2m)) = 4 * KE.
\n<\/section>\n
\nThis relationship shows that kinetic energy is proportional to the square of momentum when mass is constant. Doubling the momentum results in quadrupling the kinetic energy.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

If the linear momentum of a moving object gets doubled due to application of a force, then its kinetic energy will [amp_mcq option1=”remain same” option2=”increase by four times” option3=”increase by two times” option4=”increase by eight times” correct=”option2″] This question was previously asked in UPSC CDS-2 – 2020 Download PDFAttempt Online The kinetic energy of the … <\/p>\n

Detailed SolutionIf the linear momentum of a moving object gets doubled due to applicat<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1088],"tags":[1288,1129,1128],"class_list":["post-86124","post","type-post","status-publish","format-standard","hentry","category-upsc-cds-2","tag-1288","tag-mechanics","tag-physics","no-featured-image-padding"],"yoast_head":"\nIf the linear momentum of a moving object gets doubled due to applicat<\/title>\n<meta name=\"description\" content=\"The kinetic energy of the moving object will increase by four times. The linear momentum (p) of an object is given by the product of its mass (m) and velocity (v), i.e., p = mv. The kinetic energy (KE) is given by KE = (1\/2)mv\u00b2. We can express KE in terms of momentum: KE = (1\/2)m(p\/m)\u00b2 = p\u00b2\/(2m). If the momentum is doubled (p' = 2p), the new kinetic energy (KE') will be KE' = (p')\u00b2\/(2m) = (2p)\u00b2\/(2m) = 4p\u00b2\/(2m) = 4 * (p\u00b2\/(2m)) = 4 * KE.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/if-the-linear-momentum-of-a-moving-object-gets-doubled-due-to-applicat\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"If the linear momentum of a moving object gets doubled due to applicat\" \/>\n<meta property=\"og:description\" content=\"The kinetic energy of the moving object will increase by four times. The linear momentum (p) of an object is given by the product of its mass (m) and velocity (v), i.e., p = mv. The kinetic energy (KE) is given by KE = (1\/2)mv\u00b2. We can express KE in terms of momentum: KE = (1\/2)m(p\/m)\u00b2 = p\u00b2\/(2m). If the momentum is doubled (p' = 2p), the new kinetic energy (KE') will be KE' = (p')\u00b2\/(2m) = (2p)\u00b2\/(2m) = 4p\u00b2\/(2m) = 4 * (p\u00b2\/(2m)) = 4 * KE.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/if-the-linear-momentum-of-a-moving-object-gets-doubled-due-to-applicat\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T03:38:10+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"If the linear momentum of a moving object gets doubled due to applicat","description":"The kinetic energy of the moving object will increase by four times. The linear momentum (p) of an object is given by the product of its mass (m) and velocity (v), i.e., p = mv. The kinetic energy (KE) is given by KE = (1\/2)mv\u00b2. We can express KE in terms of momentum: KE = (1\/2)m(p\/m)\u00b2 = p\u00b2\/(2m). If the momentum is doubled (p' = 2p), the new kinetic energy (KE') will be KE' = (p')\u00b2\/(2m) = (2p)\u00b2\/(2m) = 4p\u00b2\/(2m) = 4 * (p\u00b2\/(2m)) = 4 * KE.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/if-the-linear-momentum-of-a-moving-object-gets-doubled-due-to-applicat\/","og_locale":"en_US","og_type":"article","og_title":"If the linear momentum of a moving object gets doubled due to applicat","og_description":"The kinetic energy of the moving object will increase by four times. The linear momentum (p) of an object is given by the product of its mass (m) and velocity (v), i.e., p = mv. The kinetic energy (KE) is given by KE = (1\/2)mv\u00b2. We can express KE in terms of momentum: KE = (1\/2)m(p\/m)\u00b2 = p\u00b2\/(2m). If the momentum is doubled (p' = 2p), the new kinetic energy (KE') will be KE' = (p')\u00b2\/(2m) = (2p)\u00b2\/(2m) = 4p\u00b2\/(2m) = 4 * (p\u00b2\/(2m)) = 4 * KE.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/if-the-linear-momentum-of-a-moving-object-gets-doubled-due-to-applicat\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T03:38:10+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/if-the-linear-momentum-of-a-moving-object-gets-doubled-due-to-applicat\/","url":"https:\/\/exam.pscnotes.com\/mcq\/if-the-linear-momentum-of-a-moving-object-gets-doubled-due-to-applicat\/","name":"If the linear momentum of a moving object gets doubled due to applicat","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T03:38:10+00:00","dateModified":"2025-06-01T03:38:10+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The kinetic energy of the moving object will increase by four times. The linear momentum (p) of an object is given by the product of its mass (m) and velocity (v), i.e., p = mv. The kinetic energy (KE) is given by KE = (1\/2)mv\u00b2. We can express KE in terms of momentum: KE = (1\/2)m(p\/m)\u00b2 = p\u00b2\/(2m). If the momentum is doubled (p' = 2p), the new kinetic energy (KE') will be KE' = (p')\u00b2\/(2m) = (2p)\u00b2\/(2m) = 4p\u00b2\/(2m) = 4 * (p\u00b2\/(2m)) = 4 * KE.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/if-the-linear-momentum-of-a-moving-object-gets-doubled-due-to-applicat\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/if-the-linear-momentum-of-a-moving-object-gets-doubled-due-to-applicat\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/if-the-linear-momentum-of-a-moving-object-gets-doubled-due-to-applicat\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC CDS-2","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-cds-2\/"},{"@type":"ListItem","position":3,"name":"If the linear momentum of a moving object gets doubled due to applicat"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/86124","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=86124"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/86124\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=86124"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=86124"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=86124"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}