{"id":85218,"date":"2025-06-01T03:08:01","date_gmt":"2025-06-01T03:08:01","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=85218"},"modified":"2025-06-01T03:08:01","modified_gmt":"2025-06-01T03:08:01","slug":"the-number-of-moles-of-oxygen-gas-used-in-the-complete-combustion-of-1","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/the-number-of-moles-of-oxygen-gas-used-in-the-complete-combustion-of-1\/","title":{"rendered":"The number of moles of oxygen gas used in the complete combustion of 1"},"content":{"rendered":"

The number of moles of oxygen gas used in the complete combustion of 1 mole of glucose is :<\/p>\n

[amp_mcq option1=”1″ option2=”3″ option3=”6″ option4=”12″ correct=”option3″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC CDS-1 – 2022<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe balanced chemical equation for the complete combustion of glucose (C6H12O6) shows that 1 mole of glucose reacts with 6 moles of oxygen gas (O2).
\n<\/section>\n
\nComplete combustion of a hydrocarbon or carbohydrate involves reaction with sufficient oxygen to produce carbon dioxide (CO2) and water (H2O). Balancing the chemical equation ensures that the number of atoms of each element is the same on both the reactant and product sides, representing the stoichiometric ratios.
\n<\/section>\n
\nThe balanced combustion reaction for glucose is: C6H12O6(s) + 6O2(g) -> 6CO2(g) + 6H2O(l). From this equation, the molar ratio of glucose to oxygen is 1:6. Therefore, 1 mole of glucose requires 6 moles of oxygen gas for complete combustion.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

The number of moles of oxygen gas used in the complete combustion of 1 mole of glucose is : [amp_mcq option1=”1″ option2=”3″ option3=”6″ option4=”12″ correct=”option3″] This question was previously asked in UPSC CDS-1 – 2022 Download PDFAttempt Online The balanced chemical equation for the complete combustion of glucose (C6H12O6) shows that 1 mole of glucose … <\/p>\n

Detailed SolutionThe number of moles of oxygen gas used in the complete combustion of 1<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1087],"tags":[1108,1096,1155],"class_list":["post-85218","post","type-post","status-publish","format-standard","hentry","category-upsc-cds-1","tag-1108","tag-chemistry","tag-physical-and-chemical-changes-solution","no-featured-image-padding"],"yoast_head":"\nThe number of moles of oxygen gas used in the complete combustion of 1<\/title>\n<meta name=\"description\" content=\"The balanced chemical equation for the complete combustion of glucose (C6H12O6) shows that 1 mole of glucose reacts with 6 moles of oxygen gas (O2). Complete combustion of a hydrocarbon or carbohydrate involves reaction with sufficient oxygen to produce carbon dioxide (CO2) and water (H2O). 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