{"id":85705,"date":"2025-06-01T03:25:11","date_gmt":"2025-06-01T03:25:11","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=85705"},"modified":"2025-06-01T03:25:11","modified_gmt":"2025-06-01T03:25:11","slug":"a-person-is-standing-on-a-frictionless-horizontal-ground-how-can-he-m","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/a-person-is-standing-on-a-frictionless-horizontal-ground-how-can-he-m\/","title":{"rendered":"A person is standing on a frictionless horizontal ground. How can he m"},"content":{"rendered":"

A person is standing on a frictionless horizontal ground. How can he move by a certain distance on this ground?<\/p>\n

[amp_mcq option1=”By sneezing” option2=”By jumping” option3=”By running” option4=”By rolling” correct=”option1″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC CDS-2 – 2017<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe correct option is A) By sneezing.
\n<\/section>\n
\nOn a frictionless horizontal surface, a person cannot propel themselves forward by pushing against the ground (like walking, running, or jumping) because there is no friction to provide an external reaction force in the horizontal direction. However, by sneezing, the person expels air in one direction. According to Newton’s third law of motion, this action creates an equal and opposite reaction force on the person’s body, propelling them in the opposite direction of the expelled air.
\n<\/section>\n
\nThis is a classic physics problem illustrating Newton’s laws of motion, particularly the conservation of momentum. In the absence of external forces (friction), the total momentum of the person-air system remains constant. If the person expels air with a certain momentum, their body must acquire an equal and opposite momentum to conserve the total momentum (initially zero).
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

A person is standing on a frictionless horizontal ground. How can he move by a certain distance on this ground? [amp_mcq option1=”By sneezing” option2=”By jumping” option3=”By running” option4=”By rolling” correct=”option1″] This question was previously asked in UPSC CDS-2 – 2017 Download PDFAttempt Online The correct option is A) By sneezing. On a frictionless horizontal surface, … <\/p>\n

Detailed SolutionA person is standing on a frictionless horizontal ground. How can he m<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1088],"tags":[1101,1129,1128],"class_list":["post-85705","post","type-post","status-publish","format-standard","hentry","category-upsc-cds-2","tag-1101","tag-mechanics","tag-physics","no-featured-image-padding"],"yoast_head":"\nA person is standing on a frictionless horizontal ground. How can he m<\/title>\n<meta name=\"description\" content=\"The correct option is A) By sneezing. On a frictionless horizontal surface, a person cannot propel themselves forward by pushing against the ground (like walking, running, or jumping) because there is no friction to provide an external reaction force in the horizontal direction. However, by sneezing, the person expels air in one direction. 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