{"id":84632,"date":"2025-06-01T02:42:09","date_gmt":"2025-06-01T02:42:09","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=84632"},"modified":"2025-06-01T02:42:09","modified_gmt":"2025-06-01T02:42:09","slug":"a-parallel-plate-capacitor-with-air-in-between-the-plates-has-capaci","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/a-parallel-plate-capacitor-with-air-in-between-the-plates-has-capaci\/","title":{"rendered":"A parallel-plate capacitor, with air in between the plates, has capaci"},"content":{"rendered":"

A parallel-plate capacitor, with air in between the plates, has capacitance C. Now the space between the two plates of the capacitor is filled with a dielectric of dielectric constant 7. Then the value of the capacitance will become<\/p>\n

[amp_mcq option1=”C” option2=”C\/7″ option3=”7C” option4=”14C” correct=”option3″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC CDS-1 – 2017<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe correct answer is C) 7C.
\n<\/section>\n
\nThe capacitance of a parallel-plate capacitor is given by C = \u03b5 * A \/ d, where \u03b5 is the permittivity of the material between the plates, A is the area of the plates, and d is the distance between them. When there is air (or vacuum) between the plates, the permittivity is approximately \u03b5\u2080, and the capacitance is C = \u03b5\u2080 * A \/ d. When the space is filled with a dielectric material of dielectric constant \u03ba, the permittivity changes to \u03b5 = \u03ba * \u03b5\u2080. Therefore, the new capacitance C’ becomes C’ = (\u03ba * \u03b5\u2080) * A \/ d = \u03ba * (\u03b5\u2080 * A \/ d). Given that the dielectric constant \u03ba = 7, the new capacitance is C’ = 7 * C.
\n<\/section>\n
\nIntroducing a dielectric material between the plates of a capacitor increases the electric field strength between the plates for the same voltage, or reduces the voltage across the plates for the same charge. This results in the capacitor being able to store more charge at the same voltage, effectively increasing its capacitance.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

A parallel-plate capacitor, with air in between the plates, has capacitance C. Now the space between the two plates of the capacitor is filled with a dielectric of dielectric constant 7. Then the value of the capacitance will become [amp_mcq option1=”C” option2=”C\/7″ option3=”7C” option4=”14C” correct=”option3″] This question was previously asked in UPSC CDS-1 – 2017 … <\/p>\n

Detailed SolutionA parallel-plate capacitor, with air in between the plates, has capaci<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1087],"tags":[1101,1160,1128],"class_list":["post-84632","post","type-post","status-publish","format-standard","hentry","category-upsc-cds-1","tag-1101","tag-physical-properties-of-materials","tag-physics","no-featured-image-padding"],"yoast_head":"\nA parallel-plate capacitor, with air in between the plates, has capaci<\/title>\n<meta name=\"description\" content=\"The correct answer is C) 7C. The capacitance of a parallel-plate capacitor is given by C = \u03b5 * A \/ d, where \u03b5 is the permittivity of the material between the plates, A is the area of the plates, and d is the distance between them. When there is air (or vacuum) between the plates, the permittivity is approximately \u03b5\u2080, and the capacitance is C = \u03b5\u2080 * A \/ d. When the space is filled with a dielectric material of dielectric constant \u03ba, the permittivity changes to \u03b5 = \u03ba * \u03b5\u2080. Therefore, the new capacitance C' becomes C' = (\u03ba * \u03b5\u2080) * A \/ d = \u03ba * (\u03b5\u2080 * A \/ d). Given that the dielectric constant \u03ba = 7, the new capacitance is C' = 7 * C.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/a-parallel-plate-capacitor-with-air-in-between-the-plates-has-capaci\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"A parallel-plate capacitor, with air in between the plates, has capaci\" \/>\n<meta property=\"og:description\" content=\"The correct answer is C) 7C. The capacitance of a parallel-plate capacitor is given by C = \u03b5 * A \/ d, where \u03b5 is the permittivity of the material between the plates, A is the area of the plates, and d is the distance between them. When there is air (or vacuum) between the plates, the permittivity is approximately \u03b5\u2080, and the capacitance is C = \u03b5\u2080 * A \/ d. When the space is filled with a dielectric material of dielectric constant \u03ba, the permittivity changes to \u03b5 = \u03ba * \u03b5\u2080. Therefore, the new capacitance C' becomes C' = (\u03ba * \u03b5\u2080) * A \/ d = \u03ba * (\u03b5\u2080 * A \/ d). Given that the dielectric constant \u03ba = 7, the new capacitance is C' = 7 * C.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/a-parallel-plate-capacitor-with-air-in-between-the-plates-has-capaci\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T02:42:09+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"A parallel-plate capacitor, with air in between the plates, has capaci","description":"The correct answer is C) 7C. The capacitance of a parallel-plate capacitor is given by C = \u03b5 * A \/ d, where \u03b5 is the permittivity of the material between the plates, A is the area of the plates, and d is the distance between them. When there is air (or vacuum) between the plates, the permittivity is approximately \u03b5\u2080, and the capacitance is C = \u03b5\u2080 * A \/ d. When the space is filled with a dielectric material of dielectric constant \u03ba, the permittivity changes to \u03b5 = \u03ba * \u03b5\u2080. Therefore, the new capacitance C' becomes C' = (\u03ba * \u03b5\u2080) * A \/ d = \u03ba * (\u03b5\u2080 * A \/ d). Given that the dielectric constant \u03ba = 7, the new capacitance is C' = 7 * C.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/a-parallel-plate-capacitor-with-air-in-between-the-plates-has-capaci\/","og_locale":"en_US","og_type":"article","og_title":"A parallel-plate capacitor, with air in between the plates, has capaci","og_description":"The correct answer is C) 7C. The capacitance of a parallel-plate capacitor is given by C = \u03b5 * A \/ d, where \u03b5 is the permittivity of the material between the plates, A is the area of the plates, and d is the distance between them. When there is air (or vacuum) between the plates, the permittivity is approximately \u03b5\u2080, and the capacitance is C = \u03b5\u2080 * A \/ d. When the space is filled with a dielectric material of dielectric constant \u03ba, the permittivity changes to \u03b5 = \u03ba * \u03b5\u2080. Therefore, the new capacitance C' becomes C' = (\u03ba * \u03b5\u2080) * A \/ d = \u03ba * (\u03b5\u2080 * A \/ d). Given that the dielectric constant \u03ba = 7, the new capacitance is C' = 7 * C.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/a-parallel-plate-capacitor-with-air-in-between-the-plates-has-capaci\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T02:42:09+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/a-parallel-plate-capacitor-with-air-in-between-the-plates-has-capaci\/","url":"https:\/\/exam.pscnotes.com\/mcq\/a-parallel-plate-capacitor-with-air-in-between-the-plates-has-capaci\/","name":"A parallel-plate capacitor, with air in between the plates, has capaci","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T02:42:09+00:00","dateModified":"2025-06-01T02:42:09+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The correct answer is C) 7C. The capacitance of a parallel-plate capacitor is given by C = \u03b5 * A \/ d, where \u03b5 is the permittivity of the material between the plates, A is the area of the plates, and d is the distance between them. When there is air (or vacuum) between the plates, the permittivity is approximately \u03b5\u2080, and the capacitance is C = \u03b5\u2080 * A \/ d. When the space is filled with a dielectric material of dielectric constant \u03ba, the permittivity changes to \u03b5 = \u03ba * \u03b5\u2080. Therefore, the new capacitance C' becomes C' = (\u03ba * \u03b5\u2080) * A \/ d = \u03ba * (\u03b5\u2080 * A \/ d). Given that the dielectric constant \u03ba = 7, the new capacitance is C' = 7 * C.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/a-parallel-plate-capacitor-with-air-in-between-the-plates-has-capaci\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/a-parallel-plate-capacitor-with-air-in-between-the-plates-has-capaci\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/a-parallel-plate-capacitor-with-air-in-between-the-plates-has-capaci\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC CDS-1","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-cds-1\/"},{"@type":"ListItem","position":3,"name":"A parallel-plate capacitor, with air in between the plates, has capaci"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/84632","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=84632"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/84632\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=84632"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=84632"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=84632"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}