{"id":8398,"date":"2024-04-15T02:59:58","date_gmt":"2024-04-15T02:59:58","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=8398"},"modified":"2024-04-15T02:59:58","modified_gmt":"2024-04-15T02:59:58","slug":"in-the-time-cost-optimisation-using-cpm-method-for-network-analysis-the-crashing-of-the-activities-along-the-critical-path-is-done-starting-with-the-activity-having-a-longest-duration-b-highest-co","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/in-the-time-cost-optimisation-using-cpm-method-for-network-analysis-the-crashing-of-the-activities-along-the-critical-path-is-done-starting-with-the-activity-having-a-longest-duration-b-highest-co\/","title":{"rendered":"In the time-cost optimisation, using CPM method for network analysis, the crashing of the activities along the critical path is done starting with the activity having A. Longest duration B. Highest cost slope C. Least cost slope D. Shortest duration"},"content":{"rendered":"<p>\r\n    <!-- Check if it's an AMP page -->\r\n            <!-- Non-AMP version -->\r\n        <div class=\"mcq-container\" data-quiz-id=\"quizState_6a9aa44e2411a\">\r\n                                            <div class=\"option\" data-option-key=\"option1\" data-is-correct=\"true\">\r\n                    Longest duration                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option2\" data-is-correct=\"false\">\r\n                    Highest cost slope                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option3\" data-is-correct=\"false\">\r\n                    Least cost slope                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option4\" data-is-correct=\"false\">\r\n                    Shortest duration                <\/div>\r\n                            \r\n            <!-- Feedback messages for non-AMP -->\r\n            <div class=\"feedback\" data-feedback=\"wrong\">Answer is Right!<\/div>\r\n            <div class=\"feedback\" data-feedback=\"right\">Answer is Wrong!<\/div>\r\n        <\/div>\r\n\r\n        <script>\r\n        document.addEventListener('DOMContentLoaded', function () {\r\n            var containers = document.querySelectorAll('.mcq-container');\r\n\r\n            containers.forEach(function(container) {\r\n                var options = container.querySelectorAll('.option');\r\n                var feedbackSelect = container.querySelector('[data-feedback=\"select\"]');\r\n                var feedbackWrong = container.querySelector('[data-feedback=\"wrong\"]');\r\n                var feedbackRight = container.querySelector('[data-feedback=\"right\"]');\r\n\r\n                options.forEach(function(option) {\r\n                    option.addEventListener('click', function() {\r\n                        var selectedOption = option.getAttribute('data-option-key');\r\n                        var isCorrect = option.getAttribute('data-is-correct') === 'true';\r\n\r\n                        \/\/ Remove previous selections\r\n                        options.forEach(function(opt) {\r\n                            opt.classList.remove('correct', 'incorrect');\r\n                        });\r\n\r\n                        \/\/ Add the correct\/incorrect class\r\n                        if (isCorrect) {\r\n                            option.classList.add('correct');\r\n                            feedbackRight.hidden = false;\r\n                            feedbackWrong.hidden = true;\r\n                        } else {\r\n                            option.classList.add('incorrect');\r\n                            feedbackRight.hidden = true;\r\n                            feedbackWrong.hidden = false;\r\n                        }\r\n\r\n                        \/\/ Hide select feedback\r\n                        feedbackSelect.hidden = true;\r\n                    });\r\n                });\r\n            });\r\n        });\r\n        <\/script>\r\n    \r\n    <!--more--><\/p>\n<p>The correct answer is: A. Longest duration.<\/p>\n<p>Crashing is a technique used in project management to shorten the project schedule by adding resources to activities on the critical path. The critical path is the longest path through a project network diagram, and it determines the overall project duration. By crashing activities on the critical path, the project duration can be shortened.<\/p>\n<p>The cost slope of an activity is the amount of additional cost incurred for each additional unit of time saved. The cost slope of an activity is determined by the activity&#8217;s cost and duration. Activities with a high cost slope are more <div class=\"youtube-subscribe-container\">\r\n        <a href=\"https:\/\/www.youtube.com\/channel\/UCNHT8lW-JmLC68rjBfZhdkg?sub_confirmation=1\" target=\"_blank\" class=\"youtube-subscribe-button\">\r\n            <span class=\"youtube-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 576 512\">\r\n                    <path d=\"M549.7 124.1c-6.3-23.7-24.8-42.3-48.3-48.6C458.8 64 288 64 288 64S117.2 64 74.6 75.5c-23.5 6.3-42 24.9-48.3 48.6-11.4 42.9-11.4 132.3-11.4 132.3s0 89.4 11.4 132.3c6.3 23.7 24.8 41.5 48.3 47.8C117.2 448 288 448 288 448s170.8 0 213.4-11.5c23.5-6.3 42-24.2 48.3-47.8 11.4-42.9 11.4-132.3 11.4-132.3s0-89.4-11.4-132.3zm-317.5 213.5V175.2l142.7 81.2-142.7 81.2z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Subscribe on YouTube\r\n        <\/a>\r\n    <\/div> expensive to crash than activities with a low cost slope.<\/p>\n<p>When crashing activities, it is important to start with the activities that have the longest duration and the highest cost slope. This will result in the <div class=\"telegram-channel-container\">\r\n        <a href=\"https:\/\/t.me\/pscnotes2025\" target=\"_blank\" class=\"telegram-channel-button\">\r\n            <span class=\"telegram-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 496 512\">\r\n                    <path fill=\"white\" d=\"M248,8C111,8,0,119,0,256s111,248,248,248s248-111,248-248S385,8,248,8z M362,177L320,367c-3,14-10,18-20,14l-56-41l-27,26 c-3,3-5,5-10,5l4-63L323,196c5-5-1-7-8-3l-98,62l-42-13c-9-3-10-9,2-14l162-63C351,160,365,164,362,177z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Join Our Telegram Channel\r\n        <\/a>\r\n    <\/div> greatest reduction in project duration for the least amount of additional cost.<\/p>\n<p>Here is a brief explanation of each option:<\/p>\n<ul>\n<li>Option A: Longest duration. This is the correct answer. Activities with a longer duration have a greater impact on the project schedule, so they should be crashed first.<\/li>\n<li>Option B: Highest cost slope. This is not the correct answer. Activities with a high cost slope are more expensive to crash, but they do not necessarily have a greater impact on the project schedule.<\/li>\n<li>Option C: Least cost slope. This is not the correct answer. Activities with a low cost slope are less expensive to crash, but they also have a smaller impact on the project schedule.<\/li>\n<li>Option D: Shortest duration. This is not the correct answer. Activities with a shorter duration have a smaller impact on the project schedule, so they should be crashed last.<\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>Join Our Telegram Channel Subscribe on YouTube<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[655],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>In the time-cost optimisation, using CPM method for network analysis, the crashing of the activities along the critical path is done starting with the activity having A. Longest duration B. Highest cost slope C. Least cost slope D. 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