{"id":84997,"date":"2025-06-01T02:59:20","date_gmt":"2025-06-01T02:59:20","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=84997"},"modified":"2025-06-01T02:59:20","modified_gmt":"2025-06-01T02:59:20","slug":"the-resistivity-rho-of-a-material-may-be-expressed-in-units-of","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/the-resistivity-rho-of-a-material-may-be-expressed-in-units-of\/","title":{"rendered":"The resistivity $\\rho$ of a material may be expressed in units of"},"content":{"rendered":"

The resistivity $\\rho$ of a material may be expressed in units of<\/p>\n

[amp_mcq option1=”ohm” option2=”ohm\/cm” option3=”ohm-cm” option4=”ohm-cm$^2$” correct=”option3″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC CDS-1 – 2020<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nResistivity ($\\rho$) is a fundamental property of a material that quantifies how strongly it resists the flow of electric current. Resistance ($R$) of a conductor is related to its resistivity, length ($L$), and cross-sectional area ($A$) by the formula $R = \\rho \\frac{L}{A}$. Rearranging this formula to solve for $\\rho$, we get $\\rho = R \\frac{A}{L}$.
\n<\/section>\n
\nThe unit of resistance ($R$) is Ohm ($\\Omega$). The unit of area ($A$) is typically square meters (m\u00b2) or square centimeters (cm\u00b2). The unit of length ($L$) is typically meters (m) or centimeters (cm). Substituting these units into the formula for $\\rho$: $\\text{Units of } \\rho = \\Omega \\times \\frac{\\text{cm}^2}{\\text{cm}} = \\Omega \\cdot \\text{cm}$. Alternatively, using meters: $\\text{Units of } \\rho = \\Omega \\times \\frac{\\text{m}^2}{\\text{m}} = \\Omega \\cdot \\text{m}$. Therefore, the resistivity is commonly expressed in ohm-centimeters ($\\Omega \\cdot \\text{cm}$) or ohm-meters ($\\Omega \\cdot \\text{m}$).
\n<\/section>\n
\nWhile both ohm-meter ($\\Omega \\cdot \\text{m}$) and ohm-centimeter ($\\Omega \\cdot \\text{cm}$) are valid units for resistivity, ohm-centimeter is also widely used, particularly in semiconductor physics and some older standards. Option C correctly identifies ohm-cm as a unit for resistivity.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

The resistivity $\\rho$ of a material may be expressed in units of [amp_mcq option1=”ohm” option2=”ohm\/cm” option3=”ohm-cm” option4=”ohm-cm$^2$” correct=”option3″] This question was previously asked in UPSC CDS-1 – 2020 Download PDFAttempt Online Resistivity ($\\rho$) is a fundamental property of a material that quantifies how strongly it resists the flow of electric current. Resistance ($R$) of a … <\/p>\n

Detailed SolutionThe resistivity $\\rho$ of a material may be expressed in units of<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1087],"tags":[1288,1140,1128],"class_list":["post-84997","post","type-post","status-publish","format-standard","hentry","category-upsc-cds-1","tag-1288","tag-measurement-unit","tag-physics","no-featured-image-padding"],"yoast_head":"\nThe resistivity $\\rho$ of a material may be expressed in units of<\/title>\n<meta name=\"description\" content=\"Resistivity ($rho$) is a fundamental property of a material that quantifies how strongly it resists the flow of electric current. Resistance ($R$) of a conductor is related to its resistivity, length ($L$), and cross-sectional area ($A$) by the formula $R = rho frac{L}{A}$. Rearranging this formula to solve for $rho$, we get $rho = R frac{A}{L}$. The unit of resistance ($R$) is Ohm ($Omega$). The unit of area ($A$) is typically square meters (m\u00b2) or square centimeters (cm\u00b2). The unit of length ($L$) is typically meters (m) or centimeters (cm). Substituting these units into the formula for $rho$: $text{Units of } rho = Omega times frac{text{cm}^2}{text{cm}} = Omega cdot text{cm}$. Alternatively, using meters: $text{Units of } rho = Omega times frac{text{m}^2}{text{m}} = Omega cdot text{m}$. Therefore, the resistivity is commonly expressed in ohm-centimeters ($Omega cdot text{cm}$) or ohm-meters ($Omega cdot text{m}$).\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/the-resistivity-rho-of-a-material-may-be-expressed-in-units-of\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"The resistivity $\\rho$ of a material may be expressed in units of\" \/>\n<meta property=\"og:description\" content=\"Resistivity ($rho$) is a fundamental property of a material that quantifies how strongly it resists the flow of electric current. Resistance ($R$) of a conductor is related to its resistivity, length ($L$), and cross-sectional area ($A$) by the formula $R = rho frac{L}{A}$. Rearranging this formula to solve for $rho$, we get $rho = R frac{A}{L}$. The unit of resistance ($R$) is Ohm ($Omega$). The unit of area ($A$) is typically square meters (m\u00b2) or square centimeters (cm\u00b2). The unit of length ($L$) is typically meters (m) or centimeters (cm). Substituting these units into the formula for $rho$: $text{Units of } rho = Omega times frac{text{cm}^2}{text{cm}} = Omega cdot text{cm}$. Alternatively, using meters: $text{Units of } rho = Omega times frac{text{m}^2}{text{m}} = Omega cdot text{m}$. Therefore, the resistivity is commonly expressed in ohm-centimeters ($Omega cdot text{cm}$) or ohm-meters ($Omega cdot text{m}$).\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/the-resistivity-rho-of-a-material-may-be-expressed-in-units-of\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T02:59:20+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"The resistivity $\\rho$ of a material may be expressed in units of","description":"Resistivity ($rho$) is a fundamental property of a material that quantifies how strongly it resists the flow of electric current. Resistance ($R$) of a conductor is related to its resistivity, length ($L$), and cross-sectional area ($A$) by the formula $R = rho frac{L}{A}$. Rearranging this formula to solve for $rho$, we get $rho = R frac{A}{L}$. The unit of resistance ($R$) is Ohm ($Omega$). The unit of area ($A$) is typically square meters (m\u00b2) or square centimeters (cm\u00b2). The unit of length ($L$) is typically meters (m) or centimeters (cm). Substituting these units into the formula for $rho$: $text{Units of } rho = Omega times frac{text{cm}^2}{text{cm}} = Omega cdot text{cm}$. Alternatively, using meters: $text{Units of } rho = Omega times frac{text{m}^2}{text{m}} = Omega cdot text{m}$. Therefore, the resistivity is commonly expressed in ohm-centimeters ($Omega cdot text{cm}$) or ohm-meters ($Omega cdot text{m}$).","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/the-resistivity-rho-of-a-material-may-be-expressed-in-units-of\/","og_locale":"en_US","og_type":"article","og_title":"The resistivity $\\rho$ of a material may be expressed in units of","og_description":"Resistivity ($rho$) is a fundamental property of a material that quantifies how strongly it resists the flow of electric current. Resistance ($R$) of a conductor is related to its resistivity, length ($L$), and cross-sectional area ($A$) by the formula $R = rho frac{L}{A}$. Rearranging this formula to solve for $rho$, we get $rho = R frac{A}{L}$. The unit of resistance ($R$) is Ohm ($Omega$). The unit of area ($A$) is typically square meters (m\u00b2) or square centimeters (cm\u00b2). The unit of length ($L$) is typically meters (m) or centimeters (cm). Substituting these units into the formula for $rho$: $text{Units of } rho = Omega times frac{text{cm}^2}{text{cm}} = Omega cdot text{cm}$. Alternatively, using meters: $text{Units of } rho = Omega times frac{text{m}^2}{text{m}} = Omega cdot text{m}$. Therefore, the resistivity is commonly expressed in ohm-centimeters ($Omega cdot text{cm}$) or ohm-meters ($Omega cdot text{m}$).","og_url":"https:\/\/exam.pscnotes.com\/mcq\/the-resistivity-rho-of-a-material-may-be-expressed-in-units-of\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T02:59:20+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/the-resistivity-rho-of-a-material-may-be-expressed-in-units-of\/","url":"https:\/\/exam.pscnotes.com\/mcq\/the-resistivity-rho-of-a-material-may-be-expressed-in-units-of\/","name":"The resistivity $\\rho$ of a material may be expressed in units of","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T02:59:20+00:00","dateModified":"2025-06-01T02:59:20+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"Resistivity ($\\rho$) is a fundamental property of a material that quantifies how strongly it resists the flow of electric current. Resistance ($R$) of a conductor is related to its resistivity, length ($L$), and cross-sectional area ($A$) by the formula $R = \\rho \\frac{L}{A}$. Rearranging this formula to solve for $\\rho$, we get $\\rho = R \\frac{A}{L}$. The unit of resistance ($R$) is Ohm ($\\Omega$). The unit of area ($A$) is typically square meters (m\u00b2) or square centimeters (cm\u00b2). The unit of length ($L$) is typically meters (m) or centimeters (cm). Substituting these units into the formula for $\\rho$: $\\text{Units of } \\rho = \\Omega \\times \\frac{\\text{cm}^2}{\\text{cm}} = \\Omega \\cdot \\text{cm}$. Alternatively, using meters: $\\text{Units of } \\rho = \\Omega \\times \\frac{\\text{m}^2}{\\text{m}} = \\Omega \\cdot \\text{m}$. Therefore, the resistivity is commonly expressed in ohm-centimeters ($\\Omega \\cdot \\text{cm}$) or ohm-meters ($\\Omega \\cdot \\text{m}$).","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/the-resistivity-rho-of-a-material-may-be-expressed-in-units-of\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/the-resistivity-rho-of-a-material-may-be-expressed-in-units-of\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/the-resistivity-rho-of-a-material-may-be-expressed-in-units-of\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC CDS-1","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-cds-1\/"},{"@type":"ListItem","position":3,"name":"The resistivity $\\rho$ of a material may be expressed in units of"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/84997","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=84997"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/84997\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=84997"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=84997"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=84997"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}