{"id":84740,"date":"2025-06-01T02:48:04","date_gmt":"2025-06-01T02:48:04","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=84740"},"modified":"2025-06-01T02:48:04","modified_gmt":"2025-06-01T02:48:04","slug":"consider-the-following-chemical-reaction-afe%e2%82%82o%e2%82%83s-bcog-%e2%86%92-cfes","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-chemical-reaction-afe%e2%82%82o%e2%82%83s-bcog-%e2%86%92-cfes\/","title":{"rendered":"Consider the following chemical reaction :\naFe\u2082O\u2083(s) + bCO(g) \u2192 cFe(s)"},"content":{"rendered":"<p>Consider the following chemical reaction :<br \/>\naFe\u2082O\u2083(s) + bCO(g) \u2192 cFe(s) + dCO\u2082<br \/>\nIn the balanced chemical equation of the above, which of the following will be the values of the coefficients a, b, c and d respectively?<\/p>\n<p>[amp_mcq option1=&#8221;3, 2, 3, 1&#8243; option2=&#8221;1, 3, 2, 3&#8243; option3=&#8221;2, 3, 3, 1&#8243; option4=&#8221;3, 3, 2, 1&#8243; correct=&#8221;option2&#8243;]<\/p>\n<div class=\"psc-box-pyq-exam-year-detail\">\n<div class=\"pyq-exam\">\n<div class=\"psc-heading\">This question was previously asked in<\/div>\n<div class=\"psc-title line-ellipsis\">UPSC CDS-1 &#8211; 2018<\/div>\n<\/div>\n<div class=\"pyq-exam-psc-buttons\"><a href=\"\/pyq\/pyq-upsc-cds-1-2018.pdf\" target=\"_blank\" class=\"psc-pdf-button\" rel=\"noopener\">Download PDF<\/a><a href=\"\/pyq-upsc-cds-1-2018\" target=\"_blank\" class=\"psc-attempt-button\" rel=\"noopener\">Attempt Online<\/a><\/div>\n<\/div>\n<section id=\"pyq-correct-answer\">\nThe given chemical reaction is the reduction of iron(III) oxide by carbon monoxide: Fe\u2082O\u2083(s) + CO(g) \u2192 Fe(s) + CO\u2082(g). To balance the equation aFe\u2082O\u2083 + bCO \u2192 cFe + dCO\u2082, we balance the atoms of each element:<br \/>\n&#8211; Fe: 2a = c<br \/>\n&#8211; O: 3a + b = 2d<br \/>\n&#8211; C: b = d<br \/>\nSubstituting b=d into the oxygen balance: 3a + d = 2d, which gives 3a = d.<br \/>\nSo we have the relationships: c = 2a, b = 3a, d = 3a.<br \/>\nTo find the smallest integer coefficients, we can set a=1.<br \/>\nThen, b = 3(1) = 3, c = 2(1) = 2, d = 3(1) = 3.<br \/>\nThe coefficients are a=1, b=3, c=2, d=3. This corresponds to option B.<br \/>\n<\/section>\n<section id=\"pyq-key-points\">\n&#8211; Balancing chemical equations involves ensuring the number of atoms of each element is the same on both the reactant and product sides.<br \/>\n&#8211; Coefficients represent the relative number of molecules or moles involved in the reaction.<br \/>\n&#8211; Balancing is achieved by using stoichiometric coefficients in front of the chemical formulas.<br \/>\n<\/section>\n<section id=\"pyq-additional-information\">\nThis reaction is a key process in the blast furnace for smelting iron ore, where iron(III) oxide is reduced by carbon monoxide produced from the combustion of coke. The balanced equation shows that one molecule of iron(III) oxide reacts with three molecules of carbon monoxide to produce two atoms of iron and three molecules of carbon dioxide.<br \/>\n<\/section>\n","protected":false},"excerpt":{"rendered":"<p>Consider the following chemical reaction : aFe\u2082O\u2083(s) + bCO(g) \u2192 cFe(s) + dCO\u2082 In the balanced chemical equation of the above, which of the following will be the values of the coefficients a, b, c and d respectively? [amp_mcq option1=&#8221;3, 2, 3, 1&#8243; option2=&#8221;1, 3, 2, 3&#8243; option3=&#8221;2, 3, 3, 1&#8243; option4=&#8221;3, 3, 2, 1&#8243; &#8230; <\/p>\n<p class=\"read-more-container\"><a title=\"Consider the following chemical reaction :\naFe\u2082O\u2083(s) + bCO(g) \u2192 cFe(s)\" class=\"read-more button\" href=\"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-chemical-reaction-afe%e2%82%82o%e2%82%83s-bcog-%e2%86%92-cfes\/#more-84740\">Detailed Solution<span class=\"screen-reader-text\">Consider the following chemical reaction :<br \/>\naFe\u2082O\u2083(s) + bCO(g) \u2192 cFe(s)<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1087],"tags":[1114,1096,1239],"class_list":["post-84740","post","type-post","status-publish","format-standard","hentry","category-upsc-cds-1","tag-1114","tag-chemistry","tag-inorganic-chemistry","no-featured-image-padding"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Consider the following chemical reaction : aFe\u2082O\u2083(s) + bCO(g) \u2192 cFe(s)<\/title>\n<meta name=\"description\" content=\"The given chemical reaction is the reduction of iron(III) oxide by carbon monoxide: Fe\u2082O\u2083(s) + CO(g) \u2192 Fe(s) + CO\u2082(g). To balance the equation aFe\u2082O\u2083 + bCO \u2192 cFe + dCO\u2082, we balance the atoms of each element: - Fe: 2a = c - O: 3a + b = 2d - C: b = d Substituting b=d into the oxygen balance: 3a + d = 2d, which gives 3a = d. So we have the relationships: c = 2a, b = 3a, d = 3a. To find the smallest integer coefficients, we can set a=1. Then, b = 3(1) = 3, c = 2(1) = 2, d = 3(1) = 3. The coefficients are a=1, b=3, c=2, d=3. This corresponds to option B. - Balancing chemical equations involves ensuring the number of atoms of each element is the same on both the reactant and product sides. - Coefficients represent the relative number of molecules or moles involved in the reaction. - Balancing is achieved by using stoichiometric coefficients in front of the chemical formulas.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-chemical-reaction-afe\u2082o\u2083s-bcog-\u2192-cfes\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Consider the following chemical reaction : aFe\u2082O\u2083(s) + bCO(g) \u2192 cFe(s)\" \/>\n<meta property=\"og:description\" content=\"The given chemical reaction is the reduction of iron(III) oxide by carbon monoxide: Fe\u2082O\u2083(s) + CO(g) \u2192 Fe(s) + CO\u2082(g). To balance the equation aFe\u2082O\u2083 + bCO \u2192 cFe + dCO\u2082, we balance the atoms of each element: - Fe: 2a = c - O: 3a + b = 2d - C: b = d Substituting b=d into the oxygen balance: 3a + d = 2d, which gives 3a = d. So we have the relationships: c = 2a, b = 3a, d = 3a. To find the smallest integer coefficients, we can set a=1. Then, b = 3(1) = 3, c = 2(1) = 2, d = 3(1) = 3. The coefficients are a=1, b=3, c=2, d=3. This corresponds to option B. - Balancing chemical equations involves ensuring the number of atoms of each element is the same on both the reactant and product sides. - Coefficients represent the relative number of molecules or moles involved in the reaction. - Balancing is achieved by using stoichiometric coefficients in front of the chemical formulas.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-chemical-reaction-afe\u2082o\u2083s-bcog-\u2192-cfes\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T02:48:04+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"Consider the following chemical reaction : aFe\u2082O\u2083(s) + bCO(g) \u2192 cFe(s)","description":"The given chemical reaction is the reduction of iron(III) oxide by carbon monoxide: Fe\u2082O\u2083(s) + CO(g) \u2192 Fe(s) + CO\u2082(g). To balance the equation aFe\u2082O\u2083 + bCO \u2192 cFe + dCO\u2082, we balance the atoms of each element: - Fe: 2a = c - O: 3a + b = 2d - C: b = d Substituting b=d into the oxygen balance: 3a + d = 2d, which gives 3a = d. So we have the relationships: c = 2a, b = 3a, d = 3a. To find the smallest integer coefficients, we can set a=1. Then, b = 3(1) = 3, c = 2(1) = 2, d = 3(1) = 3. The coefficients are a=1, b=3, c=2, d=3. This corresponds to option B. - Balancing chemical equations involves ensuring the number of atoms of each element is the same on both the reactant and product sides. - Coefficients represent the relative number of molecules or moles involved in the reaction. - Balancing is achieved by using stoichiometric coefficients in front of the chemical formulas.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-chemical-reaction-afe\u2082o\u2083s-bcog-\u2192-cfes\/","og_locale":"en_US","og_type":"article","og_title":"Consider the following chemical reaction : aFe\u2082O\u2083(s) + bCO(g) \u2192 cFe(s)","og_description":"The given chemical reaction is the reduction of iron(III) oxide by carbon monoxide: Fe\u2082O\u2083(s) + CO(g) \u2192 Fe(s) + CO\u2082(g). To balance the equation aFe\u2082O\u2083 + bCO \u2192 cFe + dCO\u2082, we balance the atoms of each element: - Fe: 2a = c - O: 3a + b = 2d - C: b = d Substituting b=d into the oxygen balance: 3a + d = 2d, which gives 3a = d. So we have the relationships: c = 2a, b = 3a, d = 3a. To find the smallest integer coefficients, we can set a=1. Then, b = 3(1) = 3, c = 2(1) = 2, d = 3(1) = 3. The coefficients are a=1, b=3, c=2, d=3. This corresponds to option B. - Balancing chemical equations involves ensuring the number of atoms of each element is the same on both the reactant and product sides. - Coefficients represent the relative number of molecules or moles involved in the reaction. - Balancing is achieved by using stoichiometric coefficients in front of the chemical formulas.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-chemical-reaction-afe\u2082o\u2083s-bcog-\u2192-cfes\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T02:48:04+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-chemical-reaction-afe%e2%82%82o%e2%82%83s-bcog-%e2%86%92-cfes\/","url":"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-chemical-reaction-afe%e2%82%82o%e2%82%83s-bcog-%e2%86%92-cfes\/","name":"Consider the following chemical reaction : aFe\u2082O\u2083(s) + bCO(g) \u2192 cFe(s)","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T02:48:04+00:00","dateModified":"2025-06-01T02:48:04+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The given chemical reaction is the reduction of iron(III) oxide by carbon monoxide: Fe\u2082O\u2083(s) + CO(g) \u2192 Fe(s) + CO\u2082(g). To balance the equation aFe\u2082O\u2083 + bCO \u2192 cFe + dCO\u2082, we balance the atoms of each element: - Fe: 2a = c - O: 3a + b = 2d - C: b = d Substituting b=d into the oxygen balance: 3a + d = 2d, which gives 3a = d. So we have the relationships: c = 2a, b = 3a, d = 3a. To find the smallest integer coefficients, we can set a=1. Then, b = 3(1) = 3, c = 2(1) = 2, d = 3(1) = 3. The coefficients are a=1, b=3, c=2, d=3. This corresponds to option B. - Balancing chemical equations involves ensuring the number of atoms of each element is the same on both the reactant and product sides. - Coefficients represent the relative number of molecules or moles involved in the reaction. - Balancing is achieved by using stoichiometric coefficients in front of the chemical formulas.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-chemical-reaction-afe%e2%82%82o%e2%82%83s-bcog-%e2%86%92-cfes\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-chemical-reaction-afe%e2%82%82o%e2%82%83s-bcog-%e2%86%92-cfes\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/consider-the-following-chemical-reaction-afe%e2%82%82o%e2%82%83s-bcog-%e2%86%92-cfes\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC CDS-1","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-cds-1\/"},{"@type":"ListItem","position":3,"name":"Consider the following chemical reaction : aFe\u2082O\u2083(s) + bCO(g) \u2192 cFe(s)"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/84740","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=84740"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/84740\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=84740"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=84740"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=84740"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}