{"id":84650,"date":"2025-06-01T02:43:20","date_gmt":"2025-06-01T02:43:20","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=84650"},"modified":"2025-06-01T02:43:20","modified_gmt":"2025-06-01T02:43:20","slug":"a-parallel-plate-capacitor-of-capacitance-c%e2%82%81-is-made-using-two-gold-pl","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/a-parallel-plate-capacitor-of-capacitance-c%e2%82%81-is-made-using-two-gold-pl\/","title":{"rendered":"A parallel-plate capacitor of capacitance C\u2081 is made using two gold pl"},"content":{"rendered":"

A parallel-plate capacitor of capacitance C\u2081 is made using two gold plates. Another parallel-plate capacitor of capacitance C\u2082 is made using two aluminium plates with same plate separation, and all the four plates are of same area. If \u03c1g and \u03c1a are respectively resistivities of gold and aluminium, then which one of the following relations is correct?<\/p>\n

[amp_mcq option1=”C\u2081 > C\u2082” option2=”C\u2082 > C\u2081” option3=”C\u2081\u03c1a = C\u2082\u03c1g” option4=”C\u2081 = C\u2082” correct=”option4″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC CDS-1 – 2017<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe capacitance of a parallel-plate capacitor is given by the formula C = \u03b5 * (A\/d), where \u03b5 is the permittivity of the dielectric material between the plates, A is the area of one plate, and d is the distance between the plates.
\n<\/section>\n
\n– The problem states that both capacitors have the same plate separation (d) and the four plates are of the same area (meaning the plates for C\u2081 have area A, and the plates for C\u2082 also have area A).
\n– The plates are made of gold and aluminium. These materials are conductors and form the plates; they are not the dielectric material filling the space between the plates. The dielectric material between the plates is presumably the same for both capacitors (usually air or vacuum unless specified otherwise).
\n– Since A, d, and the dielectric material (and thus its permittivity \u03b5) are the same for both capacitors, their capacitances must be equal.
\n– The resistivities of gold (\u03c1g) and aluminium (\u03c1a) are properties of the plate materials themselves and do not affect the capacitance value, which is determined by the geometry of the plates and the material *between* them.
\n<\/section>\n
\nThe capacitance of a capacitor depends on its physical dimensions (area and separation of plates) and the dielectric properties of the material filling the space between the plates. The conductive material of the plates affects properties like resistance and conductivity, but not the capacitance itself in the standard parallel-plate model.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

A parallel-plate capacitor of capacitance C\u2081 is made using two gold plates. Another parallel-plate capacitor of capacitance C\u2082 is made using two aluminium plates with same plate separation, and all the four plates are of same area. If \u03c1g and \u03c1a are respectively resistivities of gold and aluminium, then which one of the following relations … <\/p>\n

Detailed SolutionA parallel-plate capacitor of capacitance C\u2081 is made using two gold pl<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1087],"tags":[1101,1200,1128],"class_list":["post-84650","post","type-post","status-publish","format-standard","hentry","category-upsc-cds-1","tag-1101","tag-conductivity","tag-physics","no-featured-image-padding"],"yoast_head":"\nA parallel-plate capacitor of capacitance C\u2081 is made using two gold pl<\/title>\n<meta name=\"description\" content=\"The capacitance of a parallel-plate capacitor is given by the formula C = \u03b5 * (A\/d), where \u03b5 is the permittivity of the dielectric material between the plates, A is the area of one plate, and d is the distance between the plates. - The problem states that both capacitors have the same plate separation (d) and the four plates are of the same area (meaning the plates for C\u2081 have area A, and the plates for C\u2082 also have area A). - The plates are made of gold and aluminium. These materials are conductors and form the plates; they are not the dielectric material filling the space between the plates. The dielectric material between the plates is presumably the same for both capacitors (usually air or vacuum unless specified otherwise). - Since A, d, and the dielectric material (and thus its permittivity \u03b5) are the same for both capacitors, their capacitances must be equal. - The resistivities of gold (\u03c1g) and aluminium (\u03c1a) are properties of the plate materials themselves and do not affect the capacitance value, which is determined by the geometry of the plates and the material *between* them.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/a-parallel-plate-capacitor-of-capacitance-c\u2081-is-made-using-two-gold-pl\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"A parallel-plate capacitor of capacitance C\u2081 is made using two gold pl\" \/>\n<meta property=\"og:description\" content=\"The capacitance of a parallel-plate capacitor is given by the formula C = \u03b5 * (A\/d), where \u03b5 is the permittivity of the dielectric material between the plates, A is the area of one plate, and d is the distance between the plates. - The problem states that both capacitors have the same plate separation (d) and the four plates are of the same area (meaning the plates for C\u2081 have area A, and the plates for C\u2082 also have area A). - The plates are made of gold and aluminium. These materials are conductors and form the plates; they are not the dielectric material filling the space between the plates. The dielectric material between the plates is presumably the same for both capacitors (usually air or vacuum unless specified otherwise). - Since A, d, and the dielectric material (and thus its permittivity \u03b5) are the same for both capacitors, their capacitances must be equal. - The resistivities of gold (\u03c1g) and aluminium (\u03c1a) are properties of the plate materials themselves and do not affect the capacitance value, which is determined by the geometry of the plates and the material *between* them.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/a-parallel-plate-capacitor-of-capacitance-c\u2081-is-made-using-two-gold-pl\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T02:43:20+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"2 minutes\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"A parallel-plate capacitor of capacitance C\u2081 is made using two gold pl","description":"The capacitance of a parallel-plate capacitor is given by the formula C = \u03b5 * (A\/d), where \u03b5 is the permittivity of the dielectric material between the plates, A is the area of one plate, and d is the distance between the plates. - The problem states that both capacitors have the same plate separation (d) and the four plates are of the same area (meaning the plates for C\u2081 have area A, and the plates for C\u2082 also have area A). - The plates are made of gold and aluminium. These materials are conductors and form the plates; they are not the dielectric material filling the space between the plates. The dielectric material between the plates is presumably the same for both capacitors (usually air or vacuum unless specified otherwise). - Since A, d, and the dielectric material (and thus its permittivity \u03b5) are the same for both capacitors, their capacitances must be equal. - The resistivities of gold (\u03c1g) and aluminium (\u03c1a) are properties of the plate materials themselves and do not affect the capacitance value, which is determined by the geometry of the plates and the material *between* them.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/a-parallel-plate-capacitor-of-capacitance-c\u2081-is-made-using-two-gold-pl\/","og_locale":"en_US","og_type":"article","og_title":"A parallel-plate capacitor of capacitance C\u2081 is made using two gold pl","og_description":"The capacitance of a parallel-plate capacitor is given by the formula C = \u03b5 * (A\/d), where \u03b5 is the permittivity of the dielectric material between the plates, A is the area of one plate, and d is the distance between the plates. - The problem states that both capacitors have the same plate separation (d) and the four plates are of the same area (meaning the plates for C\u2081 have area A, and the plates for C\u2082 also have area A). - The plates are made of gold and aluminium. These materials are conductors and form the plates; they are not the dielectric material filling the space between the plates. The dielectric material between the plates is presumably the same for both capacitors (usually air or vacuum unless specified otherwise). - Since A, d, and the dielectric material (and thus its permittivity \u03b5) are the same for both capacitors, their capacitances must be equal. - The resistivities of gold (\u03c1g) and aluminium (\u03c1a) are properties of the plate materials themselves and do not affect the capacitance value, which is determined by the geometry of the plates and the material *between* them.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/a-parallel-plate-capacitor-of-capacitance-c\u2081-is-made-using-two-gold-pl\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T02:43:20+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"2 minutes"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/a-parallel-plate-capacitor-of-capacitance-c%e2%82%81-is-made-using-two-gold-pl\/","url":"https:\/\/exam.pscnotes.com\/mcq\/a-parallel-plate-capacitor-of-capacitance-c%e2%82%81-is-made-using-two-gold-pl\/","name":"A parallel-plate capacitor of capacitance C\u2081 is made using two gold pl","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T02:43:20+00:00","dateModified":"2025-06-01T02:43:20+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The capacitance of a parallel-plate capacitor is given by the formula C = \u03b5 * (A\/d), where \u03b5 is the permittivity of the dielectric material between the plates, A is the area of one plate, and d is the distance between the plates. - The problem states that both capacitors have the same plate separation (d) and the four plates are of the same area (meaning the plates for C\u2081 have area A, and the plates for C\u2082 also have area A). - The plates are made of gold and aluminium. 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