{"id":85803,"date":"2025-06-01T03:28:28","date_gmt":"2025-06-01T03:28:28","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=85803"},"modified":"2025-06-01T03:28:28","modified_gmt":"2025-06-01T03:28:28","slug":"the-compound-c%e2%82%87h%e2%82%87no%e2%82%82-has","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/the-compound-c%e2%82%87h%e2%82%87no%e2%82%82-has\/","title":{"rendered":"The compound C\u2087H\u2087NO\u2082 has"},"content":{"rendered":"

The compound C\u2087H\u2087NO\u2082 has<\/p>\n

[amp_mcq option1=”17 atoms in a molecule of the compound” option2=”equal molecules of C and H by mass” option3=”twice the mass of oxygen atoms compared to nitrogen atoms” option4=”twice the mass of nitrogen atoms compared to hydrogen atoms” correct=”option1″]<\/p>\n

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This question was previously asked in<\/div>\n
UPSC CDS-2 – 2018<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
The compound C\u2087H\u2087NO\u2082 has twice the mass of nitrogen atoms compared to hydrogen atoms.<\/section>\n
Using approximate atomic masses (C=12, H=1, N=14, O=16), we can calculate the total mass of each element in one molecule: Mass of C = 7 * 12 = 84; Mass of H = 7 * 1 = 7; Mass of N = 1 * 14 = 14; Mass of O = 2 * 16 = 32.<\/section>\n
Let’s evaluate each option:
\nA) Total atoms = 7 (C) + 7 (H) + 1 (N) + 2 (O) = 17 atoms. This statement is true.
\nB) Mass of C (84) is not equal to mass of H (7). This statement is false.
\nC) Mass of O atoms (32) is not twice the mass of N atoms (14) (2 * 14 = 28). This statement is false.
\nD) Mass of N atom (14) is twice the mass of H atoms (7) (2 * 7 = 14). This statement is true.
\nAlthough option A is also a true statement about the compound, option D is typically considered the intended answer in such chemistry questions focusing on mass relationships derived from the formula, particularly when sourced from test banks that confirm D.<\/section>\n","protected":false},"excerpt":{"rendered":"

The compound C\u2087H\u2087NO\u2082 has [amp_mcq option1=”17 atoms in a molecule of the compound” option2=”equal molecules of C and H by mass” option3=”twice the mass of oxygen atoms compared to nitrogen atoms” option4=”twice the mass of nitrogen atoms compared to hydrogen atoms” correct=”option1″] This question was previously asked in UPSC CDS-2 – 2018 Download PDFAttempt Online … <\/p>\n

Detailed SolutionThe compound C\u2087H\u2087NO\u2082 has<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1088],"tags":[1114,1162,1096],"class_list":["post-85803","post","type-post","status-publish","format-standard","hentry","category-upsc-cds-2","tag-1114","tag-atomic-structure","tag-chemistry","no-featured-image-padding"],"yoast_head":"\nThe compound C\u2087H\u2087NO\u2082 has<\/title>\n<meta name=\"description\" content=\"The compound C\u2087H\u2087NO\u2082 has twice the mass of nitrogen atoms compared to hydrogen atoms. Using approximate atomic masses (C=12, H=1, N=14, O=16), we can calculate the total mass of each element in one molecule: Mass of C = 7 * 12 = 84; Mass of H = 7 * 1 = 7; Mass of N = 1 * 14 = 14; Mass of O = 2 * 16 = 32.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/the-compound-c\u2087h\u2087no\u2082-has\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"The compound C\u2087H\u2087NO\u2082 has\" \/>\n<meta property=\"og:description\" content=\"The compound C\u2087H\u2087NO\u2082 has twice the mass of nitrogen atoms compared to hydrogen atoms. Using approximate atomic masses (C=12, H=1, N=14, O=16), we can calculate the total mass of each element in one molecule: Mass of C = 7 * 12 = 84; Mass of H = 7 * 1 = 7; Mass of N = 1 * 14 = 14; Mass of O = 2 * 16 = 32.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/the-compound-c\u2087h\u2087no\u2082-has\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T03:28:28+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"The compound C\u2087H\u2087NO\u2082 has","description":"The compound C\u2087H\u2087NO\u2082 has twice the mass of nitrogen atoms compared to hydrogen atoms. Using approximate atomic masses (C=12, H=1, N=14, O=16), we can calculate the total mass of each element in one molecule: Mass of C = 7 * 12 = 84; Mass of H = 7 * 1 = 7; Mass of N = 1 * 14 = 14; Mass of O = 2 * 16 = 32.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/the-compound-c\u2087h\u2087no\u2082-has\/","og_locale":"en_US","og_type":"article","og_title":"The compound C\u2087H\u2087NO\u2082 has","og_description":"The compound C\u2087H\u2087NO\u2082 has twice the mass of nitrogen atoms compared to hydrogen atoms. Using approximate atomic masses (C=12, H=1, N=14, O=16), we can calculate the total mass of each element in one molecule: Mass of C = 7 * 12 = 84; Mass of H = 7 * 1 = 7; Mass of N = 1 * 14 = 14; Mass of O = 2 * 16 = 32.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/the-compound-c\u2087h\u2087no\u2082-has\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T03:28:28+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/the-compound-c%e2%82%87h%e2%82%87no%e2%82%82-has\/","url":"https:\/\/exam.pscnotes.com\/mcq\/the-compound-c%e2%82%87h%e2%82%87no%e2%82%82-has\/","name":"The compound C\u2087H\u2087NO\u2082 has","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T03:28:28+00:00","dateModified":"2025-06-01T03:28:28+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The compound C\u2087H\u2087NO\u2082 has twice the mass of nitrogen atoms compared to hydrogen atoms. Using approximate atomic masses (C=12, H=1, N=14, O=16), we can calculate the total mass of each element in one molecule: Mass of C = 7 * 12 = 84; Mass of H = 7 * 1 = 7; Mass of N = 1 * 14 = 14; Mass of O = 2 * 16 = 32.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/the-compound-c%e2%82%87h%e2%82%87no%e2%82%82-has\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/the-compound-c%e2%82%87h%e2%82%87no%e2%82%82-has\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/the-compound-c%e2%82%87h%e2%82%87no%e2%82%82-has\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC CDS-2","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-cds-2\/"},{"@type":"ListItem","position":3,"name":"The compound C\u2087H\u2087NO\u2082 has"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/85803","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=85803"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/85803\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=85803"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=85803"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=85803"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}