{"id":85800,"date":"2025-06-01T03:28:25","date_gmt":"2025-06-01T03:28:25","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=85800"},"modified":"2025-06-01T03:28:25","modified_gmt":"2025-06-01T03:28:25","slug":"how-many-moles-of-co-can-be-obtained-by-reacting-2%c2%b70-mole-of-ch%e2%82%84-with","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/how-many-moles-of-co-can-be-obtained-by-reacting-2%c2%b70-mole-of-ch%e2%82%84-with\/","title":{"rendered":"How many moles of CO can be obtained by reacting 2\u00b70 mole of CH\u2084 with"},"content":{"rendered":"

How many moles of CO can be obtained by reacting 2\u00b70 mole of CH\u2084 with 2\u00b70 mole of O\u2082 according to the equation given below?
\nCH\u2084(g) + 1\/2 O\u2082 \u2192 CO + 2H\u2082<\/p>\n

[amp_mcq option1=”2\u00b70″ option2=”0\u00b75″ option3=”2\u00b75″ option4=”4\u00b70″ correct=”option1″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC CDS-2 – 2018<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
2.0 moles of CO can be obtained by reacting 2.0 mole of CH\u2084 with 2.0 mole of O\u2082.<\/section>\n
The balanced chemical equation is CH\u2084(g) + 1\/2 O\u2082 \u2192 CO + 2H\u2082. We need to determine the limiting reactant based on the initial amounts (2.0 mol CH\u2084 and 2.0 mol O\u2082).<\/section>\n
According to the stoichiometry, 1 mole of CH\u2084 reacts with 0.5 moles of O\u2082.
\nFor 2.0 moles of CH\u2084, 2.0 * 0.5 = 1.0 mole of O\u2082 is required. We have 2.0 moles of O\u2082, which is more than required. Thus, CH\u2084 is the limiting reactant.
\nThe amount of product is determined by the limiting reactant. From the equation, 1 mole of CH\u2084 produces 1 mole of CO. Therefore, 2.0 moles of CH\u2084 will produce 2.0 moles of CO.<\/section>\n","protected":false},"excerpt":{"rendered":"

How many moles of CO can be obtained by reacting 2\u00b70 mole of CH\u2084 with 2\u00b70 mole of O\u2082 according to the equation given below? CH\u2084(g) + 1\/2 O\u2082 \u2192 CO + 2H\u2082 [amp_mcq option1=”2\u00b70″ option2=”0\u00b75″ option3=”2\u00b75″ option4=”4\u00b70″ correct=”option1″] This question was previously asked in UPSC CDS-2 – 2018 Download PDFAttempt Online 2.0 moles of … <\/p>\n

Detailed SolutionHow many moles of CO can be obtained by reacting 2\u00b70 mole of CH\u2084 with<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1088],"tags":[1114,1096,1330],"class_list":["post-85800","post","type-post","status-publish","format-standard","hentry","category-upsc-cds-2","tag-1114","tag-chemistry","tag-hydrocarbons","no-featured-image-padding"],"yoast_head":"\nHow many moles of CO can be obtained by reacting 2\u00b70 mole of CH\u2084 with<\/title>\n<meta name=\"description\" content=\"2.0 moles of CO can be obtained by reacting 2.0 mole of CH\u2084 with 2.0 mole of O\u2082. The balanced chemical equation is CH\u2084(g) + 1\/2 O\u2082 \u2192 CO + 2H\u2082. We need to determine the limiting reactant based on the initial amounts (2.0 mol CH\u2084 and 2.0 mol O\u2082).\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/how-many-moles-of-co-can-be-obtained-by-reacting-2\u00b70-mole-of-ch\u2084-with\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"How many moles of CO can be obtained by reacting 2\u00b70 mole of CH\u2084 with\" \/>\n<meta property=\"og:description\" content=\"2.0 moles of CO can be obtained by reacting 2.0 mole of CH\u2084 with 2.0 mole of O\u2082. The balanced chemical equation is CH\u2084(g) + 1\/2 O\u2082 \u2192 CO + 2H\u2082. 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The balanced chemical equation is CH\u2084(g) + 1\/2 O\u2082 \u2192 CO + 2H\u2082. We need to determine the limiting reactant based on the initial amounts (2.0 mol CH\u2084 and 2.0 mol O\u2082).","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/how-many-moles-of-co-can-be-obtained-by-reacting-2\u00b70-mole-of-ch\u2084-with\/","og_locale":"en_US","og_type":"article","og_title":"How many moles of CO can be obtained by reacting 2\u00b70 mole of CH\u2084 with","og_description":"2.0 moles of CO can be obtained by reacting 2.0 mole of CH\u2084 with 2.0 mole of O\u2082. The balanced chemical equation is CH\u2084(g) + 1\/2 O\u2082 \u2192 CO + 2H\u2082. 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