{"id":85707,"date":"2025-06-01T03:25:13","date_gmt":"2025-06-01T03:25:13","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=85707"},"modified":"2025-06-01T03:25:13","modified_gmt":"2025-06-01T03:25:13","slug":"how-many-hydrogen-atoms-are-contained-in-1-50-g-of-glucose","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/how-many-hydrogen-atoms-are-contained-in-1-50-g-of-glucose\/","title":{"rendered":"How many hydrogen atoms are contained in 1.50 g of glucose"},"content":{"rendered":"

How many hydrogen atoms are contained in 1.50 g of glucose (C\u2086H\u2081\u2082O\u2086)?<\/p>\n

[amp_mcq option1=”3.01 \u00d7 10\u00b2\u00b2” option2=”1.20 \u00d7 10\u00b2\u00b3” option3=”2.40 \u00d7 10\u00b2\u00b3” option4=”6.02 \u00d7 10\u00b2\u00b2” correct=”option4″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC CDS-2 – 2017<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe correct option is D) 6.02 \u00d7 10\u00b2\u00b2 .
\n<\/section>\n
\nTo find the number of hydrogen atoms, we first need to calculate the number of moles of glucose in 1.50 g. The molar mass of glucose (C\u2086H\u2081\u2082O\u2086) is (6 \u00d7 12.01) + (12 \u00d7 1.008) + (6 \u00d7 16.00) \u2248 180.16 g\/mol (using rounded values C=12, H=1, O=16 gives 180 g\/mol).
\nNumber of moles of glucose = mass \/ molar mass = 1.50 g \/ 180 g\/mol \u2248 0.00833 moles.
\nOne molecule of glucose (C\u2086H\u2081\u2082O\u2086) contains 12 hydrogen atoms. Therefore, one mole of glucose contains 12 moles of hydrogen atoms.
\nNumber of moles of hydrogen atoms = 0.00833 mol glucose \u00d7 12 mol H atoms\/mol glucose = 0.1 moles of hydrogen atoms.
\nNumber of hydrogen atoms = moles of H atoms \u00d7 Avogadro’s number (6.022 \u00d7 10\u00b2\u00b3 atoms\/mol) = 0.1 mol \u00d7 6.022 \u00d7 10\u00b2\u00b3 atoms\/mol \u2248 0.6022 \u00d7 10\u00b2\u00b3 atoms = 6.022 \u00d7 10\u00b2\u00b2 atoms.
\n<\/section>\n
\nAvogadro’s number is the number of constituent particles (atoms, molecules, ions, etc.) that are contained in one mole of a substance, approximately 6.022 \u00d7 10\u00b2\u00b3. The formula weight calculation needs to consider the number of atoms of each element in the molecular formula.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

How many hydrogen atoms are contained in 1.50 g of glucose (C\u2086H\u2081\u2082O\u2086)? [amp_mcq option1=”3.01 \u00d7 10\u00b2\u00b2” option2=”1.20 \u00d7 10\u00b2\u00b3” option3=”2.40 \u00d7 10\u00b2\u00b3” option4=”6.02 \u00d7 10\u00b2\u00b2” correct=”option4″] This question was previously asked in UPSC CDS-2 – 2017 Download PDFAttempt Online The correct option is D) 6.02 \u00d7 10\u00b2\u00b2 . To find the number of hydrogen atoms, … <\/p>\n

Detailed SolutionHow many hydrogen atoms are contained in 1.50 g of glucose<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1088],"tags":[1101,1162,1096],"class_list":["post-85707","post","type-post","status-publish","format-standard","hentry","category-upsc-cds-2","tag-1101","tag-atomic-structure","tag-chemistry","no-featured-image-padding"],"yoast_head":"\nHow many hydrogen atoms are contained in 1.50 g of glucose<\/title>\n<meta name=\"description\" content=\"The correct option is D) 6.02 \u00d7 10\u00b2\u00b2 . To find the number of hydrogen atoms, we first need to calculate the number of moles of glucose in 1.50 g. The molar mass of glucose (C\u2086H\u2081\u2082O\u2086) is (6 \u00d7 12.01) + (12 \u00d7 1.008) + (6 \u00d7 16.00) \u2248 180.16 g\/mol (using rounded values C=12, H=1, O=16 gives 180 g\/mol). Number of moles of glucose = mass \/ molar mass = 1.50 g \/ 180 g\/mol \u2248 0.00833 moles. One molecule of glucose (C\u2086H\u2081\u2082O\u2086) contains 12 hydrogen atoms. Therefore, one mole of glucose contains 12 moles of hydrogen atoms. Number of moles of hydrogen atoms = 0.00833 mol glucose \u00d7 12 mol H atoms\/mol glucose = 0.1 moles of hydrogen atoms. Number of hydrogen atoms = moles of H atoms \u00d7 Avogadro's number (6.022 \u00d7 10\u00b2\u00b3 atoms\/mol) = 0.1 mol \u00d7 6.022 \u00d7 10\u00b2\u00b3 atoms\/mol \u2248 0.6022 \u00d7 10\u00b2\u00b3 atoms = 6.022 \u00d7 10\u00b2\u00b2 atoms.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/how-many-hydrogen-atoms-are-contained-in-1-50-g-of-glucose\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"How many hydrogen atoms are contained in 1.50 g of glucose\" \/>\n<meta property=\"og:description\" content=\"The correct option is D) 6.02 \u00d7 10\u00b2\u00b2 . To find the number of hydrogen atoms, we first need to calculate the number of moles of glucose in 1.50 g. The molar mass of glucose (C\u2086H\u2081\u2082O\u2086) is (6 \u00d7 12.01) + (12 \u00d7 1.008) + (6 \u00d7 16.00) \u2248 180.16 g\/mol (using rounded values C=12, H=1, O=16 gives 180 g\/mol). Number of moles of glucose = mass \/ molar mass = 1.50 g \/ 180 g\/mol \u2248 0.00833 moles. One molecule of glucose (C\u2086H\u2081\u2082O\u2086) contains 12 hydrogen atoms. Therefore, one mole of glucose contains 12 moles of hydrogen atoms. Number of moles of hydrogen atoms = 0.00833 mol glucose \u00d7 12 mol H atoms\/mol glucose = 0.1 moles of hydrogen atoms. Number of hydrogen atoms = moles of H atoms \u00d7 Avogadro's number (6.022 \u00d7 10\u00b2\u00b3 atoms\/mol) = 0.1 mol \u00d7 6.022 \u00d7 10\u00b2\u00b3 atoms\/mol \u2248 0.6022 \u00d7 10\u00b2\u00b3 atoms = 6.022 \u00d7 10\u00b2\u00b2 atoms.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/how-many-hydrogen-atoms-are-contained-in-1-50-g-of-glucose\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T03:25:13+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"How many hydrogen atoms are contained in 1.50 g of glucose","description":"The correct option is D) 6.02 \u00d7 10\u00b2\u00b2 . To find the number of hydrogen atoms, we first need to calculate the number of moles of glucose in 1.50 g. The molar mass of glucose (C\u2086H\u2081\u2082O\u2086) is (6 \u00d7 12.01) + (12 \u00d7 1.008) + (6 \u00d7 16.00) \u2248 180.16 g\/mol (using rounded values C=12, H=1, O=16 gives 180 g\/mol). Number of moles of glucose = mass \/ molar mass = 1.50 g \/ 180 g\/mol \u2248 0.00833 moles. One molecule of glucose (C\u2086H\u2081\u2082O\u2086) contains 12 hydrogen atoms. Therefore, one mole of glucose contains 12 moles of hydrogen atoms. Number of moles of hydrogen atoms = 0.00833 mol glucose \u00d7 12 mol H atoms\/mol glucose = 0.1 moles of hydrogen atoms. Number of hydrogen atoms = moles of H atoms \u00d7 Avogadro's number (6.022 \u00d7 10\u00b2\u00b3 atoms\/mol) = 0.1 mol \u00d7 6.022 \u00d7 10\u00b2\u00b3 atoms\/mol \u2248 0.6022 \u00d7 10\u00b2\u00b3 atoms = 6.022 \u00d7 10\u00b2\u00b2 atoms.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/how-many-hydrogen-atoms-are-contained-in-1-50-g-of-glucose\/","og_locale":"en_US","og_type":"article","og_title":"How many hydrogen atoms are contained in 1.50 g of glucose","og_description":"The correct option is D) 6.02 \u00d7 10\u00b2\u00b2 . To find the number of hydrogen atoms, we first need to calculate the number of moles of glucose in 1.50 g. The molar mass of glucose (C\u2086H\u2081\u2082O\u2086) is (6 \u00d7 12.01) + (12 \u00d7 1.008) + (6 \u00d7 16.00) \u2248 180.16 g\/mol (using rounded values C=12, H=1, O=16 gives 180 g\/mol). Number of moles of glucose = mass \/ molar mass = 1.50 g \/ 180 g\/mol \u2248 0.00833 moles. One molecule of glucose (C\u2086H\u2081\u2082O\u2086) contains 12 hydrogen atoms. Therefore, one mole of glucose contains 12 moles of hydrogen atoms. Number of moles of hydrogen atoms = 0.00833 mol glucose \u00d7 12 mol H atoms\/mol glucose = 0.1 moles of hydrogen atoms. Number of hydrogen atoms = moles of H atoms \u00d7 Avogadro's number (6.022 \u00d7 10\u00b2\u00b3 atoms\/mol) = 0.1 mol \u00d7 6.022 \u00d7 10\u00b2\u00b3 atoms\/mol \u2248 0.6022 \u00d7 10\u00b2\u00b3 atoms = 6.022 \u00d7 10\u00b2\u00b2 atoms.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/how-many-hydrogen-atoms-are-contained-in-1-50-g-of-glucose\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T03:25:13+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/how-many-hydrogen-atoms-are-contained-in-1-50-g-of-glucose\/","url":"https:\/\/exam.pscnotes.com\/mcq\/how-many-hydrogen-atoms-are-contained-in-1-50-g-of-glucose\/","name":"How many hydrogen atoms are contained in 1.50 g of glucose","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T03:25:13+00:00","dateModified":"2025-06-01T03:25:13+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The correct option is D) 6.02 \u00d7 10\u00b2\u00b2 . To find the number of hydrogen atoms, we first need to calculate the number of moles of glucose in 1.50 g. The molar mass of glucose (C\u2086H\u2081\u2082O\u2086) is (6 \u00d7 12.01) + (12 \u00d7 1.008) + (6 \u00d7 16.00) \u2248 180.16 g\/mol (using rounded values C=12, H=1, O=16 gives 180 g\/mol). Number of moles of glucose = mass \/ molar mass = 1.50 g \/ 180 g\/mol \u2248 0.00833 moles. One molecule of glucose (C\u2086H\u2081\u2082O\u2086) contains 12 hydrogen atoms. Therefore, one mole of glucose contains 12 moles of hydrogen atoms. Number of moles of hydrogen atoms = 0.00833 mol glucose \u00d7 12 mol H atoms\/mol glucose = 0.1 moles of hydrogen atoms. Number of hydrogen atoms = moles of H atoms \u00d7 Avogadro's number (6.022 \u00d7 10\u00b2\u00b3 atoms\/mol) = 0.1 mol \u00d7 6.022 \u00d7 10\u00b2\u00b3 atoms\/mol \u2248 0.6022 \u00d7 10\u00b2\u00b3 atoms = 6.022 \u00d7 10\u00b2\u00b2 atoms.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/how-many-hydrogen-atoms-are-contained-in-1-50-g-of-glucose\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/how-many-hydrogen-atoms-are-contained-in-1-50-g-of-glucose\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/how-many-hydrogen-atoms-are-contained-in-1-50-g-of-glucose\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC CDS-2","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-cds-2\/"},{"@type":"ListItem","position":3,"name":"How many hydrogen atoms are contained in 1.50 g of glucose"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/85707","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=85707"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/85707\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=85707"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=85707"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=85707"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}